NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.2 Solutions are based on the Mid-point Theorem.

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

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CBSE X Related Questions

  • 1.
    A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))


      • 2.
        Prove that :
        \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).


          • 3.
            The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

              • $q - 9p$
              • $p - 9q$
              • $p + 9q$
              • $2p + 9q$

            • 4.
              \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                • \(\frac{21}{4} \text{ cm}\)
                • \(\frac{28}{3} \text{ cm}\)
                • \(\frac{12}{7} \text{ cm}\)
                • \(5.5 \text{ cm}\)

              • 5.
                If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                  • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                  • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

                • 6.
                  PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.

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