NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.3 Solutions are based on the concept of Surface area of a right circular cone.

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Check out NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.3 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 13 Surface Areas and Volumes

Exercise Solutions of Class 9 Maths Chapter 13 Surface Areas and Volumes

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CBSE X Related Questions

  • 1.
    If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

      • $x^2 + 5x - 4$
      • $(x + 3) (-x + 8)$
      • $a(x^2 + 5x - 24)$
      • $x^2 - 24$

    • 2.
      If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

        • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
        • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

      • 3.
        \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

          • \(\frac{21}{4} \text{ cm}\)
          • \(\frac{28}{3} \text{ cm}\)
          • \(\frac{12}{7} \text{ cm}\)
          • \(5.5 \text{ cm}\)

        • 4.
          The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

            • $q - 9p$
            • $p - 9q$
            • $p + 9q$
            • $2p + 9q$

          • 5.
            The natural number 1 is :

              • a prime number.
              • a composite number.
              • prime as well as composite.
              • neither prime nor composite.

            • 6.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

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