NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Collegedunia Team logo

Collegedunia Team Content Curator

Content Curator

NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles Exercise 6.2 Solutions are based on alternate interior angles, alternate exterior angles, corresponding angles, Interior angles on the same side of the transversal and more.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 6 Lines and Angles

Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles 

Also check other Exercise Solutions of Class 9 Maths Chapter 6 Lines and Angles

Also Check:

Also check:

CBSE X Related Questions

  • 1.

    The following data shows the number of family members living in different bungalows of a locality:
     

    Number of Members0−22−44−66−88−10Total
    Number of Bungalows10p60q5120


    If the median number of members is found to be 5, find the values of p and q.


      • 2.

        In the adjoining figure, TP and TQ are tangents drawn to a circle with centre O. If $\angle OPQ = 15^\circ$ and $\angle PTQ = \theta$, then find the value of $\sin 2\theta$.


          • 3.

            Find the mean and mode of the following data:

            Class15--2020--2525--3030--3535--4040--45
            Frequency1210151175


              • 4.
                Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]


                  • 5.
                    The given figure shows a circle with centre O and radius 4 cm circumscribed by \(\triangle ABC\). BC touches the circle at D such that BD = 6 cm, DC = 10 cm. Find the length of AE.
                     BC touches the circle at D such that BD = 6 cm


                      • 6.

                        In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

                          Comments


                          No Comments To Show