Current electricity is an important topic in the Physics section in VITEEE exam. Practising this topic will increase your score overall and make your conceptual grip on VITEEE exam stronger.
This article gives you a full set of VITEEE PYQs for Current electricity with explanations for effective preparation. Practice of VITEEE Physics PYQs including Current electricity questions regularly will improve accuracy, speed, and confidence in the VITEEE 2026 exam.
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VITEEE PYQs for Current electricity with Solutions
1.
Potential energy as a function of \(r\) is given by \( U = \frac{A}{r^{10}} - \frac{B}{r^5} \), where \(r\) is the interatomic distance, \(A\) and \(B\) are positive constants. The equilibrium distance between the two atoms will be:- \( \left( \frac{A}{B} \right)^{\frac{1}{5}} \)
- \( \left( \frac{B}{A} \right)^{\frac{1}{5}} \)
- \( \left( \frac{2A}{B} \right)^{\frac{1}{5}} \)
\( \left( \frac{B}{2A} \right)^{\frac{1}{5}} \)
2.
For the circuit shown in the figure, the current through the inductor is \( 0.9A \) while the current through the condenser is \( 0.4A \). Then:

- Current drawn from source \( I = 1.13A \)
- \( \omega = \frac{1}{1.5LC} \)
- \( I = 0.5A \)
- \( I = 0.6A \)
3.
Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:- 2 : 3
- 16 : 81
- 25 : 169
- 25 : 1
4.
Angular momentum of the particle rotating with a central force is constant due to- constant torque
- constant force
- constant linear momentum
- zero torque
5.
What will be the maximum speed of a car on a road turn of radius 30m if the coefficient of friction between the tyres and the road is 0.4? (Take \( g = 9.8 { m/s}^2 \))- \( 10.84 { m/s} \)
- \( 9.84 { m/s} \)
- \( 8.84 { m/s} \)
- \( 6.84 { m/s} \)
6.
A stone of mass \( m \), tied to a string is being whirled in a vertical circle with a uniform speed. The tension in the string is:- the same throughout the motion
- minimum at the highest position of the circular path
- minimum at the lowest position of the circular path
- minimum when the rope is in the horizontal position
7.
The P-V diagram of a diatomic ideal gas system undergoing a cyclic process is shown in the figure. The work done during the adiabatic process \( CD \) is (Use \( \gamma = 1.4 \)):

- \( -500J \)
- \( 200J \)
- \( -400J \)
- \( 400J \)
8.
The recoil speed of a hydrogen atom after it goes from \( n = 5 \) state to \( n = 1 \) state will be:- 4.34 m/s
- 2.19 m/s
- 4.17 m/s
- 3.25 m/s
9.
A and B are two metals with threshold frequencies \( 1.8 \times 10^{14} \) Hz and \( 2.2 \times 10^{14} \) Hz. Two identical photons of energy \( 0.825 \) eV each are incident on them. Then photoelectrons are emitted in (Take \( h = 6.6 \times 10^{-34} \) Js):- B alone
- A alone
- Neither A nor B
- Both A and B
10.
A car moves at a speed of \( 20 { m/s} \) on a banked track and describes an arc of a circle of radius \( 40\sqrt{3} \) m. The angle of banking is: (Take \( g = 10 { m/s}^2 \))- \( 25^\circ \)
- \( 60^\circ \)
- \( 45^\circ \)
- \( 30^\circ \)
11.
The escape velocity of a body depends upon mass as:- \( m^0 \)
- \( m^1 \)
- \( m^2 \)
- \( m^3 \)
12.
If \( V_1 \) is the velocity of a body projected from point A and \( V_2 \) is the velocity of a body projected from point B, which is vertically below the highest point C, and if both the bodies collide, then:

- \( V_1 = \frac{1}{2} V_2 \)
- \( V_2 = \frac{1}{2} V_1 \)
- \( V_1 = V_2 \)
- \( V_1 = 3V_2 \)
13.
The resistance of $0.01\, N$ solution of an electrolyte was found to be $220\, ohm$ at $298\, K$ using a conductivity cell with a cell constant of $0.88\,cm^{-1}$. The value of equivalent conductance of solution is -- $400\, mho\, cm^2 \,g \,eq^{-1}$
- $295\, mho\, cm^2 \,g \,eq^{-1}$
- $419\, mho\, cm^2 \,g \,eq^{-1}$
- $425\, mho\, cm^2 \,g \,eq^{-1}$
14.
Zener breakdown occurs in a p − n junction having p and n both:- lightly doped and have wide depletion layer
- heavily doped and have narrow depletion layer
- lightly doped and have narrow depletion layer
- heavily doped and have wide depletion layer
15.
A person aiming to reach the exactly opposite point on the bank of a stream is swimming with speed of \( 0.5 \) m/s at an angle of \( 120^\circ \) with the direction of flow of water. The speed of water in the stream is:- \( 1 \) m/s
- \( 0.5 \) m/s
- \( 0.25 \) m/s
- \( 0.433 \) m/s




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