The MHT CET 2025 question paper for April 20 Shift 2 (PCM group) is available here for download. The MHT CET 2025 question paper consists of 150 multiple-choice questions (MCQs) totaling 200 marks divided in 3 sections, Physics, Chemistry and Mathematics and 50 questions in each subject.
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MHT CET 2025 20 April Shift 2 PCM Question Paper PDF Download
| MHT CET 2025 PCM Question Paper With Answer Key | Download | Check Solution |

Which of the following gases is most soluble in water?
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Which of the following elements does not have a completely filled outermost shell in its ground state?
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Which of the following is an example of a redox reaction?
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In the reaction \( \mathrm{2H_2 + O_2 \rightarrow 2H_2O} \), if 4 moles of hydrogen react completely with oxygen, how many moles of water will be produced?
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What is the volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P.?
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Evaluate the integral: \( \int \sin^5 x \, dx \)
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Evaluate the determinant of the matrix: \[ \left| \begin{array}{cc} 1 & \tan x
-\tan x & 1 \end{array} \right| \]
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Evaluate the expression: \[ f\left(f(f(x))\right) + \left(f(f(x))\right)^2 \quad if \quad x = 1 \]
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A copper ball at \(80^\circ C\) is brought to \(60^\circ C\) in 5 minutes, with surrounding temperature at \(20^\circ C\). Find the temperature of the ball after 20 minutes.
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Given \( f'(1) = 3 \), \( f(1) = 1 \), and
\[ y = f\left(f(f(x))\right) + \left(f(x)\right)^2, \]
then find \( \frac{dy}{dx} \) at \( x = 1 \).
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If \( y = x^x + x^x \), then find \( \frac{dy}{dx} \):
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Evaluate the definite integral: \( \int_{-2}^{2} |x^2 - x - 2| \, dx \)
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Find the value of the integral: \( \int \frac{2x + 3}{(xy)(x^2 + 1)} \, dx \)
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If \( \int \frac{2x + 3}{(x - 1)(x^2 + 1)} \, dx = \log_x \{(x - 1)^{\frac{5}{2}}(x^2 + 1)^a\} - \frac{1}{2} \tan^{-1}x + C \), then the value of \( a \) is:
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Expected Minimum Qualifying Marks for MHT CET 2025
The Maharashtra Common Entrance Test (MHT CET) 2025 is an important test for students who want to participate in undergraduate programs like engineering and pharmacy in Maharashtra. The cut-off marks will be published after the exam by the officials. However, based on past years' data and current analysis, we can provide expected minimum cut-off marks:
| Category | Expected Minimum Marks (Out of 200) |
| General (Open Category) | 145–160 |
| Other Backward Classes (OBC) | 135–145 |
| Scheduled Castes (SC) | 120–135 |
| Scheduled Tribes (ST) | 110–125 |
| Economically Weaker Section (EWS) | 145–155 |
| Persons with Disabilities (PWD) | 95–110 |
According to previous year data, in MHT CET 2024 it was found that out of 675,377 candidates, only 37 scored 100 percentile from which 34 were from PCM and 3 were from PCB. This indicates that just 0.009% of PCM candidates, 0.001% of PCB candidates, and 0.005% overall, were focussed and achieved a perfect score.
MHT-CET 2025 Topper’s Strategy: Scoring 90 Percentile
What is a good percentile and rank in MHT CET 2025?
The results of the MHT CET 2025 exam are important for getting admissions in engineering and pharmacy programs in Maharashtra. Your performance on the exam is not only dependent on your marks but also on your percentile and rank. Usually, the more marks you obtain the higher your percentile and rank will be, thus allowing you to maximize your chances of gaining admission into better colleges. The table below outlines a range of expected marks, percentile, and rank in order to sense what "good" means on the exam.
| Marks (Out of 200) | Percentile Range | Expected Rank Range |
| 160+ | Above 99.50 | 1 - 900 |
| 150 - 160 | Above 99.00 | 900 - 1800 |
| 140 - 150 | 98.00 - 99.00 | 1800 - 2700 |
| 110 - 140 | 96.00 - 98.00 | 3000 - 7900 |
| 100 - 110 | 95.00 - 96.00 | 7900 - 10990 |
| 96 - 100 | 92.00 - 94.00 | 10990 - 14500 |
| 81 - 95 | 85.00 - 91.00 | 14500 - 19500 |
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