LCR Circuit is an important topic in the Physics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.
This article gives you a full set of VITEEE PYQs for LCR Circuit with explanations for effective preparation. Practice of VITEEE Physics PYQs including LCR Circuit questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.
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VITEEE PYQs for LCR Circuit with Solutions
1.
The pressure inside a tyre is 4 times that of the atmosphere. If the tyre bursts suddenly at temperature \( 300K \), what will be the new temperature?- \( 300(4)^{7/2} \)
- \( 300(4)^{2/7} \)
- \( 300(2)^{7/2} \)
- \( 300(4)^{-27} \)
2.
Which of the following figure represents the variation of \( \ln \left( \frac{R}{R_0} \right) \) with \( \ln A \) (If \( R \) is the radius of a nucleus and \( A \) is its mass number)?3.
A ball of radius \( r \) and density \( \rho \) falls freely under gravity through a distance \( h \) before entering water. The velocity of the ball does not change even on entering water. If the viscosity of water is \( \eta \), the value of \( h \) is given by:
\includegraphics[width=0.5\linewidth]{28.png}- \( \frac{2}{9} \frac{r^2 (1 - \rho)}{\eta g} \)
- \( \frac{2}{81} \frac{r^2 (\rho - 1)}{\eta g} \)
- \( \frac{2}{81} \frac{r^4 (\rho - 1)}{\eta^2 g} \)
- \( \frac{2}{9} \frac{r^4 (\rho - 1)}{\eta^2 g} \)
4.
The magnetic field of a plane electromagnetic wave is given by: \[ \vec{B} = 2 \times 10^{-8} \sin \left(0.5 \times 10^3 x + 1.5 \times 10^{11} t \right) \hat{j} \, {T}. \] {The amplitude of the electric field would be:}- \( 6 \, {V/m} \, {along x-axis} \)
- \( 3 \, {V/m} \, {along z-axis} \)
- \( 6 \, {V/m} \, {along z-axis} \)
- \( 2 \times 10^{-8} \, {V/m} \, {along z-axis} \)
5.
The self-induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10A to 25 A in 1s, the change in the energy of the inductance is:- 740J
- 437.5J
- 540J
- 637.5J
6.
A vertical electric field of magnitude \( 4.9 \times 10^5 \, {N/C} \) just prevents a water droplet of a mass \( 0.1 \, {g} \) from falling. The value of charge on the droplet will be: (Given \( g = 9.8 \, {m/s}^2 \))- \( 1.6 \times 10^{-9} \, {C} \)
- \( 2.0 \times 10^{-9} \, {C} \)
- \( 3.2 \times 10^{-9} \, {C} \)
- \( 0.5 \times 10^{-9} \, {C} \)
7.
The current in an $L-R$ circuit builds up to $\left(3 / 4^{\text {th }}\right)$ of its steady state value in $4$ seconds. The time constant of this circuit is- $\frac{1}{\ln 2} \sec$
- $\frac{2}{\ln 2} \sec$
- $\frac{3}{\ln 2} \sec$
- $\frac{4}{\ln 2} \sec$
8.
The ozone layer in the atmosphere absorbs:- Only the radio waves
- Only the visible light
- Only the \( \gamma \)-rays
- X-rays and ultraviolet rays
9.
A particle is moving with a velocity \( \vec{v} = K (y \hat{i} + x \hat{j} )\), where \( K \) is a constant. The general equation for its path is:- \( y = x^2 + {constant} \)
- \( y^2 = x + {constant} \)
- \( y^2 = x^2 + {constant} \)
- \( xy = {constant} \)
10.
Water falls from a \( 40 \) m high dam at the rate of \( 9 \times 10^4 \) kg per hour. Fifty percent of gravitational potential energy can be converted into electrical energy. The number of \( 100W \) lamps that can be lit is:- \( 25 \)
- \( 50 \)
- \( 100 \)
- \( 18 \)
11.
The equation of a wave on a string of linear mass density \( 0.04 \) kg/m is given by:
\[ y = 0.02 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{0.50} \right) \] The tension in the string is:- \( 4.0 N \)
- \( 12.5 N \)
- \( 0.5 N \)
- \( 6.25 N \)
12.
A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the gas from D to E to F will be:

- −450J
- 450J
- 900J
- 1350J
13.
A sinusoidal voltage of amplitude 25 V and frequency 50 Hz is applied to a half-wave rectifier using a P-N junction diode. No filter is used, and the load resistor is \( 1000\Omega \). The forward resistance \( R_f \) of the ideal diode is \( 10\Omega \). The percentage rectifier efficiency is:- \( 40\% \)
- \( 20\% \)
- \( 30\% \)
- \( 15\% \)








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