MHT CET PYQs for Matrices with Solutions: Practice MHT CET Previous Year Questions

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Shivam Yadav

Educational Content Expert | Updated on - Nov 26, 2025

Matrices is an important topic in the Mathematics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.

This article gives you a full set of MHT CET PYQs for Matrices with explanations for effective preparation. Practice of MHT CET Mathematics PYQs including Matrices questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.

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MHT CET PYQs for Matrices with Solutions

  • 1.
    Let the foot of the perpendicular from the point \( (1, 2, 4) \) on the line \( \frac{x+2}{4} = \frac{y-1}{2} = \frac{z+1}{3} \) be \( P \). Then the distance of \( P \) from the plane \( 3x + 4y + 12z + 23 = 0 \) is:

      • \( 5 \)
      • \( \frac{50}{13} \)
      • \( 4 \)
      • \( \frac{63}{13} \)

    • 2.

      If \(\begin{bmatrix} 2 & 1 \\ 3 & 2\end{bmatrix}\) A \(\begin{bmatrix} -3 & 2 \\ 5 & -3\end{bmatrix}\) =\(\begin{bmatrix} 1 & 0 \\ 0 & 1\end{bmatrix}\), then A =?

        • \(\begin{bmatrix} 1 & 1 \\ 0 & 1\end{bmatrix}\)

        • \(\begin{bmatrix} 1 & 0 \\ 1 & 1\end{bmatrix}\)

        • \(\begin{bmatrix} 1 & 1 \\ 1 & 1\end{bmatrix}\)

        • \(\begin{bmatrix} 1 & 1 \\ 1 & 0\end{bmatrix}\)


      • 3.

        If matrix A =\(\begin{bmatrix} 1 & 2 \\ 4 & 3 \end{bmatrix}\) is such that AX = I, where I is 2 x 2 unit matrix, then X =

          • \(\frac {1}{5}\)\(\begin{bmatrix} 3 & 2 \\ 4 & 1 \end{bmatrix}\)

          • \(\frac {1}{5}\)\(\begin{bmatrix} 3 & -2 \\ -4 & 1 \end{bmatrix}\)

          • \(\frac {1}{5}\)\(\begin{bmatrix} -3 & -2 \\ 4 & 1 \end{bmatrix}\)

          • \(\frac {1}{5}\)\(\begin{bmatrix} -3 & 2 \\ 4 & -1 \end{bmatrix}\)


        • 4.
          A spherical iron ball \( 10 \, \text{cm} \) in radius is coated with a layer of ice of uniform thickness that melts at a rate of \( 50 \, \text{cm}^3/\text{min} \). When the thickness of ice is \( 15 \, \text{cm} \), then the rate at which the thickness of ice decreases is:

            • \( \frac{5}{6\pi} \, \text{cm/min} \)
            • \( \frac{1}{54\pi} \, \text{cm/min} \)
            • \( \frac{1}{18\pi} \, \text{cm/min} \)
            • \( \frac{1}{36\pi} \, \text{cm/min} \)

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