CBSE Class 10 2025 Mathematics Set-3 (430/6/3) Question Paper : Download Solution PDF With Answer Key

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Shivam Yadav

Updated 3+ months ago

The Mathematics theory paper is of 80 marks, while 20 marks are allocated for the internal assessment. The paper covers topics such as Algebra, Geometry, Trigonometry, Mensuration, Statistics & Probability, and Coordinate Geometry. It includes formula-based, conceptual, and application-based problems.

CBSE Class 10 Mathematics Question Paper 2025 Set – 3 (430/6/3) with Answer Key

CBSE Class 10 2025 Mathematics Question Paper with Answer Key

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CBSE Class 10 Mathematics 2025 Question Paper with Solution (Set 2 43062)

Question 1:

In two concentric circles centred at \( O \), a chord \( AB \) of the larger circle touches the smaller circle at \( C \). If \( OA = 3.5 \, cm \), \( OC = 2.1 \, cm \), then \( AB \) is equal to

  • (A) 5.6 cm
  • (B) 2.8 cm
  • (C) 3.5 cm
  • (D) 4.2 cm
Correct Answer: (A) 5.6 cm
View Solution

Given: \( OA = 3.5 \, cm \), \( OC = 2.1 \, cm \).

Here, \( AB \) is a chord of the larger circle and touches the smaller circle at point \( C \), which implies \( C \) is the midpoint of chord \( AB \), and \( OC \) is perpendicular from the center \( O \) to chord \( AB \).

In the right triangle \( \triangle OAC \), \[ AC = \sqrt{OA^2 - OC^2} = \sqrt{(3.5)^2 - (2.1)^2} = \sqrt{12.25 - 4.41} = \sqrt{7.84} = 2.8 \, cm \]
Since \( C \) is the midpoint of \( AB \), the full length is: \[ AB = 2 \times AC = 2 \times 2.8 = 5.6 \, cm \]


% Quicktip Quick Tip: When a chord touches a smaller concentric circle and you’re given distances from the center, use the Pythagorean theorem to find half the chord length.


Question 2:

Three coins are tossed together. The probability that at least one head comes up is

  • (A) \(\dfrac{3}{8}\)
  • (B) \(\dfrac{7}{8}\)
  • (C) \(\dfrac{1}{8}\)
  • (D) \(\dfrac{3}{4}\)
Correct Answer: (B) \(\dfrac{7}{8}\)
View Solution

Question 3:

The volume of air in a hollow cylinder is \(450 \, cm^3\). A cone of same height and radius as that of cylinder is kept inside it. The volume of empty space in the cylinder is

  • (A) \(225 \, cm^3\)
  • (B) \(150 \, cm^3\)
  • (C) \(250 \, cm^3\)
  • (D) \(300 \, cm^3\)
Correct Answer: (A) \(225 \, \text{cm}^3\)
View Solution

Question 4:

If the length of the shadow of a tower is \(\sqrt{3}\) times its height, then the angle of elevation of the sun is

  • (A) \(45^\circ\)
  • (B) \(30^\circ\)
  • (C) \(60^\circ\)
  • (D) \(0^\circ\)
Correct Answer: (B) \(30^\circ\)
View Solution

Question 5:

22nd term of the A.P.: \(\frac{3}{2}, \frac{1}{2}, -\frac{1}{2}, -\frac{3}{2}, \ldots\) is

  • (A) \(\dfrac{45}{2}\)
  • (B) \(-9\)
  • (C) \(-\dfrac{39}{2}\)
  • (D) \(-21\)
Correct Answer: (C) \(-\dfrac{39}{2}\)
View Solution

Question 6:

In the given graph, the polynomial \(p(x)\) is shown. Number of zeroes of \(p(x)\) is

  • (A) 3
  • (B) 2
  • (C) 1
  • (D) 4
Correct Answer: (A) 3
View Solution

Question 7:

If probability of happening of an event is 57%, then probability of non-happening of the event is

  • (A) 0.43
  • (B) 0.57
  • (C) 53%
  • (D) \(\dfrac{1}{57}\)
Correct Answer: (A) 0.43
View Solution

Question 8:

OAB is a sector of a circle with centre O and radius 7 cm. If length of arc \(\overset{\frown}{AB} = \dfrac{22}{3} \, cm\), then \(\angle AOB\) is equal to

  • (A) \(\left(\dfrac{120}{7}\right)^\circ\)
  • (B) \(45^\circ\)
  • (C) \(60^\circ\)
  • (D) \(30^\circ\)
Correct Answer: (C) \(60^\circ\)
View Solution

Question 9:

If the sum of first \(n\) terms of an A.P. is given by \(S_n = \dfrac{n}{2}(3n + 1)\), then the first term of the A.P. is

  • (A) 2
  • (B) \(\dfrac{3}{2}\)
  • (C) 4
  • (D) \(\dfrac{5}{2}\)
Correct Answer: (D) \(\dfrac{5}{2}\)
View Solution

Question 10:

To calculate mean of grouped data, Rahul used assumed mean method. He used \(d = (x - A)\), where \(A\) is the assumed mean. Then \(\bar{x}\) is equal to

  • (A) \(A + \bar{d}\)
  • (B) \(A + h\bar{d}\)
  • (C) \(h(A + \bar{d})\)
  • (D) \(A - h\bar{d}\)
Correct Answer: (B) \(A + h\bar{d}\)
View Solution

Question 11:

The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

  • (A) 3
  • (B) -2
  • (C) -8
  • (D) 2
Correct Answer: (B) -2
View Solution

Question 12:

If \(\sqrt{3} \sin \theta = \cos \theta\), then value of \(\theta\) is

  • (A) \(\sqrt{3}\)
  • (B) \(60^\circ\)
  • (C) \(\dfrac{1}{\sqrt{3}}\)
  • (D) \(30^\circ\)
Correct Answer: (B) \(60^\circ\)
View Solution

Question 13:

ABCD is a rectangle with its vertices at \((2, -2), (8, 4), (4, 8), (-2, 2)\) taken in order. Length of its diagonal is

  • (A) \(4\sqrt{2}\)
  • (B) \(6\sqrt{2}\)
  • (C) \(4\sqrt{26}\)
  • (D) \(2\sqrt{26}\)
Correct Answer: (D) \(2\sqrt{26}\)
View Solution

Question 14:

Two dice are rolled together. The probability of getting a sum more than 9 is

  • (A) \(\dfrac{5}{6}\)
  • (B) \(\dfrac{5}{18}\)
  • (C) \(\dfrac{1}{6}\)
  • (D) \(\dfrac{1}{2}\)
Correct Answer: (B) \(\dfrac{5}{18}\)
View Solution

Question 15:

In \(\triangle ABC\), \(DE \parallel BC\). If \(AE = (2x + 1)\) cm, \(EC = 4\) cm, \(AD = (x + 1)\) cm and \(DB = 3\) cm, then value of \(x\) is

  • (A) 1
  • (B) 0
  • (C) -1
  • (D) \(\dfrac{1}{3}\)
Correct Answer: (A) 1
View Solution

Question 16:

The value of \(k\) for which the system of equations \(3x - 7y = 1\) and \(kx + 14y = 6\) is inconsistent, is

  • (A) -6
  • (B) \(\dfrac{2}{3}\)
  • (C) 6
  • (D) \(-\dfrac{3}{2}\)
Correct Answer: (A) -6
View Solution

Question 17:

In the given figure, \(PA\) is tangent to a circle with centre \(O\). If \(\angle APO = 30^\circ\) and \(OA = 2.5\, cm\), then \(OP\) is equal to

  • (A) 2.5 cm
  • (B) 5 cm
  • (C) \(\dfrac{5}{\sqrt{3}}\, cm\)
  • (D) 2 cm
Correct Answer: (C) \(\dfrac{5}{\sqrt{3}}\, \text{cm}\)
View Solution

Question 18:

Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

  • (A) 8 cm
  • (B) \(4\sqrt{5}\, cm\)
  • (C) \(2\sqrt{5}\, cm\)
  • (D) 12 cm
Correct Answer: (B) \(4\sqrt{5}\, \text{cm}\)
View Solution

Question 19:

Assertion (A): \((a + \sqrt{b}) \cdot (a - \sqrt{b})\) is a rational number, where \(a\) and \(b\) are positive integers.

Reason (R): Product of two irrationals is always rational.

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not correct explanation for Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (C) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (C) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 20:

Assertion (A): \(\triangle ABC \sim \triangle PQR\) such that \(\angle A = 65^\circ\), \(\angle C = 60^\circ\), \(\angle Q = 55^\circ\). Hence \(\angle Q = 55^\circ\).

Reason (R): Sum of all angles of a triangle is \(180^\circ\).

  • (A) Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not correct explanation for Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (C) Assertion (A) is false, but Reason (R) is true.
Correct Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
View Solution

Question 21:

A box contains 120 discs, which are numbered from 1 to 120. If one disc is drawn at random from the box, find the probability that

  • (i) it bears a 2-digit number
  • (ii) the number is a perfect square.
Correct Answer:
View Solution

Question 22:

(a) Evaluate: \(\dfrac{\cos 45^\circ}{\tan 30^\circ + \sin 60^\circ}\)

Correct Answer:
View Solution

OR
Question 22:

(b) Verify that \(\sin 2A = \dfrac{2\tan A}{1 + \tan^2 A}\), for \(A = 30^\circ\)

Correct Answer:
View Solution

Question 23:

(a) Solve the quadratic equation \(\sqrt{3}x^2 + 10x + 7\sqrt{3} = 0\) using the quadratic formula.

Correct Answer:
View Solution

OR
Question 23:

(b) Find the nature of roots of the equation \(4x^2 - 4a^2x + a^4 - b^4 = 0\), where \(b \ne 0\).

Correct Answer:
View Solution

Question 24:

Using prime factorisation, find the HCF of 180, 140 and 210.

Correct Answer:
View Solution

Question 25:

The perimeters of two similar triangles are 22 cm and 33 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.

Correct Answer:
View Solution

Question 26:

Given that \(\sqrt{5}\) is an irrational number, prove that \(2 + 3\sqrt{5}\) is an irrational number.

Correct Answer:
View Solution

Question 27:

(a) Find the A.P. whose third term is 16 and seventh term exceeds the fifth term by 12. Also, find the sum of first 29 terms of the A.P.

Correct Answer:
View Solution

OR
Question 27:

(b) Find the sum of first 20 terms of an A.P. whose \(n^th\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P.?

Correct Answer:
View Solution

Question 28:

Prove that \(\dfrac{\sin \theta}{1 + \cos \theta} + \dfrac{1 + \cos \theta}{\sin \theta} = 2\csc \theta\)

Correct Answer:
View Solution

Question 29:

Find the length and breadth of a rectangular park whose perimeter is 100 m and area is \(600\, m^2\).

Correct Answer:
View Solution

Let length = \(l\), breadth = \(b\)

Given: \[ 2(l + b) = 100 \Rightarrow l + b = 50 \quad (1)
Area = lb = 600 \quad (2) \]

From (1): \(b = 50 - l\)

Substitute into (2): \[ l(50 - l) = 600 \Rightarrow 50l - l^2 = 600 \Rightarrow l^2 - 50l + 600 = 0 \]

Solving: \[ l = \dfrac{50 \pm \sqrt{(-50)^2 - 4 \cdot 1 \cdot 600}}{2} = \dfrac{50 \pm \sqrt{2500 - 2400}}{2} = \dfrac{50 \pm \sqrt{100}}{2} = \dfrac{50 \pm 10}{2} \Rightarrow l = 30,\ 20;\quad b = 20,\ 30 \]


% Quicktip Quick Tip: Use perimeter to form one equation and area to form another, then solve the quadratic.


Question 30:

AB and CD are diameters of a circle with centre \(O\) and radius 7 cm. If \(\angle BOD = 30^\circ\), then find the area and perimeter of the shaded region.

Correct Answer:
View Solution

Question 31:

(a) \(\alpha, \beta\) are zeroes of the polynomial \(3x^2 - 8x + k\). Find the value of \(k\), if \(\alpha^2 + \beta^2 = \dfrac{40}{9}\)

Correct Answer:
View Solution

OR
Question 31:

(b) Find the zeroes of the polynomial \(2x^2 + 7x + 5\) and verify the relationship between its zeroes and coefficients.

Correct Answer:
View Solution

Question 32:

Find the ‘mean’ and ‘mode’ marks of the following data:

table

Correct Answer:
View Solution

Question 33:

(a) Solve the following pair of linear equations by graphical method:
\[ 2x + y = 9 \quad and \quad x - 2y = 2 \]

Correct Answer:
View Solution

OR
Question 33:

(b) Nidhi received simple interest of ₹1200 when invested ₹\(x\) at 6% p.a. and ₹\(y\) at 5% p.a. for 1 year.

Had she invested ₹\(x\) at 3% p.a. and ₹\(y\) at 8% p.a. for that year, she would have received simple interest of ₹1260.

Find the values of \(x\) and \(y\).

Correct Answer:
View Solution

Question 34:

(a) The given figure shows a circle with centre \(O\) and radius \(4\, cm\) inscribed in \(\triangle ABC\). \(BC\) touches the circle at \(D\), such that \(BD = 6\, cm\) and \(DC = 10\, cm\). Find the length of \(AE\), where \(E\) is the point of contact on \(AC\).

Correct Answer:
View Solution

Question 34:

(b) PA and PB are tangents drawn to a circle with centre \(O\). If \(\angle AOB = 120^\circ\) and \(OA = 10\, cm\), then:

  • (i) Find \(\angle OPA\)
  • (ii) Find the perimeter of AOAP.
    (iii) Find the length of chord AB.
Correct Answer:
View Solution

Question 35:

A drone is flying at a height of \(h\) metres. At an instant it observes the angle of elevation of the top of an industrial turbine as \(60^\circ\) and the angle of depression of the foot of the turbine as \(30^\circ\). If the height of the turbine is \(200\, metres\), find the value of \(h\) and the distance of the drone from the turbine.

(Use \(\sqrt{3} = 1.73\))

Correct Answer:
View Solution

Question 36:




A triangular window of a building is shown above. Its diagram represents a \(\triangle ABC\) with \(\angle A = 90^\circ\) and \(AB = AC\). Points \(P\) and \(R\) trisect \(AB\), and \(PQ \parallel RS \parallel AC\).

Based on the figure, answer the following:

  • (A) [(i)] Show that \(\triangle BPQ \sim \triangle BAC\)
  • (B) [(ii)] Prove that \(PQ = \dfrac{1}{3} AC\)
  • (C) [(iii)(a)] If \(AB = 3\, m\), find length \(BQ\) and \(BS\). Verify that \(BQ = \dfrac{1}{2} BS\)

    \textbf{OR}
  • (D) [(iii)(b)] Prove that \(BR^2 + RS^2 = \dfrac{4}{9} BC^2\)
Correct Answer:
View Solution

Question 37:

Gurveer and Arushi built a robot that can paint a path as it moves on a graph paper. Some co-ordinate of points are marked on it. It starts from (0, 0), moves to the points listed in order (in straight lines) and ends at (0, 0).



Arushi entered the points P(8, 6), Q(12, 2) and S(- 6, 6) in order. The path drawn by robot is shown in the figure.
Based on the above, answer the following:

  • (A) [(i)] Determine the distance \(OP\)
  • (B) [(ii)] \(QS\) is represented by the equation \(2x + 9y = 42\). Find the coordinates of the point where it intersects the y-axis.
  • (C) [(iii)(a)] Point \(R(4.8, y)\) divides the line segment \(OP\) in a certain ratio. Find the value of \(y\) and hence the ratio.

    \textbf{OR}
  • (D) [(iii)(b)] Using distance formula, show that \(\dfrac{PQ}{OS} = \dfrac{2}{3}\)
Correct Answer:
View Solution

Question 38:


A hemispherical bowl is packed in a cuboidal box. The bowl just fits in the box. Inner radius of the bowl is \(10\, cm\). Outer radius of the bowl is \(10.5\, cm\).
Answer the following questions:

  • (A) [(i)] Find the dimensions of the cuboidal box.
  • (B) [(ii)] Find the total outer surface area of the box.
  • (C) [(iii)(a)] Find the difference between the capacity of the bowl and the volume of the box. (Use \(\pi = 3.14\))
    \textbf{OR}
  • (D) [(iii)(b)] The inner surface of the bowl and the thickness is to be painted. Find the area to be painted.
Correct Answer:
View Solution


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