NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.4

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.4 Solutions are based on representation of cumulative frequency distribution in graphs as a Cumulative Frequency Curve.

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Check out NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.4 Solutions

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

Also check other Exercise Solutions of Class 10 Maths Chapter 14 Statistics

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Chapter Related Topics
Mean of Grouped Data	Statistics Important Question	Statistics Revision Notes
Mean Formula	Confidence Interval	Confidence Interval Formula
Step Deviation Method	Differences between Correlation and Regression	Mode of Grouped Data
Median	Class Mark	Statistics for Class 10

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CBSE X Related Questions

1.
Using prime factorisation, find the HCF of 144, 180 and 192.
View Solution
2.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.
View Solution
3.
If the sum of first n terms of an A.P. is given by $ S_n = \frac{n}{2}(3n+1) $, then the first term of the A.P. is
- 2
- $ \frac{3}{2} $
- 4
- $ \frac{5}{2} $
View Solution
4.
If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are
- 12 and 13
- 13 and 12
- 10 and 15
- 15 and 10
View Solution
5.
Find 'mean' and 'mode' of the following data : Frequency Distribution Table
Class 0 – 15 15 – 30 30 – 45 45 – 60 60 – 75 75 – 90
Frequency 11 8 15 7 10 9
View Solution
6.
There is a circular park of diameter 65 m as shown in the following figure, where AB is a diameter. An entry gate is to be constructed at a point P on the boundary of the park such that distance of P from A is 35 m more than the distance of P from B. Find distance of point P from A and B respectively.
View Solution

Class	0 – 15	15 – 30	30 – 45	45 – 60	60 – 75	75 – 90
Frequency	11	8	15	7	10	9

View All

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.4

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

CBSE X Related Questions

1.
Using prime factorisation, find the HCF of 144, 180 and 192.

2.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

3.
If the sum of first n terms of an A.P. is given by \( S_n = \frac{n}{2}(3n+1) \), then the first term of the A.P. is

4.
If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

5.
Find 'mean' and 'mode' of the following data : Frequency Distribution Table
Class 0 – 15 15 – 30 30 – 45 45 – 60 60 – 75 75 – 90
Frequency 11 8 15 7 10 9

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.4

Exercise Solutions of Class 10 Maths Chapter 14 Statistics

CBSE X Related Questions

1.Using prime factorisation, find the HCF of 144, 180 and 192.

2.In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

3.If the sum of first n terms of an A.P. is given by \( S_n = \frac{n}{2}(3n+1) \), then the first term of the A.P. is

4.If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

5.Find 'mean' and 'mode' of the following data : Frequency Distribution Table Class0 – 1515 – 3030 – 4545 – 6060 – 7575 – 90Frequency118157109

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Using prime factorisation, find the HCF of 144, 180 and 192.

2.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

3.
If the sum of first n terms of an A.P. is given by \( S_n = \frac{n}{2}(3n+1) \), then the first term of the A.P. is

4.
If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

5.
Find 'mean' and 'mode' of the following data : Frequency Distribution Table
Class 0 – 15 15 – 30 30 – 45 45 – 60 60 – 75 75 – 90
Frequency 11 8 15 7 10 9