CU Jharkhand Cutoff 2025: Check Category-wise and Round-wise Cutoff

JEE Main 2025 Cutoff for CU Jharkhand for B.Tech admission ranges from 59801 to 105884 in the General category. For B.Tech Computer Science Engineering, the Round 1 cutoff is 59801 and the last round cutoff is 74114. B.Tech Civil Engineering recorded a Round 1 cutoff of 67148 and a last round rank of 91069. Other courses such as Electrical Engineering and Metallurgical and Materials Engineering show a cutoff range between 70853 and 105884 for admission.

For OBCNCL candidates, the cutoff is in the range of 21677 for Computer Science Engineering to 38934 for Metallurgical and Materials Engineering. In the SC category, the range is 11039 in Civil Engineering to 15693 in Metallurgical and Materials Engineering. For ST candidates, the cutoff is between 3656 for Civil Engineering and 7086 for Metallurgical and Materials Engineering. Under the EWS category, the admission cutoff ranges from 9213 for Computer Science Engineering to 16815 for Metallurgical and Materials Engineering.