Structure of Atom Class 11 MCQ

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Jasmine Grover

Content Strategy Manager | Updated On - Aug 27, 2024

Atoms combine to form molecules, which then interact to form solids, gases, or liquids. The structure of atom consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom is composed of protons (positively charged) and the neutrons (no charge). The outermost portion of the atom are called electronic shells and contain electrons (negatively charged). Based on the arrangement and number of their constituent elements, an atom possess different properties. 

Class 11 Chemistry MCQs with answers and explanations are provided here for Structure of Atom. The structure of Atom MCQs is based on the CBSE board curriculum and the updated chemistry syllabus. 

Structure of Atom

Ques 1. Who discovered the electron?

  1. Rutherford
  2. Chadwick
  3. Thomson
  4. Goldstein

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Answer. (c) Thomson

Explanation: J.J Thomson discovered electrons in 1897 by performing the cathode ray experiment. Electrons are the smallest of the particles that make up an atom, and they carry a negative charge. The number of protons and electrons is equal in a neutral atom.

Ques 2. The principal quantum number describes ____

  1. energy and size of the orbit
  2. the shape of the orbital
  3. spatial orientation of the orbital
  4. the spin of the electron

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Answer: a) energy and size of the orbit

Explanation: Among the four quantum numbers, the principal quantum number describes the size and energy of the orbit. It is represented by the symbol “n”. For shells, K, L, M, N, and O, n are given by 1, 2, 3, 4, and 5.

Ques 3. What was the source of alpha particles in the Rutherford scattering experiment?

  1. Hydrogen nucleus
  2. Argon nucleus
  3. Helium nucleus
  4. None of these

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Answer. (c) Helium nucleus

Explanation: Alpha particle consists of two neutrons and two protons and is thus identical to the nucleus of a helium atom. It has no charge. The mass of the particle is approximately the sum of the mass of the proton and neutron. Its charge is equal to that of 2 protons.

Ques 4. According to Aufbau's principle, which of the following orbital should be filled first?

  1. 5d
  2. 4p
  3. 3p
  4. 2s

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Answer: d) 2s

Explanation: As per Aufbau's principle, the orbital or subshell with the lowest energy should be filled first. The ascending order of orbitals energy is given by 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 4f, 5d, 6p, 7s. So 2s orbital should be filled first.

Ques 5. What property of an element determines its chemical behaviour?

  1. Size of an element
  2. Valency of an element
  3. The molar mass of the element
  4. None of these

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Answer. (b) Valency of an element

Explanation: An element's valence is the number of hydrogen atoms that can combine with or replace (directly or indirectly) one of the element's atoms. Oxygen, for instance, has six valence electrons but its valence is 2. Some elements may have more than one power combination (or valence), while others may have only one.

Ques 6. Which of the following does not match the characteristics of an Isotope?

  1. Isotopes of some elements are radioactive
  2. Isotopes are the atoms of different elements
  3. Isotopes differ in the number of neutrons
  4. Isotopes have similar chemical properties

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Answer. (b) Isotopes are the atoms of different elements

Explanation: Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons. The number of protons in a nucleus determines the element's atomic number on the Periodic Table.

Ques 7. No two electrons have the same set of all four quantum numbers.

  1. True
  2. False

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Answer: a) True

Explanation: Yes, no two electrons have the same set of all four quantum numbers. This is explained by Pauli’s exclusion principle. At most electrons can have all 3 quantum numbers the same as they are in the same orbital. But the spin quantum number’s values are different.

Ques 8. Which of the two will be chemically more reactive, Sulphur(S) with atomic number 16 or Chlorine (Cl) with atomic number 17?

  1. Chlorine
  2. Sulfur
  3. Both are equally reactive
  4. Can’t say

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Answer. (a) Chlorine

Explanation: Chlorine can accept one electron easily as compared to sulphur which needs two electrons to complete its Octet. Hence, chlorine is more reactive chemically than sulphur.

Ques 9. Which of the following elements does not exhibit electrovalency?

  1. Sodium
  2. Calcium
  3. Carbon
  4. Chlorine

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Answer. (c) Carbon

Explanation: Elements that lose electrons show positive electrovalency and those which gain electrons show negative electrovalency. For example, in the formation of sodium chloride (Na+Cl), the electrovalency of sodium (Na) is +1, while that of chlorine (Cl) is –1.

Ques 10. What is the shape of the orbital, whose “l” is 1?

  1. Spherical
  2. Dumbbell
  3. Double dumbbell
  4. Complex

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Answer: b) Dumbbell

Explanation: The azimuthal quantum number is given by “l”. When l =0, 1, 2, and 3, they are s-orbital, p-orbital, d-orbital, and f-orbital respectively. The shapes of s-orbital, p-orbital, d-orbital, and f-orbital are Spherical, Dumbbell, Double dumbbell, and Complex respectively.

Ques 11. Which scientist gave the concept of fixed energy levels around the nucleus?

  1. Ernest Rutherford
  2. Neils Bohr
  3. J.J.Thomson
  4. None of these

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Answer. (b) Neils Bohr

Ques 12. Which of the following pairs are isobars?

  1. 17Cl35 & 17Cl37
  2. 18Ar40 & 20Ca40
  3. 6C12 & 6C14
  4. None of these

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Answer. (b) 18Ar40 & 20Ca40

Explanation: Isobar is any member of a group of atomic or nuclear species all of which have the same mass number—that is, the same total number of protons and neutrons. Thus, they are isobars.

Ques 13. Which radioactive element is used in the treatment of cancer?

  1. Iodine-131
  2. Uranium-234
  3. Plutonium-239
  4. Cobalt-60

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Answer. (d) Cobalt-60

Explanation: Radioactive elements are made up of atoms whose nuclei are unstable and give off atomic radiation as part of a process of attaining stability. The emission of radiation transforms radioactive atoms into another chemical element, which may be stable or maybe radioactive such that it undergoes further decay.

Ques 14. What is the magnetic quantum number of the orbital 2pz?

  1. 1
  2. ±1
  3. -1
  4. 0

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Answer: d) 0

Explanation: The magnetic quantum of orbital ranges from -( l–1) to l–1. Its symbol is given by m. For 2p orbital, there are 3 magnetic quantum numbers namely -1, 0, and 1. For 2pz orbital it's 0, taking that z is the internuclear axis.

Ques 15. Total number of nodes for 3d orbital is ________

  1. 3
  2. 2
  3. 1
  4. 0

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Answer: b) 2

Explanation: Total number of nodes includes angular and radial nodes. Angular nodes and radial nodes are given by the formula n–l -1 and l respectively. So the total number of nodes is n–l -1+l=n–1. For 3d orbit, “n” is 3, so t total number of nodes is 3–1=2.

Read More:

Structure of Atom – Related Concepts
Hydrogen Spectrum Planck's Quantum Theory and Black Body Radiation Electronic Configuration OF First 30 Elements
Shapes of Atomic Orbitals Degenerate Orbitals Energy level Diagram
Discovery of Electron Isobars and Isotopes Wave Nature of Electromagnetic Radiation
Emission and Absorption Spectra Line Spectrum of Hydrogen Limitations of Bohr’s Model
Quantum Mechanical Model of Atom Energies of Orbitals Aufbau Principle

Ques 16. Which of the following sets of quantum numbers is not valid?

  1. n=5, l=2, m=0, s=½
  2. n=1, l=2, m=0, s=½
  3. n=5, l=3, m=2, s=½
  4. n=5, l=2, m=0, s=-½

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Answer: b) n=1, l=2, m=0, s=½

Explanation: The set of quantum numbers n=1, l=2, m=0, s=1/2, is not valid because the value of the azimuthal quantum number should lie only in between 0 and n-1, where n is a principal quantum number. So the above set of quantum numbers is not valid.

Ques 17. How many electrons can exist with the principal quantum number’s value of 4?

  1. 16
  2. 4
  3. 32
  4. 12

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Answer: c) 32

Explanation: The number of orbitals within an orbit is n2. But as each orbital can accommodate 2 electrons, the number of electrons that can exist with the “n” as the principal quantum number is 2n2. So here 2n2=2(4)2=2(16)=32.

Ques 18. Write the values for l, n, and m for Ψ 3,1,0.

  1. 1, 3, 0
  2. 3, 1, 0
  3. 0, 3, 1
  4. 1, 0, 3

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Answer: a) 1, 3, 0

Explanation: The representation of the Schrodinger wave function is given by Ψn,l,m. Therefore by comparing Ψn,l,m and Ψ3,1,0 we get that n=3, l=1, and m=0. Here n, l, and m are principal, azimuthal, and magnetic quantum numbers respectively.

Ques 19. Who discovered the neutron?

  1. J.J Thomson
  2. Rutherford
  3. Chadwick
  4. Priestley

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Answer: c) Chadwick

Explanation: Chadwick discovered the neutral particles known as neutrons.

Ques 20. A sub-shell with n = 6, l = 2 can accommodate how many maximum electrons?

  1. 12 electrons
  2. 10 electrons
  3. 36 electrons
  4. 72 electrons

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Answer: b) 10 electrons

Explanation: n = 6, l = 2, therefore 6d will have 5 orbitals.
Hence maximum of 10 electrons can be accommodated as each orbital can have a maximum of 2 electrons.

Ques 21. In Bohr’s hydrogen atom model, the ratio of kinetic energy to the total energy of the electron in a quantum state n is

  1. 1
  2. -1
  3. 2
  4. -2

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Answer: b) -1

Explanation: In the Bohr model, the kinetic energy of an electron in an orbit = + (1/2) (e2/rn)

Total energy of the electron in an orbit = -(e2/2rn)

Therefore, KE/TE = -1

Ques 22. In a Hydrogen atom, the energy of the first excited state is – 3.4 eV. What is the KE of the same orbit of the Hydrogen atom?

  1. -13.6 eV
  2. 13.6 eV
  3. 3.4 eV
  4. 6.8 eV

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Answer: c) 3.4 eV

Explanation: For a hydrogen atom, the kinetic energy is the negative of the total energy.
The potential energy is twice the total energy.
The first excited state energy of orbital = -3.4 eV
and kinetic energy of same orbital = -(-3.4 eV) = 3.4 eV
Therefore, the kinetic energy of the same orbit of a hydrogen atom is 3.4 eV.

Ques 23. The ionization enthalpy of a hydrogen atom is 1.312 × 106 J mol-1. The energy to excite the electron from n = 1 to n = 2 is – 

  1.  6.56 × 105 J mol-1
  2. 8.51 × 105 J mol-1
  3. 7.56 × 105 J mol-1
  4. 9.84 × 105 J mol-1

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Answer: d) 9.84 × 105 J mol-1

Explanation: The energy required when an electron shifts from n = 1 to n = 2

E2 = −(1.312 × 106 × (1)²)/(2²) = −3.28 × 105 J mol-1

E1 = −1.312 × 106 J mol-1

ΔE = E2 − E1

= −3.28 × 105−(−13.2 × 106)

ΔE = 9.84 × 105 J mol-1

Ques 24. The electrons of the same orbitals are identified by – 

  1. Spin quantum number
  2. Azimuthal quantum number
  3. Magnetic quantum number
  4. Principal quantum number

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Answer: a) Spin quantum number

Explanation: Electrons having the same orbital are identified by Spin quantum number. Spin Quantum number has two values +1/2 or -½. Spin quantum number explains the direction through which an electron spins in an orbital. An electron in the same orbitals must have opposite spins. 

Ques 25. An element in the ground state that has 13 electrons in its M-shell is – 

  1. Nickel
  2. Copper
  3. Iron
  4. Chromium

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Answer: d) Chromium

Explanation: As it is in M shell, n = 3

Number of electrons in M shell = 13 → 3s23p63d5

The electronic configuration is (1s2) (2s2 2p6) (3s2 3p6 3d5) (4s1)

The element is therefore chromium.

Ques 26. Out of the following element, which one has the least number of electrons in its M-shell?

  1. Sc
  2. Mn
  3. K
  4. Ni

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Answer: c) K

Explanation: K = 19 = 1s²2s22p63s23p6s1

3s23p6 = m-shell

Hence, k has only 8 electrons in the M shell.

Ques 27. What does the magnetic quantum number signify? 

  1. Shape of orbitals
  2. Nuclear Stability
  3. Orientation of orbitals
  4. Size of orbitals

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Answer: c) Orientation of orbitals

Explanation: The magnetic quantum number signifies the orientation of orbitals

Ques 28. A gas absorbs a 355 nm photon and emits two wavelengths. If the first emission is at 680 nm, the other is at: 

  1. 518 nm
  2. 325 nm
  3. 1035 nm
  4. 743 nm

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Answer: d) 743 nm

Explanation: From the Law of Conservation of energy, the energy of the absorbed photon is equal to the combined energy of two emitted photons.
ET = E1 + E2 – (1)

Here, E1 is the Energy of the first emitted photon emitted and Eis the Energy of the second emitted photon.

Now, E = (hc)/ (λ) – (2)

Substituting values from (2) in (1) we get

(hc/λT) = (hc)/ (λ1) + (hc)/ (λ2)

Therefore, on solving the equation, we get λ2 = 742.77nm

Ques 29. The increasing order for the e/m values for the following are –  

  1. n, p, e, α
  2. n, p, α, e
  3. e, p, n, α
  4. n, α, p, e

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Answer: d) n, α, p, e

Explanation: The charge to mass ratio (e/m) for the following is as follows –

  • neutron, n = (0/1) = 0
  • α− particle = (2/4) = 0.5
  • Proton, p = (1/1) = 1
  • Electron, p = (1/1837) = 1837.

Ques 30. In the ground state, the electronic configuration of the silver atom is –  

  1. [Kr]4d95s2
  2. [Kr]4d105s1
  3. [Xe]4f145d106s1
  4. [Kr]3d104s1

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Answer: b) [Kr]4d105s1

Explanation: The electronic configuration of Ag in the ground state is [Kr]4d105s1.

Ques 31. Which of the following models is not similar to the Thomsom Model of Atom?

  1. Plum pudding model
  2. Raisin pudding model
  3. Nuclear model
  4. Watermelon model

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Answer: c) Nuclear model

Explanation: Thomson proposed a model to understand the structure of atom and arrangement of electrons around the nucleus of an atom. It is also known as plum pudding model, raisin pudding model & watermelon model. 

Ques 32. The absolute charge of a proton (in Coloumb) is----

  1. +1.60 X 10-19
  2. -1.60 X 10​-23
  3. +1.66 X 10​-27
  4. -1.66 X 10​-23

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Answer: a) +1.60 X 10-19

Explanation: The discovery of protons is credited to Rutherford. According to him, protons are positively charged particle present in the structure of an atom. The charge upon single proton is called its absolute charge i.e, +1.60 X 10-19 C.

Structure of Atom Class 11 MCQs can be used to prepare for the board exams as well as competitive exams.


Also check:

CBSE CLASS XII Related Questions

1.
Depict the galvanic cell in which the reaction Zn(s) + 2Ag+(aq) → Zn2+(aq) + 2Ag(s) takes place. Further show: 
 (i) Which of the electrode is negatively charged? 
 (ii) The carriers of the current in the cell. 
 (iii) Individual reaction at each electrode.

      2.

      Which of the following compounds would undergo aldol condensation, which the Cannizzaro reaction and which neither? Write the structures of the expected products of aldol condensation and Cannizzaro reaction. 
      \((i) Methanal \)
      \((ii) 2-Methylpentanal \)
      \((iii) Benzaldehyde \)
      \((iv) Benzophenone \)
      \((v) Cyclohexanone \)
      \((vi) 1-Phenylpropanone \)
      \((vii) Phenylacetaldehyde \)
      \((viii) Butan-1-ol \)
      \((ix) 2, 2-Dimethylbutanal\)

          3.
          Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.

              4.

              How would you account for the following: 

              1. Of the d4 species, Cr2+ is strongly reducing while manganese(III) is strongly oxidising. 
              2. Cobalt(II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised. 
              3. The d1 configuration is very unstable in ions.

                  5.

                  Draw the structures of optical isomers of: 
                  (i) \([Cr(C_2O_4)_3]^{3–}\)
                  (ii) \([PtCl_2(en)_2]^{2+}\)
                  (iii) \([Cr(NH_3)2Cl_2(en)]^{+}\)

                      6.

                      Give the IUPAC names of the following compounds:

                      (i)CH3CH(Cl)CH(Br)CH3

                      (ii)CHF2CBrClF

                      (iii)ClCH2C≡CCH2Br

                      (iv)(CCl3)3CCl

                      (v)CH3C(p-ClC6H4)2CH(Br)CH3

                      (vi)(CH3)3CCH=CClC6H4I-p

                          CBSE CLASS XII Previous Year Papers

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