Equilibrium Constant is an important topic in the Chemistry section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.
This article gives you a full set of VITEEE PYQs for Equilibrium Constant with explanations for effective preparation. Practice of VITEEE Chemistry PYQs including Equilibrium Constant questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.
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VITEEE PYQs for Equilibrium Constant with Solutions
1.
Values of dissociation constant \( K_a \) are given as follows:

Correct order of increasing base strength of the conjugate bases \( {CN}^-, {F}^- \) and \( {NO}_2^- \) is:
- \( {F}^-<{CN}^-<{NO}_2^- \)
- \( {NO}_2^-<{CN}^-<{F}^- \)
- \( {F}^-<{NO}_2^-<{CN}^- \)
- \( {NO}_2^-<{F}^-<{CN}^- \)
2.
The partial pressure of \( CH_3OH(g) \), \( CO(g) \), and \( H_2(g) \) in an equilibrium mixture for the reaction:
\[ CO(g) + 2H_2(g) \rightleftharpoons CH_3OH(g) \]are 2.0, 1.0, and 0.1 atm respectively at \( 427^\circ C \). The value of \( K_p \) for the decomposition of \( CH_3OH \) to \( CO \) and \( H_2 \) is:
- \( 10^2 \, {atm} \)
- \( 2 \times 10^2 \, {atm}^{-1} \)
- \( 50 \, {atm}^2 \)
- \( 5 \times 10^{-3} \, {atm}^2 \)
3.
The correct order of thermal stability of hydroxides is:- \( {Ba(OH)}_2 < {Ca(OH)}_2 < {Sr(OH)}_2 < {Mg(OH)}_2 \)
- \( {Mg(OH)}_2 < {Sr(OH)}_2 < {Ca(OH)}_2 < {Ba(OH)}_2 \)
- \( {Mg(OH)}_2 < {Ca(OH)}_2 < {Sr(OH)}_2 < {Ba(OH)}_2 \)
- \( {Ba(OH)}_2 < {Sr(OH)}_2 < {Ca(OH)}_2 < {Mg(OH)}_2 \)
4.
Which of the following order is not correct for the ionic radii of the given species: \( {O}^{2-} \), \( {S}^{2-} \), \( {N}^{3-} \), \( {P}^{3-} \)?- \( {O}^{2-} < {N}^{3-} < {S}^{2-} < {P}^{3-} \)
- \( {O}^{2-} < {P}^{3-} < {N}^{3-} < {S}^{2-} \)
- \( {N}^{3-} < {O}^{2-} < {P}^{3-} < {S}^{2-} \)
- \( {N}^{3-} < {S}^{2-} < {O}^{2-} < {P}^{3-} \)
5.
The geometry and magnetic behaviour of the complex \([Ni(CO)_4]\) are:- Square planar geometry and diamagnetic
- Tetrahedral geometry and diamagnetic
- Tetrahedral geometry and paramagnetic
- Square planar geometry and paramagnetic
6.
For the reaction, $2 A(g)+B_{2}(g) \rightleftharpoons 2 A B_{2}(g)$ the equilibrium constant, $K_{p}$ at $300\, K$ is $16.0$. The value of $K_{p}$ for $A B_{2}(g) \rightleftharpoons A(g)+1 / 2 B_{2}(g)$ is- 8
- 0.25
- 0.125
- 32
7.
The major product of the following reaction is:

8.
Given that the equilibrium constant for the reaction $ {2SO2(g) + O2(g) <=> 2SO3(g)}$ has a value of278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? $ {SO3(g) <=> SO2(g) + \frac{1}{2} O2(g)}$- $1.8 \times 10^{-3}$
- $3.6 \times 10^{-3}$
- $6.0 \times 10^{-2}$
- $1.3 \times 10^{-5}$
9.
The reaction, $2 A(g)+B(g) \rightleftharpoons 3 C(g)+D(g)$ is begun with the concentrations of $A$ and $B$ both at an initial value of $1.00\, M .$ When equilibrium is reached, the concentration of $D$ is measured and found to be $0.25\, M$. The value for the equilibrium constant for this reaction is given by the expression- $\left[(0.75)^{3}(0.25)\right] \div\left[(1.00)^{2}(1.00)\right]$
- $\left[(0.75)^{3}(0.25)\right] \div\left[(0.50)^{2}(0.75)\right]$
- $\left[(0.75)^{3}(0.25)\right] \div\left[(0.50)^{2}(0.25)\right]$
- $\left[(0.75)^{3}(0.25)\right] \div\left[(0.75)^{2}(0.25)\right]$
10.
For which one of the following systems at equilibrium, at constant temperature will the doubling of die volume cause a shift to the right?- $\ce{H2(g) + Cl2(g) <=> HCl(g) }$
- $\ce{2CO(g) + O2(g) <=> 2CO2(g) }$
- $\ce{N2(g) + 3H2(g) <=> NH2(g) }$
- $\ce{PCl5(g) <=> PCl3(g)+Cl2(g) }$
11.
The value of \(K_c\) for the reaction : \({A + 3B\rightleftharpoons2C}\) at \(400^\circ C\) is \(0.5.\) Calculate the value of \(K_P\)\(1.64 \times 10^{-4}\)
- \(1.64 \times 10^{-6}\)
- \(1.64 \times 10^{-5}\)
- \(1.64 \times 10^{-3}\)
12.
Consider the water gas equilibrium reaction, $C ( s )+ H _{2} O ( g ) \rightleftharpoons CO ( g )+ H _{2}( g )$ Which of the following statements is true at equilibrium?- If the amount of $C(s)$ is increased, less water would be formed
- If the amount of $C(s)$ is increased, more $CO$ and $H_2$ would be formed
- If the pressure on the system is increased by halving the volume, more water would be formed
- If the pressure on the system is increased by halving the volume, more $CO$ and $H_2$ would be formed








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