NCERT Solutions for class 10 Maths Chapter 3: Pair Of Linear Equations In Two Variables

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Strategy Lead

NCERT Solutions for Class 10 Maths Chapter 3: Pair of Linear Equations in Two Variables are provided in this article. A pair of linear equations in two variables having a solution is known as a consistent pair of linear equations. Equivalent pair of linear equations has infinitely many distinct common solutions, such a pair of solutions is known as a dependent pair of linear equations in two variables.

Class 10 Maths Chapter 3 Linear Equations in Two Variables belongs to Unit 2 Algebra which has a weightage of 20 marks in the CBSE Class 10 Maths Examination. The NCERT solutions of the chapter include questions related to the Substitution method, Elimination method, and Cross-multiplication method.

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 3


NCERT Solutions for Class 10 Mathematics Chapter 3

NCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT Solutions


Important Topics in Class 10 Maths Chapter 3

  • Linear Equations are the equations in which the powers of all the involved variables are one. 
The general form of a linear equation in two variables is ax + by + c = 0, where a and b cannot be simultaneously zero.
  • The solution of a linear equation in two variables is generally a pair of values, one for x and the other for y, which makes the two sides of the equation equal.

For example: If 3x + y = 6, then (0,6) is one of its solutions as it satisfies the equation. 

Linear Equation in 2 variables graph

  • A pair of linear equations in two variables can be represented as shown below – 

\(a_1x + b_1y+c_1=0\\ a_2x + b_2y+c_2=0\)

  • The solution for a consistent pair of linear equations can be found using various methods.

i) Elimination method

ii) Substitution Method 

iii) Cross-multiplication of solving linear equations

iv) Graphical method


NCERT Solutions For Class 10 Maths Chapter 3 Exercises:

The detailed solutions for all the NCERT Solutions for Pair of Linear Equations in Two Variables under different exercises are as follows:


Related Topics:

CBSE Class 10 Mathematics Study Guides:

CBSE X Related Questions

  • 1.
    The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

      • 0
      • 1
      • 3
      • 2

    • 2.
      In the given figure, PQ is a tangent to a circle with centre \(O(-5, 3)\). If coordinates of P and Q are \((3, 1)\) and \((0, 6)\) respectively, then using distance formula, show that \(PQ \perp OQ\).


        • 3.
          Seema daily goes to a park to exercise on machines available there. When Seema spent 15 minutes on exercise bicycle and 30 minutes on double cross walker, she received a message of burning 435 calories on her fitness watch. When she spent 30 minutes on exercise bicycle and 40 minutes on double cross walker, she received a message of burning 690 calories. Based on above information, answer the following questions:

          38(i) Represent the above situation in terms of a pair of linear equations in two variables.


            • 4.
              In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle. Based on above information, answer the following questions:

              37(i) Find \(m\angle AOP\).


                • 5.
                  Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).


                    • 6.
                      In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).

                        Comments


                        No Comments To Show