Moment Of Inertia is an important topic in the Physics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.
This article gives you a full set of MHT CET PYQs for Moment Of Inertia with explanations for effective preparation. Practice of MHT CET Physics PYQs including Moment Of Inertia questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.
Also Read
MHT CET PYQs for Moment Of Inertia with Solutions
1.
What is the moment of inertia of a solid sphere of mass \( M \) and radius \( R \) about its diameter?- \( \frac{2}{5} M R^2 \)
- \( \frac{1}{2} M R^2 \)
- \( \frac{3}{5} M R^2 \)
- \( M R^2 \)
2.
A thin circular disc of mass \( M \) and radius \( R \) is rotating in a horizontal plane about an axis passing through its center and perpendicular to its plane with angular velocity \( \omega \). If another disc of the same dimensions but of mass \( M/2 \) is placed gently on the first disc co-axially, then the new angular velocity of the system is:- \( \frac{4}{5} \omega \)
- \( \frac{5}{4} \omega \)
- \( \frac{2}{3} \omega \)
- \( \frac{3}{2} \omega \)
3.
A solid cylinder and a hollow cylinder, each of mass \( M \) and radius \( R \), are rotating with the same angular velocity \( \omega \). What is the ratio of their rotational kinetic energies \( \left( \frac{K_{\text{hollow}}}{K_{\text{solid}}} \right) \)?- 1
- 2
- 3
- 3/2
4.
The moment of inertia of a uniform circular disc of radius $ R $ and mass $ M $ about an axis touching the disc at its diameter and normal to the disc is- $ MR^2 $
- $ \frac{2}{5}MR^2 $
- $ \frac{3}{2}MR^2 $
- $ \frac{1}{2}MR^2 $
5.
For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through \( O \) (the center of mass) and \( O' \) (corner point) is:
- \( \frac{2}{3} \)
- \( \frac{1}{4} \)
- \( \frac{1}{8} \)
- \( \frac{1}{2} \)
6.
A disc of moment of inertia $'I_1'$ is rotating in horizontal plane about an axis passing through a centre and perpendicular to its plane w ith constant angular speed $?\omega_1'$. Another disc of moment of inertia $?I_2? $ having zero angular speed is placed coaxially on a rotating disc. Now both the. discs are rotating with constant angular speed $?\Omega_2 ?$. The energy lost by the initial rotating disc is- $\frac{1}{2} \left[ \frac{I_1 + I_2}{I_1 I_2 } \right] \omega_1^2$
- $\frac{1}{2} \left[ \frac{I_1 I_2 }{I_1 - I_2} \right] \omega_1^2$
- $\frac{1}{2} \left[ \frac{I_1 - I_2}{I_1 I_2 } \right] \omega_1^2$
- $\frac{1}{2} \left[ \frac{I_1 I_2 }{I_1 + I_2} \right] \omega_1^2$
Comments