Expected Percentile for MHT CET PCM May 21 2026 Shift 2 For 130 to 150 Marks

MHT CET 2026 may 21 shift 2 is expected to be moderate to tough based on the session 1 evening shift trend. Based on difficulty, MHT CET PCM May 21 Shift 2 expected percentile is around 98.6 and 99.6+ for 130 to 150 marks.

150 marks in MHT CET PCM May 21 Shift 2 is expected to have a percentile around 99.6+, making you eligible for admission to top colleges such as PICT Pune and VIT Pune for CSE programme.
Scoring 130 marks in MHT CET May 21 Shift 2 corresponds to a percentile around 98.6, which will lead to admission in SPIT Pune CS course, depending on the shift difficulty.
Candidates scoring 150 marks in the MHT CET May 21 Shift 2 paper are expected to have a rank within 7000+, making them a strong fit for top private colleges.
MHT CET expected percentile for 130- 150 marks varies shift-wise because it depends on factors such as the number of candidates appearing in a particular shift and the difficulty level.

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Expected Percentile for MHT CET PCM May 21 2026 Shift 2 For 130 to 150 Marks

Key Summary

MHT CET 2026 comprises a total of 200 marks with no negative marking for an incorrect answer.
To calculate the percentile across various shifts, MHT CET follows a normalization process to ensure fairness among candidates.
The MHT CET 2026 cutoff percentile will be published after the results are out at cetcell.mahacet.org.
MHT CET May 21 Shift 2 expected percentile for 130 to 150 marks is based on previous years' trends and session 1 afternoon shifts, which may change depending on paper difficulty and the total number of candidates appearing for the exam.

MHT CET PCM May 21, 2026 Shift 2: Expected Percentile for 130–150 Marks

The following expected percentile for 130 to 150 marks is based on session 1 and previous years' trends.

Based on difficulty level of the paper, candidates can expect 98.6 percentile for 130 marks in MHT CET PCM 21 2026 Shift 2.
With 150 marks, you can expect a MHT CET percentile around 99.6 for the May 21 2026, shift 2 paper.

Marks Range	Expected MHT CET Percentile (2026)
160- 200	99.90- 100
150- 159	99.65- 99.90
140- 149	99.10- 99.65
130- 139	98.60- 99.10
120- 129	97.70- 98.60
110- 119	96.50- 97.70
100- 109	95.00- 96.50

Note: The above percentiles are based on a difficulty level of the paper. In case the MHT CET PCM May 21, 2026 paper is easy, then the same marks range will have a lower percentile. You can check the official cutoff percentile for MHT CET 2026 at cetcell.mahacet.org after the results are out.

MHT CET PCM May 21, 2026 Shift 2: Expected Percentile for 130–150 Marks

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Ques. What is the safe score for MHT CET 2026?

Ans. A score around 130 is expected to be safe for MHT CET 2026, which corresponds to 97- 98.6 percentile. With 130 marks, you will be able to get CS/IT in private institutions and lower branches in government colleges.

Ques. What percentile is 190 marks in MHT CET?

Ans. A MHT CET percentile around 99.5 to 99.9 will correspond to 190 marks. With 99.9 percentile, you will easily get CS, the most preferred branch in tier-1 institutions.

MHT CET PCM May 21, 2026 Shift 2: Expected Rank for 130–150 Marks

The following expected rank for 130 to 150 marks is based on session 1 and previous years' trends.

Based on moderate difficulty level of the paper, candidates can expect 7000 rank for 130 marks in MHT CET PCM 21 2026 Shift 2.
With 150 marks, you can expect a MHT CET rank around 1800 for the May 21 2026, shift 2 paper.

Marks Range	Expected MHT CET Rank (2026)	Admission Chances
180+	Top 100	Top Students likely to get COEP, VJTI, SPIT
179- 160	100- 1800	Excellent score; strong chance for top branches
159- 130	1800- 7000	Very good; eligible for top government colleges
129- 100	7000- 20000	Good score; possible admission to reputed private institutes
99- 80	20000- 40000	Average and decent branches
79- 60	40000- 55000	Below-average
59- 50	55000- 70000	May secure lower-tier private colleges
Below 50	Above 70000	Unlikely to qualify for top colleges

MHT CET PCM May 21, 2026 Shift 2: Expected Rank for 130–150 Marks

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Check MHT CET 2026 Marks Vs Rank Vs Percentile: Category Wise Percentile and Rank

Ques. What is the MHT CET 2026 expected rank for 190 marks?

Ans. Scoring 190 marks is considered an excellent performance in MHT CET 2026. You will be among the top 100 ranks in MHT CET.

Ques. Can I get 99 percentile with 180 marks?

Ans. Yes, you can get 99 percentile with 180 marks in MHT CET 2026, especially in moderate or hard shifts. In the easy shift, MHT CET for 99 percentile requires a higher mark of 190.

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: College Option

Candidates scoring 130- 150 marks in MHT CET May 21 Shift 2 will fetch a percentile ranging from 98.6 to 99.6+. You will be able to get admission in a top private college based on this percentile, as per previous years' MHT CET cutoff analysis.

COEP Pune CS, IT, ETC branches will be available if you have a percentile between 98.8 and 99.5.
Candidates will be eligible for admission to the SPIT Pune ETC course if they have an MHT CET percentile of around 98.6 in the May 21, 2026, Shift 2 paper.
PICT Pune offers CS and IT branches with a requirement of around 99.3- 99.4 percentile in MHT CET.
Final admission chances depend on category, home university quota, CAP counselling round, branch demand and the overall normalization trend across all MHT CET 2026 shifts.

College Name	Expected Percentile	Branches Available
COEP Pune	98.8- 99.5+	CS, IT, ETC
VJTI Mumbai	98.2- 99.5+	CS, IT and ME
WCE Sangli	98.69+	CS and IT
PICT Pune	99.3-.99.4	CS and IT
SPIT Mumbai	98.6- 99.3+	CS, ETC
DJSCE Mumbai	97.7- 98.7	CS
MIT WPU Pune	94- 96	CS (AI and ML)
PCCOE Pune	95.5	CS
KJ Somaiya Mumbai	96.5+	CS
VIT Pune	95- 98.50	CS and CS Data Science
SPCE Mumbai	95.5+	CS

Note: The above percentiles of various colleges have been prepared from previous years' cutoff trends. These are the estimated MHT CET cutoff percentiles for open category candidates. You can check the official cutoff percentile for MHT CET 2026 at cetcell.mahacet.org after the results are out.

Related Articles:

You can check Collegedunia’s College Predictor to know your admission chances based on your MHT CET percentile for the May 21, 2026, Shift 2 paper by clicking on the link below:

MHT CET College Predictor 2026: Know Your BTech Admission Chances

Ques. Does shift difficulty in May 21 Shift 2 affect the final percentile for 130–150 marks?

Ans. Yes, MHT CET uses a normalization process where the percentile is calculated separately per shift. If May 21 Shift 2 is easier and most candidates score high, the percentile for 140 marks could drop to 97.5. If the shift is harder, then the same 140 marks could yield 99.10+ percentile.

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: Reddit Discussion

According to a Reddit post, a user asked about the good college options based on 130- 140 marks in MHT CET. In the discussion, it is suggested that CS will not be available in this marks range at COEP and VJTI, but he/she can get lower branches. In PICT and SPIT, there is a probability of getting a good branch, such as ETC, and to get admission in CS, he/she may apply to Walchand College of Engineering. A candidate must get MHT CET percentile of above 99.5 for PICT CS course.

Source: Reddit

Related Article

190 Marks in MHT CET 2026 Percentile	160 Marks in MHT CET Percentile
150 marks in MHT CET	145 Marks in MHT CET 2026 Percentile
140 Marks in MHT CET 2026 Percentile	130 Marks in MHT CET Percentile

Ques. Is 140 marks enough in MHT CET May 21 Shift 2 to get PICT Pune?

Ans. 140 marks in MHT CET May 21 shift 2 is expected to fetch a percentile around 99.1+, thus there is a low probability of getting CS. It is advised that the candidates apply to various colleges and specilizations to get admission to the colleges accepting MHT CET marks.

Ques. Can I get CS with a 98.5+ percentile based on MHT CET percentile?

Ans. Yes, you can get CS with 98.5 in low-tier private institutions such as VIT Pune, MIT WPU Pune and DJSCE Mumbai.

Expected Percentile for MHT CET PCM May 21 2026 Shift 2 For 130 to 150 Marks

Key Summary

MHT CET PCM May 21, 2026 Shift 2: Expected Percentile for 130–150 Marks

MHT CET PCM May 21, 2026 Shift 2: Expected Rank for 130–150 Marks

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: College Option

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: Reddit Discussion

MHT CET Questions

1.
A uniform solid sphere of mass $M$ and radius $R$ is placed on a smooth horizontal surface. It is struck by a horizontal cue at a height $h$ above the center. For the sphere to roll without slipping immediately after the impact, the value of $h$ must be:

2.
The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its centre and perpendicular to its length is:

3.
Let \(f(x)\) be defined by: \[ f(x)= \begin{cases} \displaystyle \int_x^6 (|t-2|+3)\,dt, & x>4 2x+8, & x\le4 \end{cases} \] Then at \(x=4\), \(f(x)\) is:

4.
If a polygon has 54 diagonals, find the number of sides of the polygon.

5.
The ratio of specific heats $C_{p}/C_{v}$ for a mixture of 1 mole of helium and 1 mole of hydrogen is:

6.
The solubility product of \(PbCl_2\) at \(298\ \text{K}\) is \(3.2 \times 10^{-5}\). What is its solubility in \(\text{mol dm}^{-3}\)?

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Key Summary

MHT CET PCM May 21, 2026 Shift 2: Expected Percentile for 130–150 Marks

MHT CET PCM May 21, 2026 Shift 2: Expected Rank for 130–150 Marks

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: College Option

MHT CET PCM May 21, 2026 Shift 2 For 130-150 Marks: Reddit Discussion

MHT CET Questions

1.A uniform solid sphere of mass $M$ and radius $R$ is placed on a smooth horizontal surface. It is struck by a horizontal cue at a height $h$ above the center. For the sphere to roll without slipping immediately after the impact, the value of $h$ must be:

2.The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its centre and perpendicular to its length is:

3.Let \(f(x)\) be defined by: \[ f(x)= \begin{cases} \displaystyle \int_x^6 (|t-2|+3)\,dt, & x>4 2x+8, & x\le4 \end{cases} \] Then at \(x=4\), \(f(x)\) is:

4.If a polygon has 54 diagonals, find the number of sides of the polygon.

5.The ratio of specific heats $C_{p}/C_{v}$ for a mixture of 1 mole of helium and 1 mole of hydrogen is:

6.The solubility product of \(PbCl_2\) at \(298\ \text{K}\) is \(3.2 \times 10^{-5}\). What is its solubility in \(\text{mol dm}^{-3}\)?

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SUBSCRIBE TO OUR NEWS LETTER

1.
A uniform solid sphere of mass $M$ and radius $R$ is placed on a smooth horizontal surface. It is struck by a horizontal cue at a height $h$ above the center. For the sphere to roll without slipping immediately after the impact, the value of $h$ must be:

2.
The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its centre and perpendicular to its length is:

3.
Let \(f(x)\) be defined by: \[ f(x)= \begin{cases} \displaystyle \int_x^6 (|t-2|+3)\,dt, & x>4 2x+8, & x\le4 \end{cases} \] Then at \(x=4\), \(f(x)\) is:

4.
If a polygon has 54 diagonals, find the number of sides of the polygon.

5.
The ratio of specific heats $C_{p}/C_{v}$ for a mixture of 1 mole of helium and 1 mole of hydrogen is:

6.
The solubility product of \(PbCl_2\) at \(298\ \text{K}\) is \(3.2 \times 10^{-5}\). What is its solubility in \(\text{mol dm}^{-3}\)?