NCERT Solutions for Class 11 Maths Chapter 10 Exercise 10.3

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Class 11 Maths NCERT Solutions Chapter 10 Straight Lines Exercise 10.3 is based on forms of Equation of a Line. Following concepts are covered under this topic:

  • General Equation of a Line
  • Distance of a Point From a Line

Download PDF NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines Exercise 10.3

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CBSE CLASS XII Related Questions

  • 1.
    Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]


      • 2.
        Find:

        If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

          • \(0\)
          • \(-2\)
          • \(-1\)
          • \(2\)

        • 3.
          If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


            • 4.
              Find:

              The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                • \(-\frac{\pi}{2}\)
                • \(-\frac{\pi}{4}\)
                • \(\frac{\pi}{4}\)
                • \(\frac{\pi}{2}\)

              • 5.
                Find a point on the line \( \frac{x - 2}{3} = \frac{1 - y}{2} = \frac{z - 3}{2} \) at a distance of \( \sqrt{2} \) units from the point \( (1, 2, 3) \).


                  • 6.
                    Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).

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