NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.1 Solutions are based on different types of quadrilaterals, and their properties.

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Check out NCERT Solutions for Class 9 Maths Chapter 8 Exercise 8.1 Solutions

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

Also check other Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.2 Solutions

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Important Chapter Related Topics
Quadrilaterals	Cyclic quadrilateral	Quadrilateral angle sum property
Perimeter of a parallelogram	Area of a Rectangle	Area of a Square

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CBSE X Related Questions

1.
In the given figure, \( \triangle AHK \sim \triangle ABC \). If \( AK = 10 \text{ cm} \), \( BC = 3.5 \text{ cm} \) and \( HK = 7 \text{ cm} \), find the length of \( AC \).
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2.
Through the mid-point Q of side CD of a parallelogram ABCD, the line AR is drawn which intersects BD at P and produced BC at R. Prove that \(AQ = QR\).
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3.
In the adjoining figure, the slant height of the conical part is :
- 4 cm
- 7 cm
- 5 cm
- 25 cm
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4.
In the given figure, \(TP\) and \(TQ\) are tangents to a circle with centre \(M\), touching another circle with centre \(N\) at \(A\) and \(B\) respectively. It is given that \(MQ = 13 \text{ cm}\), \(NB = 8 \text{ cm}\), \(BQ = 35 \text{ cm}\) and \(TP = 80 \text{ cm}\).
(i) Name the quadrilateral MQBN. (1)
(ii) Is MN parallel to PA? Justify your answer. (1)
(iii) Find length TB. (1)
(iv) Find length MN. (2)
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5.
Evaluate : \(\frac{3 \cos^2 30^{\circ} - 6 \csc^2 30^{\circ}}{\tan^2 60^{\circ}}\).
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6.
The line segment joining the points \(P(-4, -2)\) and \(Q(10, 4)\) is divided by y-axis in the ratio
- \(2:5\)
- \(1:2\)
- \(2:1\)
- \(5:2\)
View Solution

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