COMEDK UGET 2019 Question Paper (Available): Download Question Paper with Answer Key PDF

COMEDK UGET 2019 Question Paper PDF is available for download. The question paper carries a weightage of 180 marks. Candidates are required to answer 180 questions in a duration of 180 minutes. Candidates appearing for COMEDK UGET exam can download and practice question papers for a better understanding of the exam.

COMEDK UGET 2019 Question Paper with Answer Key PDF

Paper/Subject Exam Date Question Papers
Physics May 12, 2019 Check Here
Mathematics May 12, 2019 Check Here

*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.

COMEDK UGET 2019 Questions

  • 1.
    The magnetic flux linked with a coil is given by the equation: $ \phi = 8t^2 + t + 10 $ The e.m.f. induced in the coil in the 3rd second will be

      • 49 V
      • 33 V
      • 16 V
      • 20 V

    • 2.
      The resistance of a 10 m long wire is 10 $ \Omega $. Its length is increased by 25\% by stretching the wire uniformly. The new resistance is

        • 18.6 \( \Omega \)
        • 15.6 \( \Omega \)
        • 12.8 \( \Omega \)
        • 14.9 \( \Omega \)

      • 3.
        A voltmeter of resistance $1000 \, \Omega $ and $0.5 \, \text{V/div} $ is to be converted into a voltmeter to make it read $1 \, \text{V/div} $. The value of high resistance to be connected in series with it is

          • 6000 \( \Omega \)
          • 5000 \( \Omega \)
          • 4000 \( \Omega \)
          • 1000 \( \Omega \)

        • 4.
          A scooter moves with a speed of 7 m/s on a straight road and is stopped by applying the brakes. Before stopping, the scooter travels 10 m. If the weight of the scooter is W, then the total resistance to the motion of the scooter will be

            • \(\frac{1}{2} W\)
            • \(\frac{1}{4} W\)
            • 4W
            • 2W

          • 5.
            A satellite is revolving around the earth in a circular orbit with kinetic energy of $1.69 \times 10^{10}$ J. The additional kinetic energy required for just escaping into the outer space is

              • \( 3.38 \times 10^{10} \, \text{J} \)
              • \( 1.69 \times 10^{10} \, \text{J} \)
              • \( 0.89 \times 10^{10} \, \text{J} \)
              • \( 1.35 \times 10^{10} \, \text{J} \)

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