NCERT Solutions For Class 11 Physics Chapter 7: System of Particles and Rotational Motion

NCERT Solutions for Class 11 Physics Chapter 7 System of Particles and Rotational Motion covers all the concepts discussed in the Class 11 Physics Chapter 7. The combination of rotational motion and the translational motion of a rigid body is known as rolling motion. According to the law of conservation of angular momentum, if there is no external couple acting, the total angular momentum of a rigid body or a system of particles is conserved.

Class 11 Physics Chapter 7 System of Particles and Rotational Motion has a weightage of 17 marks along with Unit 4 Work, Energy, and Power and Unit 6 Gravitation. The Class 11 Physics Chapter 7 discusses the concepts of TorqueAngular Momentum, and Rotational Kinetic Energy.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 7


NCERT Solutions for Class 11 Physics Chapter 7

NCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT Solutions

Class 11 Physics Chapter 7 – Concepts Covered

  • Centre of MassFor a system of particles, the centre of mass is the balancing point where the entire mass of the system is concentrated, for consideration of its translational motion.

If there are 2 particles with mass m1 and m2 with position vectors \(\overrightarrow{r_1}\ and\ \overrightarrow{r_2}\), then the position vector of centre of mass is given as:

\(\overrightarrow{r_{cm}} = {{m_1}\overrightarrow{r_{1}} + {m_2}\overrightarrow{r_{2}} \over m_1 + m_2}\)

  • The cross product of two vectors \(\overrightarrow{A}\) and \(\overrightarrow{B}\) is another vector \(\overrightarrow{C}\), which has a magnitude equal to the product of the magnitudes of 2 vectors and the sine of the smaller angle \(\theta\) between them.
\(\overrightarrow{A} \times \overrightarrow{B} = \overrightarrow{C} = ABsin\theta \hat{c}\)
  • Torque or moment of force is the product of the magnitude of the force acting on a particle and the perpendicular distance of the application of this force from the axis of rotation of the particle.
\(Torque = Force \times perpendicular\ distance\)
  • The angular momentum about an axis of rotation is a vector quantity, with a magnitude equal to the product of the magnitude of momentum and the perpendicular distance of the line of action of momentum from the axis of rotation. Its direction is perpendicular to the plane that contains the momentum and the perpendicular distance.

\(\overrightarrow{L} = \overrightarrow{r} \times \overrightarrow{p} \)

  • Torque and angular momentum are correlated to each other.
\(\tau = {\overrightarrow{dL} \over dt}\)

CBSE CLASS XII Related Questions

  • 1.
    Two infinitely long conductors kept along XX' and YY' axes are carrying current \( I_1 \) and \( I_2 \) along -X axis and -Y axis respectively. Find the magnitude and direction of the net magnetic field produced at point P(X, Y).


      • 2.

        Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen? 


          • 3.
            A current flows through a cylindrical conductor of radius \( R \). The current density at a point in the conductor is \( j = \alpha r \) (along its axis), where \( \alpha \) is a constant and \( r \) is the distance from the axis of the conductor. The current flowing through the portion of the conductor from \( r = 0 \) to \( r = \frac{R}{2} \) is proportional to:

              • \( R \)
              • \( R^2 \)
              • \( R^3 \)
              • \( R^4 \)

            • 4.

              A current-carrying coil is placed in an external uniform magnetic field. The coil is free to turn in the magnetic field. What is the net force acting on the coil? Obtain the orientation of the coil in stable equilibrium. Show that in this orientation the flux of the total field (field produced by the loop + external field) through the coil is maximum. 


                • 5.
                  A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).


                    • 6.
                      In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:
                       curved lines represent equipotential surfaces

                        • A
                        • B
                        • C
                        • D
                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show