Resistance is an important topic in the Physics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.
This article gives you a full set of VITEEE PYQs for Resistance with explanations for effective preparation. Practice of VITEEE Physics PYQs including Resistance questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.
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VITEEE PYQs for Resistance with Solutions
1.
Which statement is correct for the given circuit?- I through $R_1 > I$ through $R_2$
- I through $R_3 > I$ through $R_2$ and $R_1$
- I through $R_2 > I$ through $R_3$ and $R_1$
- I is same in $R_1, R_2$ and $R_3$
2.
The current in the $1\Omega$ resistor shown in the circuit is- $\frac{2}{3}\,A$
- $3\,A$
- $6\,A$
- $2\,A$
3.
Three resistances of $4 \,\Omega$ each are connected as shown in figure. If the point $D$ divides the resistance into two equal halves, the resistance between point $A$ and $D$ will be- $12\, \Omega$
- $6\, \Omega$
- $3\, \Omega$
- $\frac{1}{3}\Omega$
4.
What is the resistance of a conductor if the potential difference across it is 12 V and the current flowing through it is 3 A?- 4 \( \Omega \)
- 6 \( \Omega \)
- 9 \( \Omega \)
- 12 \( \Omega \)
5.
The temperature coefficient of resistance of a wire is $0.00125/K$. At $300\,K$ its resistance is 1 $\Omega$ .The resistance of the wire will be 2 $\Omega$ at- 1154 K
- 1100 K
- 1400 K
- 1127 K
6.
The resistance of a field coil measures 50$\Omega$ at 20?C and 65$\Omega$ at 70?C. The temperature coefficient of resistance is- 0.0086/?C
- 0.0068/?C
- 0.0096/?C
- 0.0999/?C
7.
Resistances 1 $\Omega$,2 $\Omega$ and 3 $\Omega$ are connected to form a triangle.If a 1.5 V cell of negligible internal resistance is connected across the 3 $\Omega$ resistor, the current flowing through this resistor will be- 0.25 A
- 0.5 A
- 1.0 A
- 1.5 A
8.
In given circuit, all resistances are of $10 \Omega$. Current flowing through ammeter is- 3.6 A
- 1.8 A
- 2 A
- 1 A
9.
Three resistances of values 2$\Omega$, 3$\Omega$ and 6$\Omega$ are to be connected to produce an effective resistance of 4$\Omega$ . This can be done by connecting- 6$\Omega$ resistance in series with the parallel combination of 2$\Omega$ and 3$\Omega$
- 3$\Omega$resistance in series with the parallel combination of 2$\Omega$ and 6$\Omega$
- 2$\Omega$resistance in series with the parallel combination of 3$\Omega$ and 6$\Omega$
- 2$\Omega$ resistance in parallel with the parallel combination of 3$\Omega$ and 6$\Omega$
10.
The masses of three copper wires are in the ratio $2 : 3 : 5$ and their lengths are in the ratio $5 : 3 : 2$ .Then, the ratio of their electrical resistances is- 1 : 9 : 15
- 2 : 3 : 5
- 5 : 3 : 2
- 125 : 30 : 8
11.
Three resistors $1\,\Omega , 2\,\Omega$ and $3\,\Omega $ are connected to form a triangle. Across $3\,\Omega$ resistor a $3\,V$ battery is connected. The current through $3\,\Omega$ resistor is- 0.75A
- 1A
- 2A
- 1.5A
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