NCERT Solutions for Class 11 Maths Chapter 10 Exercise 10.2

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Class 11 Maths NCERT Solutions Chapter 10 Straight Lines Exercise 10.2 is based on forms of Equation of a Line. Following concepts are covered under this topic:

Horizontal and vertical lines
Point-slope form
Two-point form
Slope-intercept form

Download PDF NCERT Solutions for Class 11 Maths Chapter 10 Straight Lines Exercise 10.2

Check out the solutions of Class 11 Maths NCERT solutions Chapter 10 Straight Lines Exercise 10.2

Read More: NCERT Solutions For Class 11 Maths Chapter 10 Straight Lines

Also check other Exercise Solutions of Class 11 Maths Chapter 10 Straight Lines

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Chapter Related Topics
Horizontal and vertical lines	Analytical Geometry	Intercept
Slope Formula	Slope Intercept Form Formula	Point Gradient Formula
Perpendicular Line Formula	Point Slope Form Formula	Different Forms of Equation of Line

Also check:

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Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
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CBSE CLASS XII Related Questions

1.
Find:

The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]
View Solution
2.
An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.
Based on the above information, answer the following questions :
3.
Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]
View Solution
4.
Find:

The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:
- \(-\frac{\pi}{2}\)
- \(-\frac{\pi}{4}\)
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{2}\)
View Solution
5.
Find:
Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).
- \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
View Solution
6.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).
View Solution

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NCERT Solutions For Class 11 Maths Chapter 10: Straight Lines

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