Coordinates Exercise 1.1 Class 9 Maths NCERT Solutions

The Coordinates Exercise 1.1 solutions cover the opening exercise of the new Ganita Manjari book. This is the first practice set of Chapter 1. These NCERT Solutions Class 9 Maths Chapter 1 Coordinates Exercise 1.1 teach you to read a point on a grid using two numbers and measure short distances along the walls of a room.

• Questions solved: one figure-based question with four parts, all answered in full.
• Main skills: reading coordinates from a grid and finding lengths along an axis.
• Chapter link: it sets up the plotting and distance work in Exercise 1.2.

These solutions are prepared by subject teachers, matched to the current 2026-27 NCERT, and checked step by step so a Class 9 student can follow each line.

What Does Class 9 Maths Chapter 1 Coordinates Exercise 1.1 Cover?

Exercise 1.1 uses a simple real-life picture. Reiaan's room is drawn on a grid, with the bottom wall as the x-axis and the left wall as the y-axis. You locate doors and corners, write each as a point (x, y), and measure how wide a door is. The key idea is that a point on the x-axis has y = 0, and a point on the y-axis has x = 0. When two points share a coordinate, the gap between them is just the difference of the numbers that change. The exercise keeps the numbers small and the picture clear, so it is a gentle start to the chapter. You do not need any formula yet. You only need to count grid squares and subtract carefully. This makes Exercise 1.1 the best place to fix your basics before harder plotting begins.

Video Walkthrough

Source: PW Class 9 - NEEV on YouTube

Coordinates Exercise 1.1 Question Breakdown

This exercise has a single question built around Fig. 1.3, but it is split into four parts. The table shows what each part asks.

Sample Solved Question from Exercise 1.1

Here is part (iii), solved step by step, so you can see how a length is found on the grid.

Question: The room door runs from D₁(8, 0) to R₁(11.5, 0). How wide is the door?

Step 1. Check the two ends. Both D₁ and R₁ have y = 0, so the door lies flat along the x-axis.

Step 2. Since the points share the y-value, the width is the difference of the x-values.

Step 3. Subtract: |11.5 - 8| = 3.5 feet.

Final answer. The room door is 3.5 feet wide, a comfortable width that a wheelchair can pass through.

How to Use These Coordinates Exercise 1.1 Solutions

Read the figure first, then try each part on your own. Use the Collegedunia solutions only to check your working line by line. Do not copy the steps before you have tried the part yourself. The value comes from spotting your own mistake and fixing it.

• Trace each door on the grid before you write any number.
• Mark which coordinate stays fixed, so you know which one to subtract.
• Compare your final door widths with the answers here to catch sign slips.

More Class 9 Maths Coordinates Solutions

Open the full chapter page or any other exercise of Coordinates from the table below.