Hund’s Rule: Electronic Configuration, Application & Examples

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Hund’s rule of maximum multiplicity deals with the filling of electrons in the subshell of atoms. It helps in determining the overall electronic configuration by removing the anomalies related to the same energy orbitals in a subshell. Electrons filling in the orbitals of the same subshell follow the guidelines as stated by Hund’s rule.

Keyterms: Electron, atoms, subshell, orbitals, Energy level, Aufbau rule, Pauli Exclusion rule, atomic spectra

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Hund’s Rule

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Hund’s Rule of maximum multiplicity provides a method for arranging electrons in orbitals of a subshell. The Aufbau rule works according to the energy level of the subshells and determines the lowest energy subshell to be filled first. Each subshell (s,p,d,f) has a different number of orbitals. Electrons filling in the orbitals of the same subshell follows the guidelines as stated by Hund’s rule. 

Hund’s Rule

Hund’s Rule

The rule includes two basic parameters.

  • Before completely filling a subshell, every orbital in that subshell must be singly filled.
  • For maximum multiplicity, all electrons are assigned the same spin in orbitals with single occupancy.

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Explanation Of Hund’s Rule

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Each atom has subshells and a subshell can have a different number of orbitals. The Aufbau principle determines that the lowest energy orbital gets filled first. But an anomaly arises in the case of orbitals of the same subshell. The orbitals of the same subshell have the same energy. Hund’s rule comes into play here.

The following diagram illustrates how the 2p orbitals get filled up subsequently:

Filling up of Orbitals

Filling up of Orbitals

According to Hund’s rule of maximum multiplicity, all electrons while entering a subshell, fill up the orbitals of the subshell singly i.e. unpaired electrons occupy all the orbitals first. All such electrons are having the same spin so as to maximise the multiplicity of spin. According to the rule, the lowest energy term in the electronic configuration will be the one with the highest value of spin multiplicity.

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Hund’s Rule And Electronic Configuration

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Three basic laws govern the overall electronic configuration of atoms of the periodic table: The Aufbau principle, The Hund’s rule and the Pauli Exclusion principle. 

  • Aufbau rule decides that the orbitals having the lowest energy shall be filled first. 
  • Pauli exclusion rule determines that no two electrons in an orbital can have the same spin. 
  • Hund’s rule focuses on the electronic configuration in the case of orbitals of the same subshell i.e. the degenerate orbitals. Let us take a few examples:

p-subshell

Filling of p subshell

Filling of p subshell

Every p-subshell has 3 orbitals. First, the three orbitals get singly filled. Then the remaining electrons enter the orbitals to pair up. They follow the Pauli exclusion rule which maintains that inside an orbital electrons will have opposite spin.

d-subshell

Following Hund’s rule, the first five electrons in the five orbitals have the same spin. Then they pair up subsequently.

Filling of d subshell

Filling of d subshell

The stability of any electronic configuration will increase if the electron-electron repulsion is minimised. So in the case of a subshell with singly filled degenerate orbitals, unpaired electrons are the farthest from each other. Hence stability is achieved through Hund’s rule.

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Examples Of Hund’s Rule

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Let us see how Hund’s rule affects the electronic configuration of degenerate orbitals of the following atoms:

Nitrogen atom

Electronic Configuration: 1s22s22p3

Nitrogen orbital filling

Nitrogen orbital filling

Here, the 2p subshell has three electrons. So accordingly before pairing all the orbitals will be filled with single electrons.

Oxygen atom

Electronic Configuration: 1s22s22p4

Oxygen orbital filling

Oxygen orbital filling

Since an oxygen atom has one more electron than nitrogen, that electron will now pair up the electron in the first orbital of the p-subshell.

Carbon atom

Electronic configuration : 1s22s22p2

Carbon orbital filling

Carbon orbital filling

While filling up the 2p orbitals, 2 electrons occupy an orbital each with identical spin conforming to Hund’s rule.

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Applications of Hund’s Rule

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  • Hund’s rule has indispensable significance in quantum chemistry. It emphasises the stability of degenerate orbitals of the same subshell.
  • Hund’s rule has uses in spectroscopy to generate the atomic spectra of elements.
  • Hund’s rule helps in determining a stable electronic configuration by ensuring maximum multiplicity of spin.

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Things To Remember

  1. Three basic laws govern the overall electronic configuration of atoms of the periodic table: The Aufbau principle, The Hund’s rule and the Pauli Exclusion principle.
  2. Maximum multiplicity of spin is obtained by the electrons filling the degenerate orbitals. This means that initially when all the orbitals are singly filled all the electrons will have identical spin.
  3. The Pauli exclusion rule determines that no two electrons in an orbital can have the same spin.
  4. Electronic configuration determines the orbital location of the electrons of an atom as well as the overall stability of the atom.
  5. According to the Aufbau rule, the orbital with the lowest energy gets filled first.

Previous Year Questions


Sample Questions

Ques. What is the purpose of electronic configuration? State Aufbau principle. (3 marks)

Ans. Valence electrons have the biggest role in an element’s chemical behaviour. An atom with unpaired electrons in its valence shell will be more unstable than the ones having all the electrons paired. This arrangement of electrons in the orbitals according to the energy of the subshells is called electronic configuration. The Aufbau rule, Hund’s multiplicity rule, and the Pauli exclusion rule help us determine a stable configuration.

Aufbau principle states that while filling up the electrons in the orbitals, the orbital with the least energy gets filled up first.

Ques. Write the electronic configuration of the Oxygen atom according to Aufbau and Hund’s rules. (3 marks)

Ans. Oxygen atom has 8 electrons. Hence the electronic configuration can be written as 1s22s22p4.

Electronic Configuration of the Oxygen Atom

The first two electrons enter the 1s orbital, 2nd two electrons pair up in the 2s orbital. Now for the 2p orbitals, there are three orbitals. Each orbital will take two electrons. So first all the orbitals get one each. Now we have a single electron left. So the first orbital gets paired. This is the electronic configuration of an Oxygen atom conforming to Aufbau and Hund’s rules.

Ques. State a few applications of Hund’s rule. (2 marks)

Ans. Few applications of Hund’s rule are as follows:

  1. Hund’s rule has indispensable significance in quantum chemistry.It emphasises on the stability of degenerate orbitals of the same subshell.
  2. Hund’s rule has been used in spectroscopy to generate the atomic spectra of elements.
  3. Hund’s rule helps in determining a stable electronic configuration by ensuring maximum multiplicity of spin.

Ques. What is a multiplicity of spin? Explain it using an example. (3 marks)

Ans. Multiplicity of spin is given by the total number of spin orientations. Multiplicity of spin is calculated by the formula 2S+1. Hund’s rule says that the highest value of 2S+1 conforms to the lowest energy or the most stable configuration. The maximum value is attained only in the case of identical spins. Let us take the example of the 2p subshell. The 2p subshell has 3 orbitals. Let us fill 3 electrons in the three orbitals. The different arrangements possible are shown below:

Multiplicity of spin

The value of 2S+1 is maximum in the 1st and 4th cases since the electrons are having identical spins. So the spins add up resulting in a maximum spin.

Ques. Find out the spin multiplicity of the Oxygen atom. (2 marks)

Ans. The electronic configuration of the Oxygen atom is 1s22s22p4. Only one degenerate orbital of the 2p subshell gets paired up.

Spin Multiplicity of the Oxygen Atom

S = 1 and the multiplicity is 2S + 1 = 3.

Ques. Find the spin multiplicity of the Nitrogen atom. (2 marks)

Ans. Nitrogen has the electronic configuration of 1s22s22p3. Hence all the degenerate orbitals of the 2p subshell are half-filled.

Spin Multiplicity of the Nitrogen Atom

So, spin = ½ +½ +½ = 3/2 

And multiplicity = 2S+1 = 2(3/2)+1 = 4.

Ques. What subshells are possible in n=3 energy level? How many orbitals are possible at this level? (2 marks)

Ans. We know that the values of the quantum number l determine the number of subshells.

For n=3, l has the values: 0,1 and 2. So three subshells s, p and d are possible at n=3 energy level.

For n=3 energy level we have three subshells- s,p and d subshells. We know that the subshell has 1 orbital. p has 3 orbitals and d subshell has 5 orbitals. So the total number of orbitals at n=3 energy level is 9.

Ques.(a)If the quantum number l has a value of 2 then what can be the permitted values of ml
(b)For an orbital with n=3, what are the different possible values of l?
(c) For l=3, what are the possible values of ml? (3 marks)

Ans.

  1. For l=2, the permitted values of ml are = -2 , -1 , 0 , +1 , +2 .
  2. For n=3, the possible values of l are = 0,1 and 2.
  3. For l=3 , the possible values of ml are = -3 , -2 , -1 , 0 , +1 , +2 , +3 .

Ques. Write the electronic configurations Fe2+ and find the total number of unpaired electrons in its ground state. (2 marks)

Ans. Fe2+ The electronic configuration of Fe is 1s22s22p63s23p63d64s2

For Fe2+ 2 electrons are removed from the 4s orbital so the resultant configuration is :

1s22s22p63s23p63d6 . All orbitals are completely filled except the 3d orbitals. We can write the arrangement of the 3d orbitals as follows

Electronic Configurations Fe2+

As is clear, the total number of unpaired electrons = 4.

Ques. Write the electronic configuration of Cl- ion. Also, find the total number of unpaired electrons in its ground state. (2 marks)

Ans. The electronic configuration of Clis 1s22s22p63s23p5 . Since Cl- has one electron extra. So its p subshell will be fully paired. Hence the electronic configuration for Cl- ion will be 

1s22s22p63s23p6

So the total number of unpaired electrons is zero.


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CBSE CLASS XII Related Questions

1.
Write the Nernst equation and emf of the following cells at 298 K : 
(i) Mg(s) | Mg2+ (0.001M) || Cu2+(0.0001 M) | Cu(s) 
(ii) Fe(s) | Fe2+ (0.001M) || H+ (1M)|H2(g)(1bar) | Pt(s) 
(iii) Sn(s) | Sn2+(0.050 M) || H+ (0.020 M) | H2(g) (1 bar) | Pt(s) 
(iv) Pt(s) | Br2(l) | Br-  (0.010 M) || H+ (0.030 M) | H2(g) (1 bar) | Pt(s).

      2.
      Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.

          3.

          Write down the electronic configuration of:
          (i) Cr3+ (iii) Cu+ (v) Co2+ (vii) Mn2+ 
          (ii) Pm3+ (iv) Ce4+ (vi) Lu2+ (viii) Th4+

              4.

              Write equations of the following reactions: 
              (i)Friedel-Crafts reaction–alkylation of anisole.
              (ii)Nitration of anisole.

              (iii)Bromination of anisole in ethanoic acid medium.
              (iv)Friedel-Craft’s acetylation of anisole.

               

                  5.
                  Depict the galvanic cell in which the reaction Zn(s) + 2Ag+(aq) → Zn2+(aq) + 2Ag(s) takes place. Further show: 
                   (i) Which of the electrode is negatively charged? 
                   (ii) The carriers of the current in the cell. 
                   (iii) Individual reaction at each electrode.

                      6.

                      The rate constant for the decomposition of hydrocarbons is 2.418 x 10-5 s-1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

                          CBSE CLASS XII Previous Year Papers

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