MHT CET PYQs for Projectile motion with Solutions: Practice MHT CET Previous Year Questions

Shivam Yadav's profile photo

Shivam Yadav

Educational Content Expert | Updated on - Nov 26, 2025

Projectile motion is an important topic in the Physics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.

This article gives you a full set of MHT CET PYQs for Projectile motion with explanations for effective preparation. Practice of MHT CET Physics PYQs including Projectile motion questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.

Also Read

MHT CET PYQs for Projectile motion with Solutions

  • 1.
    A ball is thrown vertically upward with an initial velocity of \( 20 \, \text{m/s} \). Calculate the time taken for the ball to reach its maximum height.

      • \( 2 \, \text{s} \)
      • \( 4 \, \text{s} \)
      • \( 1.5 \, \text{s} \)
      • \( 3 \, \text{s} \)

    • 2.
      An object is dropped from a helicopter flying horizontally at 360 km/h. It falls from a height of 2 km and reaches the ground in 20 seconds. What is the displacement of the package relative to the helicopter's position when it was dropped?

        • 2 km
        • \( 2\sqrt{2} \) km
        • 4 km
        • \( 8 \) km

      • 3.
        Two projectiles are projected at \( 30^\circ \) and \( 60^\circ \) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

          • \( 2 : \sqrt{3} \)
          • \( \sqrt{3} : 1 \)
          • \( 1 : 3 \)
          • \( 1 : \sqrt{3} \)

        • 4.

          A solid metallic cube having total surface area $ 24 \, \text{m}^2 $ is uniformly heated. If its temperature is increased by $ 10^\circ \, \text{C} $, calculate the increase in volume of the cube. 
          $ \text{(Given: } \alpha = 5.0 \times 10^{-4} \, \text{C}^{-1} \text{)} $

            • \( 2.4 \times 10^6 \, \text{cm}^3 \)
            • \( 1.2 \times 10^5 \, \text{cm}^3 \)
            • \( 6.0 \times 10^4 \, \text{cm}^3 \)
            • \( 4.8 \times 10^5 \, \text{cm}^3 \)

          • 5.
            The value of acceleration due to gravity at Earth's surface is \( 9.8 \, \text{m/s}^2 \). The altitude above its surface at which the acceleration due to gravity decreases to \( 4.9 \, \text{m/s}^2 \) is close to: (Radius of Earth \( R = 6.4 \times 10^6 \, \text{m} \))

              • \( 2.6 \times 10^6 \, \text{m} \)
              • \( 6.4 \times 10^6 \, \text{m} \)
              • \( 9.0 \times 10^6 \, \text{m} \)
              • \( 1.6 \times 10^6 \, \text{m} \)

            Fees Structure

            Structure based on different categories

            CategoriesState
            General800
            Women800
            sc600
            pwd600
            Others600

            In case of any inaccuracy, Notify Us! 

            Comments


            No Comments To Show