MHT CET PYQs for Sets with Solutions: Practice MHT CET Previous Year Questions

Educational Content Expert | Updated on - Nov 26, 2025

Sets is an important topic in the Mathematics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.

This article gives you a full set of MHT CET PYQs for Sets with explanations for effective preparation. Practice of MHT CET Mathematics PYQs including Sets questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.

MHT CET PYQs for Sets with Solutions

1.
The differential equation of the family of curves $y = c_{1} e^{x} + c_{2} e^{- x}$ is:
- (A) $\frac{d^{2} y}{{d x}^{2}} + y = 0$
- (B) $\frac{d^{2} y}{{d x}^{2}} - y = 0$
- (C) $\frac{d^{3} y}{d x^{3}} + y = 0$
- (D) $\frac{d^{4} y}{{d x}^{4}} - 1 = 0$
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2.
The differential form of the equation $y^{2} + (x - b)^{2} = c$ :
- (A) $y \frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2} - 1 = 0$
- (B) $y \frac{d^{2} y}{d x^{2}} + \frac{d y}{d x} + 1 = 0$
- (C) $y \frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2} + 1 = 0$
- (D) $\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2} - 1 = 0$
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3.
General solution of $(x^{2} + y^{2}) d x - 2 x y d y = 0$ is:
- (A) $y^{2} + x^{2} = c x^{2}$
- (B) $x^{2} - y^{2} = c x$
- (C) $x^{2} = c x (x^{2} - y^{2})$
- (D) None of these
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MHT CET PYQs for Sets with Solutions: Practice MHT CET Previous Year Questions

MHT CET PYQs for Sets with Solutions

1.
The differential equation of the family of curves $y = c_{1} e^{x} + c_{2} e^{- x}$ is:

2.
The differential form of the equation $y^{2} + (x - b)^{2} = c$ :

3.
General solution of $(x^{2} + y^{2}) d x - 2 x y d y = 0$ is:

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MHT CET PYQs for Sets with Solutions

1.The differential equation of the family of curves y=c1ex+c2e−x is:

2.The differential form of the equation y2+(x−b)2=c:

3.General solution of (x2+y2)dx−2xydy=0 is:

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1.
The differential equation of the family of curves $y = c_{1} e^{x} + c_{2} e^{- x}$ is:

2.
The differential form of the equation $y^{2} + (x - b)^{2} = c$ :

3.
General solution of $(x^{2} + y^{2}) d x - 2 x y d y = 0$ is: