CMAT 2019 Question Paper: Download CMAT Question Paper with Solutions PDF

CMAT 2019 Questions

• 1.

  A fair coin is tossed repeatedly. If tail appears on first four tosses, then the probability of head appearing on fifth toss equals.
  

  • \(\frac{5}{12}\)
    
  • \(\frac{1}{2}\)
    
  • \(\frac{5}{6}\)
    
  • \(\frac{1}{6}\)
  View Solution

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• 2.

  There are three bottles of mixture of syrup and water in the ratios \(2:3\), \(3:4\) and \(7:5\). \(10\) litres of first and \(21\) litres of second bottles are taken. How much quantity of mixtures from third bottle is to be taken so that the final syrup and water ratio of mixture from three bottles will be \(1:1\) if the final mixture from all the three bottles is added and mixed in a big container?
  

  • \(20\) litres
    
  • \(25\) litres
    
  • \(30\) litres
    
  • \(35\) litres
  View Solution

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• 3.

  In a race \(A\), \(B\) and \(C\) take part. \(A\) beats \(B\) by \(30\) meters, \(B\) beats \(C\) by \(20\) meters and \(A\) beats \(C\) by \(48\) meters.
  Given below are two statements:
  Statement I: The length of the race is \(300\) meters.
  Statement II: The speed of \(A\), \(B\) and \(C\) are in the ratio \(50:45:40\).
  In the light of the above statements, choose the correct answer from the options given below:
  

  • Both Statement I and Statement II are true
    
  • Both Statement I and Statement II are false
    
  • Statement I is true but Statement II is false
    
  • Statement I is false but Statement II is true
  View Solution

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• 4.

  Arrange the following in descending order.
  (A) \(\sqrt{3} - \sqrt{2}\)
  (B) \(\sqrt{4} - \sqrt{3}\)
  (C) \(\sqrt{5} - \sqrt{4}\)
  (D) \(\sqrt{2} - 1\)
  Choose the correct answer from the options given below:
  

  • \(A>B>C>D\)
    
  • \(D>C>B>A\)
    
  • \(D>A>B>C\)
    
  • \(A>C>B>D\)
  View Solution

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• 5.

  \(20\) girls, among whom are \(A\) and \(B\) sit down at a round table. The probability that there are \(4\) girls between \(A\) and \(B\) is
  

  • \(\frac{2}{19}\)
    
  • \(\frac{6}{19}\)
    
  • \(\frac{13}{19}\)
    
  • \(\frac{17}{19}\)
  View Solution