MHT CET 2026 May 15 Shift 1 PCM Question Paper- Download PDF with Solutions

MHT CET 2026 May 15 Shift 1 PCM Question Paper is available for download here. Maharashtra State CET Cell conducted MHT CET 2026 PCM Exam on May 15 in Shift 1 from 9 AM to 12 PM in CBT mode.

The MHT CET 2026 PCM Question Paper consists of 150 multiple-choice questions (MCQs) totalling 200 marks divided into 3 sections: Physics, Chemistry, and Mathematics, with 50 questions in each subject.
Physics and Chemistry questions carry 1 mark each while Mathematics questions carry 2 marks each.
There is no negative marking for incorrect answers.

Download MHT CET 2026 May 15 Shift 1 PCM Question Paper with Solutions PDF from the links provided below.

MHT CET 2026 May 15 Shift 1 PCM Question Paper PDF Download

MHT CET 2026 May 15 Shift 1 Question Paper	Download PDF	Check Solutions

Question 1:

The rate of reaction \(A \rightarrow P\) is \(1.25 \times 10^{-2}\) mol dm\(^{-3}\) s\(^{-1}\) when \([A] = 0.5\) M. Calculate the rate constant if the reaction is second order in A.

(A) 0.05
(B) 0.04
(C) 0.03
(D) 0.01

Parameter	Details
Conducting Body	Maharashtra Common Entrance Test Cell (Maharashtra CET Cell)
Exam Mode	Online (Computer-Based Test)
Duration	180 minutes (3 hours)
Groups / Subjects	PCM (Physics, Chemistry, Mathematics) for Engineering
Total Questions	150
Total Marks	200
Question Type	Multiple Choice Questions (MCQs)
Marks Distribution	Mathematics – 2 marks/question Physics and Chemistry – 1 mark/question
Negative Marking	No
Syllabus Weightage	Class 12 – 80% Class 11 – 20%

MHT CET 2026 May 15 Shift 1 PCM Question Paper PDF Download

MHT CET PCM Exam Pattern 2026

MHT-CET 2026 Paper Analysis

MHT CET Questions

1.If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \] and \( y(0)=1 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:

2.For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \] then \[ x^2\frac{d^2y}{dx^2} \] is equal to:

3.Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]

4.Let \[ \vec a=\hat i+\hat j+\hat k \] \[ \vec b=\hat i-\hat j+2\hat k \] If a vector \( \vec c \) is coplanar with \( \vec a \) and \( \vec b \) such that \[ \vec c\cdot \vec a=1 \] and \[ \vec c\cdot \vec b=2 \] then \( \vec c \) is:

5.If \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \] and \[ y(0)=2, \] then find the value of \[ y\left(\frac{\pi}{2}\right). \]

6.The range of the function \[ y=\log(\sin x) \] where \( \sin x>0 \) is:

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1.
If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \] and \( y(0)=1 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:

2.
For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \] then \[ x^2\frac{d^2y}{dx^2} \] is equal to:

3.
Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]

4.
Let \[ \vec a=\hat i+\hat j+\hat k \] \[ \vec b=\hat i-\hat j+2\hat k \] If a vector \( \vec c \) is coplanar with \( \vec a \) and \( \vec b \) such that \[ \vec c\cdot \vec a=1 \] and \[ \vec c\cdot \vec b=2 \] then \( \vec c \) is:

5.
If \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \] and \[ y(0)=2, \] then find the value of \[ y\left(\frac{\pi}{2}\right). \]

6.
The range of the function \[ y=\log(\sin x) \] where \( \sin x>0 \) is: