NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.2 Solutions are based on the Mid-point Theorem.

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

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CBSE X Related Questions

  • 1.
    The HCF of 960 and 432 is :

      • 48
      • 54
      • 72
      • 36

    • 2.
      In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

        • \( 130^\circ \)
        • \( 50^\circ \)
        • \( 120^\circ \)
        • \( 90^\circ \)

      • 3.
        Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)


          • 4.
            If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


              • 5.
                D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


                  • 6.
                    A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

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