NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Exercise 2.3 Solutions

CBSE X Related Questions

  • 1.
    If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).


      • 2.
        If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

          • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
          • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
          • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
          • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

        • 3.
          The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

            • 0
            • 1
            • 3
            • 2

          • 4.
            Prove that :
            \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).


              • 5.
                If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                  • $x^2 + 5x - 4$
                  • $(x + 3) (-x + 8)$
                  • $a(x^2 + 5x - 24)$
                  • $x^2 - 24$

                • 6.
                  Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
                  Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

                    • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                    • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                    • Assertion (A) is true, but Reason (R) is false.
                    • Assertion (A) is false, but Reason (R) is true.

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