NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5 Laws of Motion are provided in the article below. The branch of physics where we study the motion of a body by considering the cause which is the force which generates the motion is called Dynamics. Newton’s three laws of motion make us understand how objects act when standing still, while moving or when forces behave upon them.

Class 11 Physics Chapter 5 Laws of Motion belongs to Unit 3 which has a weightage of 23 marks along with Unit 2 Kinematics and Unit 3. The Class 11 Physics Chapter 5 NCERT Solutions deals with the concepts of force and Laws of Motion, Non-contact force, Inertia and Mass.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 5

NCERT Solutions for Class 11 Physics Chapter 5

NCERT Solutions

Class 11 Physics Chapter 5 – Concepts Covered

Newton’s First Law of Motion is referred to as the “Law of Inertia”. The law defines inertia, an inertial frame of reference, and force.

A body will remain at rest or continue to be in motion with a uniform velocity unless an external force is applied to it.

Newton’s Second Law of Motion: When an external force is applied to a body with constant mass, the force produces an acceleration. The acceleration that is produced is directly proportional to the force and then inversely proportional to the mass of the body.

\(\overrightarrow {F} = K {dP \over dt} = Km \overrightarrow a\)

Newton’s Third Law of Motion: To every action, there is an equal and opposite reaction force.

When body A exerts a force on some other body B, then B exerts an equal and opposite force on A.

Linear momentum of a body is the product of the mass and velocity of the body.

Linear Momentum = mass x velocity

Impulse is the product of force and the small-time interval for which the force acts.

\(Impulse= \int Fdt\)

Class 11 Physics Chapter 5 Related Guides –

Banking of Roads	Types of Friction	Rolling Friction
Sliding Friction	Pseudo Force	Tension Force
Kinetic Friction	Motion in Physics	Derivation of Centripetal Acceleration
Coefficient of Static Friction	Aristotle Fallacy	Static Friction
Impending Motion	Interaction of Forces	Difference between momentum and inertia

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Class 11 Physics Notes	Relation between articles in Physics
Difference between in Physics	Physics Study Notes	SI Units in Physics
Derivations in Physics	Physics Constants	Physics Formula

CBSE CLASS XII Related Questions

1.
In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

View Solution

2.
The figure represents the variation of the electric potential \( V \) at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at:

View Solution

3.
Assertion : Photoelectric effect is a spontaneous phenomenon. Reason (R): According to the wave picture of radiation, an electron would take hours/days to absorb sufficient energy to overcome the work function and come out from a metal surface.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Both Assertion (A) and Reason (R) are false.

View Solution

4.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

\( 0.5 \times 10^3 \, \text{m}^{-1} \)
\( 6.0 \times 10^2 \, \text{m}^{-1} \)
\( 7.5 \times 10^2 \, \text{m}^{-1} \)
\( 1.5 \times 10^3 \, \text{m}^{-1} \)

View Solution

5.
A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
the magnetic dipole moment of the coil, and
the magnitude of the counter torque that must be applied to prevent the coil from turning.

View Solution

6.
The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

\( \dfrac{3h}{2\pi} \)
\( \dfrac{2h}{\pi} \)
\( \dfrac{h}{\pi} \)
\( \dfrac{h}{2\pi} \)

View Solution

NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5

Class 11 Physics Chapter 5 – Concepts Covered

CBSE CLASS XII Related Questions

1.
In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

2.
The figure represents the variation of the electric potential \( V \) at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at:

3.
Assertion : Photoelectric effect is a spontaneous phenomenon. Reason (R): According to the wave picture of radiation, an electron would take hours/days to absorb sufficient energy to overcome the work function and come out from a metal surface.

4.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

6.
The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

Similar Physics Concepts

Comments

dOGVmW

NCERT Solutions For Class 11 Physics Chapter 5: Laws of Motion

NCERT Solutions for Class 11 Physics Chapter 5

Class 11 Physics Chapter 5 – Concepts Covered

CBSE CLASS XII Related Questions

1.In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

2.The figure represents the variation of the electric potential \( V \) at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at:

3.Assertion : Photoelectric effect is a spontaneous phenomenon. Reason (R): According to the wave picture of radiation, an electron would take hours/days to absorb sufficient energy to overcome the work function and come out from a metal surface.

4.The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

6.The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

Similar Physics Concepts

Comments

dOGVmW

1.
In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

2.
The figure represents the variation of the electric potential \( V \) at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at:

3.
Assertion : Photoelectric effect is a spontaneous phenomenon. Reason (R): According to the wave picture of radiation, an electron would take hours/days to absorb sufficient energy to overcome the work function and come out from a metal surface.

4.
The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

6.
The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be: