Gravitation is an important topic in the Physics section in MHT CET exam. Practising this topic will increase your score overall and make your conceptual grip on MHT CET exam stronger.
This article gives you a full set of MHT CET PYQs for Gravitation with explanations for effective preparation. Practice of MHT CET Physics PYQs including Gravitation questions regularly will improve accuracy, speed, and confidence in the MHT CET 2026 exam.
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MHT CET PYQs for Gravitation with Solutions
1.
A satellite of mass ‘m’ is revolving around the earth of mass ‘M’ in an orbit of radius ‘r’. The angular momentum of the satellite about the centre of orbit will be
\(\sqrt {GMmr}\)
\(\sqrt {GMm^2r}\)
\(\sqrt {mvr}\)
\(\sqrt {GMm}\)
2.
The gravitational potential energy of a 2 kg object at a height of 5 m above the surface of the Earth is?- 100 J
- 150 J
- 50 J
- 25 J
3.
At a height \( h \) above the Earth's surface, the acceleration due to gravity becomes \( \frac{g}{\sqrt{3}} \). What is the value of \( h \) in terms of the Earth's radius \( R \)?- \( R \)
- \( \sqrt{2}R \)
- \( 2R \)
- \( \frac{R}{2} \)
4.
The height from Earth's surface at which acceleration due to gravity becomes \(\frac{g}{4}\) is \(\_\_\)? (Where \(g\) is the acceleration due to gravity on the surface of the Earth and \(R\) is the radius of the Earth.)
- \(\sqrt{2}R\).
- \(R\).
- \(\frac{R}{\sqrt{2}}\).
- \(2R\).
5.
In a satellite, if the time of revolution is $ T $ , then $ KE $ is proportional to- $ \frac{1}{T} $
- $ \frac{1}{T^2} $
- $ \frac{1}{T^3} $
- $ T^{-2/3} $
6.
The gravitational potential energy of an object of mass 5 kg at a height of 10 m above the surface of the Earth is:- \( 490 \, \text{J} \)
- \( 500 \, \text{J} \)
- \( 450 \, \text{J} \)
- \( 550 \, \text{J} \)
7.
Two satellites A and B rotate round a planet’s orbit having radius 4R and R respectively. If the speed of satellite A is 3 V then speed of satellite B is
\(\frac {3V}{2}\)
6V
\(\frac {4V}{2}\)
12 V
8.
A body of mass $ 1.5 \, \text{kg} $ is dropped from a height of $ 20 \, \text{m} $. What is its speed just before hitting the ground? (Assume $ g = 9.8 \, \text{m/s}^2 $)- \( 19.8 \, \text{m/s} \)
- \( 14 \, \text{m/s} \)
- \( 20 \, \text{m/s} \)
- \( 9.8 \, \text{m/s} \)
9.
If $W_1$, $W_2$ and $W_3$ represent the work done in moving a particle from $A$ to $B$ along three different paths $1$, $2$ and $3$ (as shown in fig) in the gravitational field of the point mass $'m'$. Find the correct relation between $'W'_1$, $'W_2'$ and $'W_3'$- $W_1 < W_3 < W_2$
- $W_1 < W_2 < W_3$
- $W_1 = W_2 = W_3$
- $W_1 > W_3 > W_2$
10.
What is the gravitational force between two objects of masses \( m_1 = 10 \, \text{kg} \) and \( m_2 = 20 \, \text{kg} \), separated by a distance of \( r = 5 \, \text{m} \)? (Gravitational constant \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \))\( 5.33 \times 10^{-10} \, \text{N} \)
- \( 2.67 \times 10^{-9} \, \text{N} \)
- \( 4.67 \times 10^{-9} \, \text{N} \)
\( 1.33 \times 10^{-9} \, \text{N} \)
11.
The value of \( g \) at height \( h \) above Earth's surface is \( \frac{g}{\sqrt{3}} \). Find \( h \) in terms of the radius of the Earth.- \( R \)
- \( 2R \)
- \( R\sqrt{3} \)
- \( \frac{R}{\sqrt{3}} \)
12.
Two identical particles each of mass \( m \) go around a circle of radius \( a \) under the action of their mutual gravitational attraction. The angular speed of each particle will be:- \( \sqrt{\frac{Gm}{2a^3}} \)
- \( \sqrt{\frac{Gm}{8a^3}} \)
- \( \sqrt{\frac{Gm}{4a^3}} \)
- \( \sqrt{\frac{Gm}{a^3}} \)
13.
If $ g $ is the acceleration due to gravity on earth?s surface, the gain of the potential energy of an object of mass $ m $ raised from the surface of the earth to a height equal to the radius $ R $ of the earth is- $ 2mgR $
- $ mgR $
- $ \frac{1}{2}\,mgR $
- $ \frac{1}{4}\,mgR $
14.
"The height from Earth's surface at which acceleration due to gravity becomes \( g/4 \), where \( g \) is acceleration due to gravity on the surface of Earth and \( R \) is the radius of Earth?"- \( \sqrt{2}R \).
- \( R \).
- \( R/\sqrt{2} \).
- \( 2R \).
15.
A satellite is orbiting the Earth at a height of \( 10^4 \, \text{km} \) above the Earth's surface. If the radius of the Earth is \( 6.4 \times 10^6 \, \text{m} \), calculate the orbital speed of the satellite. (Gravitational constant \( G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \) and Earth's mass \( M = 6 \times 10^{24} \, \text{kg} \))- \( 7.0 \, \text{km/s} \)
- \( 8.0 \, \text{km/s} \)
- \( 9.0 \, \text{km/s} \)
- \( 10.0 \, \text{km/s} \)
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