Magnetic Field is an important topic in the Physics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.
This article gives you a full set of VITEEE PYQs for Magnetic Field with explanations for effective preparation. Practice of VITEEE Physics PYQs including Magnetic Field questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.
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VITEEE PYQs for Magnetic Field with Solutions
1.
In a potentiometer experiment, the balancing length of a cell is $560\, cm$. When an external resistance of $10 \, \Omega$ is connected in parallel to the cell, the balancing length changes by $60 \,cm$.The internal resistance of a cell is- $1.4\, \Omega$
- $1.6\, \Omega$
- $0.12 \, \Omega$
- $1.2\, \Omega$
2.
A proton of mass $ 1.67 \times 10^{-27}\, kg$ enters a uniform magnetic field $1\, T$ of at point A shown in figure with a speed of $10^7\, ms^{-1}$ The magnetic field is directed normal to the plane of paper downwards. The proton emerges out of the magnetic field at point $C$, then the distance $AC$ and the value of angle $\theta $ will respectively be- $0.7\, m ,\, 45^{\circ}$
- $0.7\, m ,\, 90^{\circ}$
- $0.14\, m ,\, 90^{\circ}$
- $0.14\, m ,\, 45^{\circ}$
3.
If \( m \) is magnetic moment and \( B \) is the magnetic field, then the torque is given by:- \(\vec{m} \vec B \)
- \( \frac{\vec m}{\vec B} \)
- \(\vec m \times \vec B \)
- \( |\vec m||\vec B| \)
4.
Two sources of equal emf are connected to a resistance $R$. The internal resistance of these sources are $r_1$ and $r_2 (r_1 > r_2 )$. If the potential difference across the source having internal resistance $r_2$ is zero, then- $R = \frac{r_1 r_2}{r_2 - r_1}$
- $R = r_2 \left( \frac{r_1 + r_2}{r_2 - r_1} \right)$
- $R = \left( \frac{r_1 r_2}{r_2 - r_1} \right)$
- $R = r_2 - r_1$
5.
When you walk through a metal detector carrying a metal object in your pocket, it raises an alarm. This phenomenon works on:- Electromagnetic induction
- Resonance in ac circuits
- Mutual induction in ac circuits
- Interference of electromagnetic waves
6.
The work done by an uniform magnetic field, on a moving charge is- zero because $\vec{F}$ acts parallel to $\vec{v}$
- positive because $\vec{F}$ acts perpendicular to $\vec{v}$
- zero because $\vec{F}$ acts perpendicular to $\vec{v}$
- negative because $\vec{F}$ acts parallel to $\vec{v}$
7.
In the hydrogen atom, the electron is making $6.6 \times 10^{15}$ rps. If the radius of orbit is $0.53 \times 10^{-10}$ m, then magnetic field produced at the centre of the orbit is- 140T
- 12.5T
- 1.4T
- 0.14T
8.
The magnetic field at a distance r from a long wire carrying current i is 0.4 tesla. The magnetic field at a distance 2r is- 0.2 tesla
- 0.8 tesla
- 0.1 tesla
- 0.6 tesla
9.
In a Rutherford scattering experiment, when a projectile of charge \( Z_1 \) and mass \( M_1 \) approaches a target nucleus of charge \( Z_2 \) and mass \( M_2 \), the distance of closest approach is \( r_0 \). The energy of the projectile is:- Directly proportional to \( Z_1Z_2 \)
- Inversely proportional to \( Z_1 \)
- Directly proportional to mass \( M_1 \)
- Directly proportional to \( M_1 \times M_2 \)
10.
A planet in a distant solar system is 10 times more massive than Earth and its radius is 10 times smaller. Given that the escape velocity from Earth's surface is 11 km/s, the escape velocity from the planet’s surface would be:- \( 1.1 \) km/s
- \( 11 \) km/s
- \( 110 \) km/s
- \( 0.11 \) km/s
11.
The magnetic field at a point due to a current carrying conductor is directly proportional to- resistance of the conductor
- thickness of the conductor
- current flowing through the conductor
- distance from the conductor
12.
Two solenoids are given - 1st has 1 turn per unit length and 2nd has n turns per unit length. Ratio of magnetic fields at their centres is- $n : 1 $
- $1 : n $
- $1 : n^2 $
- $n^2 : 1 $
13.
The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by:- \( \vec{\mu}_L = \frac{e \vec{L}}{2m} \)
- \( \vec{\mu}_L = -\frac{e \vec{L}}{2m} \)
- \( \vec{\mu}_l = -\frac{e \vec{L}}{m} \)
- \( \vec{\mu}_l = \frac{2e \vec{L}}{m} \)
14.
A current \( I \) flows along the length of an infinitely long, straight, thin-walled pipe. Then:- the magnetic field at all points inside the pipe is the same, but not zero
- the magnetic field is zero only on the axis of the pipe
- the magnetic field is different at different points inside the pipe
- the magnetic field at any point inside the pipe is zero
15.
A proton with energy of 2 MeV enters a uniform magnetic field of2.5 T normally. The magnetic force on the proton is (Take mass of proton to be $1.6 \times 10^{-27} kg )$- $3 \times 10^{-12}N$
- $8 \times 10^{-10}N$
- $8 \times 10^{-12}N$
- $2 \times 10^{-10}N$
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