introduction to organic chemistry is an important topic in the Chemistry section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.
This article gives you a full set of MHT CET PYQs for introduction to organic chemistry with explanations for effective preparation. Practice of MHT CET Chemistry PYQs including introduction to organic chemistry questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.
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MHT CET PYQs for introduction to organic chemistry with Solutions
1.
Which of the following is Clemmensen reduction?- Reduction of aldehydes/ketones to alkanes using zinc amalgam and HCl
- Oxidation of alcohols to aldehydes/ketones
- Reduction of nitro compounds to amines using Sn and HCl
- Reduction of carboxylic acids to aldehydes using LiAlH\(_4\)
2.
Which element shows the lower oxidation state in the 3d series?- Scandium (Sc)
- Titanium (Ti)
- Zinc (Zn)
- None of the above
3.
Find the total volume of a unit cell given the radius of the atom.- \( 8r^3 \)
- \( \frac{64r^3}{3\sqrt{3}} \)
- \( \frac{32r^3}{\sqrt{2}} \)
- \( \frac{16r^3}{\sqrt{3}} \)
4.
Which of the following represents the correct IUPAC name for \( \text{CH}_3\text{CH}_2\text{OH} \)?- Methanol
- Ethanol
- Propanol
- Butanol
5.
What is the concentration of \( \text{H}^+ \) ions if the pH is 2.7?- \( 2.00 \times 10^{-3} \, \text{M} \)
- \( 1.99 \times 10^{-3} \, \text{M} \)
- \( 1.80 \times 10^{-3} \, \text{M} \)
- None of the above
6.
Which of the following represents the correct IUPAC name for \( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)?- Methanol
- Ethanol
- Propanol
- Butanol
7.
Which of the following represents the Stephan Reaction?- \( C_6H_5CH_2Cl \xrightarrow{NaOH} C_6H_5CH_2OH \)
- \( C_6H_5Cl \xrightarrow{NaOH} C_6H_5OH \)
- \( C_6H_5Cl \xrightarrow{AlCl_3} C_6H_5CH_3 \)
- \( C_6H_5CH_3 \xrightarrow{NaOCl} C_6H_5Cl \)
8.
Calculate the pH of the solution using the Henderson-Hasselbalch equation.- \( \text{pH} = \text{p}K_a + \log \left( \frac{\text{[acid]}}{\text{[salt]}} \right) \)
- \( \text{pH} = \text{p}K_a - \log \left( \frac{\text{[salt]}}{\text{[acid]}} \right) \)
- \( \text{pH} = \text{p}K_a + \log \left( \frac{\text{[salt]}}{\text{[acid]}} \right) \)
- None of the above
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