Gravitational Force: Law of Gravitation, Derivation, Principle of Superposition

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Gravitational Force is the force of attraction between all masses in the universe. For example, the attraction of the earth's mass for bodies near its surface. Newton's law of gravitation states that particles of matter in the universe attract each other with a force. This force varies directly as the product of the masses and inversely as the square of the distance between them. 

Read Also: Gravitational Potential Energy

Key Terms: Gravitation, Newton's law of gravitation, Earth gravity, Gravitation on Moon, Principle of Superposition, Vector Form


What is Gravitational Force?

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Gravitation is a study of how two masses interact, one of which is heavier and the other lighter, and force is the force that attracts all bodies towards itself in this universe. All bodies are pulled by gravity, and it is the force that moves objects towards themselves. Gravitational force is a central force that is exerted along the line joining the q of two masses, and the direction of that force depends only on their position with respect to the source mass.

\(\overrightarrow{F} (f) = f (r) r\hat{}\)

Gravitation Detailed Video Explanation

Historically, gravitation has been driven by the problem of determining the interaction between two masses and the relativistic effects associated with that interaction.

the interaction between two masses

Interaction between two masses
Check Important Notes for Value of g on Moon

History of Gravitational Theory

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Ptolemy presented the geocentric model of the solar system. For over 1500 years, Ptolemy’s geocentric model has been relied upon for astrological and astronomical predictions. Later, it failed to explain planetary motions. This lead Nicholas Copernicus to develop the heliocentric model which states that the test mass rotates in circular orbits around the source mass. Despite accurately predicting the position and motion of the planet, the model has failed to account for many aspects such as seasons. This resulted in the formulation of a model based on Kepler’s laws of planetary motion.


Newton's Law of Gravitation

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According to Newton’s law of gravitation, “every particle in the universe is attracted by every other particle with force, no matter how big the difference between them.”

  • Force is directly proportional to the product of their masses between two particles, i.e., F ∝ M1M2 …….. (equation 1)
  • Force is inversely proportional to the square of the distance between their centre, i.e., F ∝ 1/r2 ……… (equation 2)

When we combine equation 1 and equation 2, we get

\(F=G\frac{m_1m_2}{r^2}\)

  • F(r) is a variable, non-contact, and conservative force.
  • The inverse square law force f(r) is also known as the gravitational constant since it varies as a square of r. The proportionality constant (G) lies in the above equation and represents gravity.
  • A dimension formula for G is [M-1L3T-2].
  • The value for gravitational constant in SI Unit is 6.67 × 10-11 Nm2 kg-2.
  • The value in CGS Unit is 6.67×10-8 dyne cm2 g-2.

Law of Gravitation Formula

Law of Gravitation Formula

Check Also: Weightlessness


Vector Form of Newton's Law

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Gravitational forces on the two particles create an action-reaction pair when they are represented by a vector form of Newton’s law of gravitation.

According to the above figure, the two particles of mass has been placed a distance apart.

\(\overrightarrow{r_{21}} = (\overrightarrow{r_2} - \overrightarrow{r_1})\)

The direction of the vector is from M1 to M2.

The force applied on M2 by M1 is as follows:

\(\overrightarrow{F} (f) = f (r) r\hat{}\)

The negative sign indicates the attractive nature of the force.

The force on M1 and M2 is as follows:

\(\overrightarrow{F_12} = -\frac{GM_{1}M_{2}}{r^{2}_{12}}\hat{r_{12}}\)

\(\text{Since, } \hat{r_{12}} = -\hat{r_{21}}\)

\(\overrightarrow{F_{12}} = \frac{GM_{1}M_{2}}{(-r_{21})^{2}}[\hat{-r_{21}}]\)

\(\overrightarrow{F_{12}} = \frac{GM_{1}M_{2}}{(r_{21})^{2}}[\hat{r_{21}}]\)

\(- \overrightarrow{F_{21}}\)

Therefore, the applied forces are equal and opposite as per Newton's third law which also applies to gravitational forces.

Also check: Specific Gravity


Formula of Newton's Law

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Newton’s Law of Gravitation defines what gravity is, and shows how it determines how much weight we carry and how far we jump before falling.

In accordance with Newton’s laws of gravitation, every particle in the universe attracts every other particle with a force directly proportionate to their mass products and inversely proportional to their distances.

The mathematical representation is as follows.

  • F = Gravitational force between two objects (in Newton)
  • G = Universal Gravitational Constant, i.e., 6.674 × 10-11 Nm2kg-2
  • M1 = mass of one massive body (kilograms)
  • M2 = mass of another massive body (kilograms)
  • R = separation between the bodies (kilometres)

Check Important Relation between G and g


Principle of Superposition of Gravitational Force

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When a system consists of ‘n’ particles, Newton’s law of gravitation only applies to interactions between particles. If the system contains n(n – 1)/2 particles, there are n(n – 1)/2 interactions.

The principle of superposition states that the sum of each of these interactions if each act independently, can be expressed as the vector sum of those interactions.

F = F12 + F13 + F14 . . . . . . + F1n

Gravitational force F acts on a particle when the number of point masses in a system equals the vector sum of the forces exerted by the other masses on the particle.


Derivation of Newton's Law of Gravitation from Karl's Law

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An object rotates in a nearly circular orbit of radius “r” around a source mass with a constant angular velocity.

The centripetal force is as follows.

F = mrω2 = mr × (2π/T)2

Using Kepler’s Third Law, we get, T2 ∝ r3

Substituting this value in the equation of force, we get

F = 4π2mr/Kr3

Where K = 4π2/GM

The equation of Newton’s law of gravitation is as follows.

F = GMm/r2

Read Further: Earth Satellites


Things to Remember

  • Gravitational force and the law of gravitation is one of the most significant topics of the electricity chapter. Around 2-3 questions can come from this topic. The overall weightage of generators and electricity is around 10 marks. 
  • Almost all things that exist in the universe attract each other. Gravitational force is the force that one object exerts on another while attracting it towards itself.
  • The formula for the force of gravitation, F = G × [M1M2]/r2
  • The value for gravitational constant in SI Unit is 6.67 × 10-11 Nm2 kg-2.
  • The value in CGS Unit is 6.67×10-8 dyne cm2 g-2.
  • The equation of Newton’s law of gravitation is F = GMm/r2.

Previous Year Questions

  1. The time period of a satellite of earth is 5 hours. If the separation between the… [BITSAT 2019]
  2. There is a shell of mass M and density of the shell is uniform… [BITSAT 2013]
  3. If the earth shrinks such that its density becomes 8 times to the present value… [AP EAPCET]
  4. Four identical particles of equal masses 1kg made to move along the… [JEE Main 2021]
  5. Acceleration due to gravity is g on the surface of the earth… [JKCET 2004]
  6. The acceleration due to gravity at a height h above the earths surface is… [AP EAPCET]
  7. A synchronous relay satellite reflects TV signals and transmits TV programmer… [BHU UET]
  8. A body weighs 72 N on the surface of the earth. What is the gravitational force on… [NEET 2020]
  9. The dependence of acceleration due to gravity g on the distance r from the centre… [NEET 2010]
  10. The escape velocity from earth is 11.2 km/s. If a body is to be projected in… [NEET 1993]
  11. The time period of a satellite of earth is 5 hours. If the separation between… [BITSAT 2019]
  12. There is a shell of mass M and density of the shell is uniform… [BITSAT 2013]
  13. If the earth shrinks such that its density becomes 8 times to the present value… [AP EAPCET]
  14. Four identical particles of equal masses 1kg made to move along the… [JEE Main 2021]
  15. Acceleration due to gravity is g on the surface of the earth. Then the value of… [JKCET 2004]

Sample Questions

Ques: Find the force of gravity acting on an object of mass 2000 kg at the Earth’s surface? (2 marks)
Given: Mass of Earth (m1) = 5.98 × 1024kg
Mass of object (m2) = 2000kg
The radius of the Earth (r)= 6.38 × 106m
Acceleration due to gravity (g) = 9.8 m/s2
Universal constant (G) = 6.67 x 10-11 N m2 / kg2

Ans:

F = Gm1m2/r2

F = ( 6.67 x 10-11) (5.98 × 1024)(2 x 103)/(6.38 × 106)2

F = (7.978 x 1017)/ (4.07044 × 1013)

F = 1.959 x 104 or F = 19.59 N

Ques: Find the force of gravity acting on an object of mass 1000 kg at 20,000 meters above the Earth’s surface? (3 marks)
Given: Mass of Earth (m1) = 5.98 × 1024kg
Mass of object (m2) = 1000kg
The radius of the Earth (r)= 6.38 × 106m
Acceleration due to gravity (g) = 9.8 m/s2
Universal constant (G) = 6.67 x 10-11 N m2 / kg2
h = 2 x 104 m

Ans:

F = Gm1m2/(r +h)2

F = ( 6.67 x 10-11) (5.98 × 1024)(1 x 103)/(6.38 × 106 + 2 x 104 )2

F = (3.988 x 1017)/(4.058 x 1013)

F = 9,827.50

F = 0.9827 x 104

Ques: Why is the gravitational potential energy negative? (2 marks)

Ans: The gravitational potential energy is the negative of work done. So, it always had a negative value because infinity is taken as the reference point of zero potential energy.

Ques: What are two factors that determine whether a planet has an atmosphere or not? (2 marks)

Ans: Gravitational acceleration at a planet’s surface determines whether an atmosphere exists. Also, the surface temperature of a planet is an important determining factor.

Ques: Why is the body weightless at the centre of Earth? (2 marks)

Ans: The weight of a body is given by,

w=mg

g=0

w=m*0

w=0

Therefore, the weight at the centre of Earth, g is zero. So, the overall weight of a body in the centre of Earth will be zero.

Ques: Name the law of physics which form the second law of Kepler. (1 mark)

Ans: The fundamental law forms the basis of Kepler’s law of conservation of angular momentum.

Ques: In which city will the ball weigh more – Delhi or Shimla. Explain with reasons. (2 marks)

Ans: Due to the effect of gravity, the acceleration of a body decreases at higher altitudes, which is why a body at Delhi will weigh more.

Ques: Is it possible for a material medium to screen out the gravitational effect? Explain briefly. (2 marks)

Ans: No, it is not possible to screen gravitational force because it does not depend on a medium. However, you can screen the materials for electrostatic force as the force depends on the medium.

Ques: As you travel from Brazil to Greenland, will you maintain the same weight? Elaborate the reason. (2 marks)

Ans: The weight will increase as we move from Brazil to Greenland because the acceleration due to gravity will increase. Since the bulged oblate shape of the earth makes gravity stronger at poles versus less at the equator. Moreover, Greenland is closer to the North Pole as opposed to Brazil.

Ques: Why is it necessary to launch space rockets eastward? (2 marks)

Ans: Space rockets can be launched in the same direction as Earth rotates in 24 hours. This allows it to rise without the need for much fuel since Earth rotates from west to east every 24 hours.

Ques: The moon's distance from the center of the Earth was decreased by a multiple of three. How would this affect the gravitational force of the Earth on the moon? (3 marks)

Ans: The law of gravitation is written as F=Gm1m2/r2, with G being equal to 6.67∗10−11 m3/kg∗s2.

Since the radius of the two masses acting on each other is squared and is found in the denominator, a decrease in the radius by a multiple of three will cause a nine-fold increase in the gravitational force.

\(F_1= \frac{Gm_1m_2}{r^2} \rightarrow F_2=\frac{Gm_1m_2}{(\frac{1}{3}r)^2}= 9F_1\)

Ques: What is the acceleration due to gravity on a planet on which an object with a mass of 20.0kg has a weight of 270N? (3 marks)

Ans: Solve the following equation for acceleration, using the values given in the question.

F=ma

\(a= \frac{F}{m}\)

\(a= \frac{270N}{20 kg}= 13.5\frac{m}{s^2}\)

Ques: A certain planet has three times the radius of Earth and nine times the mass. How does the acceleration of gravity at the surface of this planet (ag) compare to the acceleration at the surface of Earth (g)? (3 marks)

Ans: The acceleration of gravity is given by the equation ag=GM/r2, where G is constant.

For Earth, ag=GMearth/r2earth=g.

For the new planet, 

.

So, the acceleration is the same in both cases.

Ques: What will happen to the gravitational force between two bodies if the masses of one body are doubled? (1 Mark)

Ans: If the mass of one body is doubled, force is also doubled.

Ques: How is gravitation different from gravity? (1 Mark)

Ans: Gravitation is the force of attraction between any two bodies while gravity refers to the attraction between anybody and the earth.

Ques: Why can one jump higher on the surface of the moon than on the earth? (1 Mark)

Ans: Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth.

Ques: Suppose the gravity of the earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? [NCERT Exemplar] (2 marks)

Ans: The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of the moon is due to the centripetal force provided by the gravitational force of the earth.

Ques: If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. Why? (2 marks)

Ans: The acceleration due to gravity does not depend upon the mass of the stone or body. Both the bodies fall with the same acceleration towards the surface of the earth. Thus a big stone will fall with the same acceleration as a small stone. So, both the stones will reach the ground at the same time when dropped simultaneously.

Ques: Mention any four phenomena that the universal law of gravitation was able to explain. (2 marks)

Ans: The universal law of gravitation was able to explain successfully

  • Force that binds us to the earth.
  • Motion of the moon around the earth.
  • Motion of planets around the sun.
  • Tides due to the moon and the sun.

Ques: Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent. (4 marks)

Ans: Upward motion v = u + gt1

0 = u – gt1

t1 = ug …(1)

Downward motion

v = u + gt2

v = 0 + gt2

As the body falls back to the earth with the same velocity it was thrown vertically upwards.

∴ v = u

u = 0 + gt2

t2 = u/g …(2)

From (1) and (2), we get t1 = t2

⇒ Time of ascent = Time of descent


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CBSE CLASS XII Related Questions

1.

An object of size 3.0 cm is placed 14cm in front of a concave lens of focal length 21cm. Describe the image produced by the lens. What happens if the object is moved further away from the lens?

      2.
      A closely wound solenoid of \(2000 \) turns and area of cross-section \(1.6 × 10^{-4}\  m^2\), carrying a current of \(4.0 \ A\), is suspended through its centre allowing it to turn in a horizontal plane. 
      (a) What is the magnetic moment associated with the solenoid?
      (b) What is the force and torque on the solenoid if a uniform horizontal magnetic field of \(7.5 × 10^{-2}\  T\) is set up at an angle of \(30º\) with the axis of the solenoid?

          3.
          Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the to charges is the electric potential zero? Take the potential at infinity to be zero.

              4.
              A capillary tube of radius r is dipped inside a large vessel of water. The mass of water raised above water level is M. If the radius of capillary is doubled, the mass of water inside capillary will be

                • 5M
                • 2M
                • \(\frac M4\)

                • M

                5.
                A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field ?
                1. inside the sphere
                2. just outside the sphere
                3. at a point 18 cm from the centre of the sphere?

                    6.

                    A tank is filled with water to a height of 12.5cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?

                        CBSE CLASS XII Previous Year Papers

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