physical world is an important topic in the Physics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.
This article gives you a full set of MHT CET PYQs for physical world with explanations for effective preparation. Practice of MHT CET Physics PYQs including physical world questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.
Also Read
MHT CET PYQs for physical world with Solutions
1.
If y = tan-1 ((2 + 3x) / (3 - 2x)) + tan-1 (4x / (1 + 5x2)), thendy/dx =- \( \frac{1}{1 + 25x^2} \)
- \( \frac{5}{1 + 25x^2} \)
- \( \frac{1}{1 + 5x^2} \)
- \( \frac{5}{1 + 5x^2} \)
2.
Evaluate the definite integral: \[ \int_{0}^{\frac{\pi}{2}} \frac{dx}{1 + (\cot x)^{101}} = ? \]- \( \frac{\pi}{4} \)
- \( \frac{\pi}{2} \)
- \( \frac{1}{2} \)
- 1
3.
If \( x^y + y^x = a^b \), then \( \frac{dy}{dx} \) at \( x = 1, y = 2 \) is:- \( -1 \)
- \( 1 \)
- \( 2 \)
- \( \frac{1}{2} \)
4.
For all real x, the minimum value of the function f(x) = (1 - x + x^2) / (1 + x + x^2) is:- \( \frac{1}{3} \)
- \( 0 \)
- \( 3 \)
- \( 1 \)
5.
If a(4 + x^2) = x + y - x^3 = a^3 * (dy/dx) at x = 1, then the value of (dy/dx) is:- 5
- 4
- 3
- 2
6.
The particular solution of the differential equation, \[ x y \frac{dy}{dx} = x^2 + 2y^2 \quad \text{when} \quad y(1) = 0 \quad \text{is:} \]- \( \frac{x^2 + y^2}{x^3} = 1 \)
- \( x^2 + y^2 = x \)
\( x^2 + 2y^2 = x^4 \)
\( x^2 + y^2 = x^4 \)
7.
Evaluate the integral: ∫ log((2 + x)2 + x) dx- \( (2 + x)^{2 + x} + C \)
- \( (2 + x) \log((2 + x)^{2 + x}) + C \)
- \( (2 + x) \cdot (2 + x)^{x} + C \)
- \( (2 + x)(2 + x)^{x} (\log(2 + x) + 1) + C \)
8.
The area enclosed between the parabola \( y^2 = 4x \) and the line \( y = 2x - 4 \) is:- \( \frac{17}{3} \) sq. units
- 15 sq. units
- \( \frac{19}{3} \) sq. units
- 9 sq. units
Comments