NCERT Solutions for class 10 Maths chapter 15 Probability

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NCERT Solutions for class 10 Maths chapter 15 Probability are provided in this article. Some of the important topics in Probability chapter include:

  1. Probability Impossible Events
  2. Events in Probability
  3. Geometric Probability
  4. Probability- A Theoretical Approach

Expected no.of questions: 2 to 3 questions of total 5 marks

Download PDF: NCERT Solutions for Class 10 Mathematics Chapter 15 pdf


NCERT Solutions for Class 10 Mathematics Chapter 15

NCERT Solutions for Class 10 Mathematics Chapter 15 Probability is given below.

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Class 10 Mathematics Chapter 15 Probability – Important Topics

The three types of probabilities are theoretical probability, experimental probability, and axiomatic probability. The theoretical probability calculates the probability based on formulas and input values. The experimental probability gives a realistic value and is based on the experimental values for calculation. Quite often the theoretical and experimental probability differ in their results and the axiomatic probability is based on the axioms which govern the concepts of probability.

Formula for Probability:

P(E) = n(E) / n(S)

Formula for Theoretical Probability:

P(E) = Number of Favourable Outcomes / Number of Total Outcomes

Formula for Experimental Probability:

P(E) = Number of Favourable Outcomes / Total number of times experiment is done

Rules of Probability:

  • Probability of an impossible event is null.
  • Maximum Probability of any event can be its total number of possible outcomes.
  • Probability exists between 0 and 1. The probability can be zero also.
  • Probability cannot be negative.
  • Probability of A or Probability of B is addition of probability of A and the probability of B.

NCERT Solutions for Class 10 Maths Chapter 15 Exercises

NCERT Solutions for Class 10 Mathematics Chapter 15 Probability Exercises are given below.

Chapter Related Articles:

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CBSE X Related Questions

  • 1.
    Evaluate : \(\frac{3 \cos^2 30^{\circ} - 6 \csc^2 30^{\circ}}{\tan^2 60^{\circ}}\).


      • 2.
        Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
        Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Assertion (A) is false, but Reason (R) is true.

        • 3.
          If the median of the following distribution is 32.5, then find the values of x and y.


            • 4.

              Which of the following sequence is \(\textit{not }\)an A.P. ?
               

                • \( 2, \frac{5}{2}, 3, \frac{7}{2}, \dots \)
                • \( -1.2, -3.2, -5.2, -7.2, \dots \)
                • \( \sqrt{2}, \sqrt{8}, \sqrt{18}, \dots \)
                • \( 1^2, 3^2, 5^2, 7^2, \dots \)

              • 5.
                Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

                  • \(2\pi r^3\)
                  • \(3\pi r^3\)
                  • \(5\pi r^3\)
                  • \(4\pi r^3\)

                • 6.
                  Aarush bought 2 pencils and 3 chocolates for Rs 11 and Tanish bought 1 pencil and 2 chocolates for Rs 7 from the same shop. Represent this situation in the form of a pair of linear equations. Find the price of 1 pencil and 1 chocolate, graphically.

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