KEAM 2020 Question Papers: Download Previous Year Question Paper with Answer Key PDFs

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Uddipana Choudhury

Content Writer | Updated 3+ months ago

KEAM 2020 question paper is available for download. The overall question paper was of moderate difficulty level, with few questions being lengthy. Both papers had a total of 120 questions which were of class 11th and 12th levels. As per test takers, Physics was the toughest subject in the exam, whereas both Chemistry and Mathematics were comparatively easier.

KEAM 2020 Question Papers with Solution PDF

Paper/ Subject Exam Date Shift/ Slot Question Paper with Solution
Physics & Chemistry July 16, 2020 - Check Here
Mathematics July 16, 2020 Afternoon Check Here

*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.

KEAM 2020 Questions

  • 1.
    Solve for \( a \) and \( b \) given the equations: \[ \sin x + \sin y = a, \quad \cos x + \cos y = b, \quad x + y = \frac{2\pi}{3} \]

      • \( a = \frac{1}{2}, \quad b = \frac{1}{2} \)
      • \( a = \frac{1}{2}, \quad b = \frac{1}{\sqrt{2}} \)
      • \( a = 0, \quad b = 1 \)
      • \( a = 1, \quad b = 1 \)

    • 2.
      If \( A \) is a \( 3 \times 3 \) matrix and \( |B| = 3|A| \) and \( |A| = 5 \), then find \( \left| \frac{\text{adj} B}{|A|} \right| \).

        • 3
        • 9
        • 1
        • 5

      • 3.
        An unbiased die is tossed until a sum \( S \) is obtained. If \( X \) denotes the number of times tossed, find the ratio \( \frac{P(X = 2)}{P(X = 5)} \).

          • \( \frac{1}{4} \)
          • \( \frac{1}{2} \)
          • \( \frac{1}{3} \)
          • \( \frac{1}{5} \)

        • 4.
          If $ f(x) = \log 3 - \sin x $, $ y = f(f(x)) $, find $ y(0) $.

            • \( 2 \)
            • \( 0 \)
            • \( 1 \)
            • \( \log 3 \)

          • 5.
            The inward electric flux through a closed surface is \( 6 \times 10^{-5} \) and the outward flux is \( 3 \times 10^{-5} \). Then the total charge enclosed is?

              • \( 9 \times 10^{-5} \, \text{C} \)
              • \( 3 \times 10^{-5} \, \text{C} \)
              • \( 6 \times 10^{-5} \, \text{C} \)
              • \( 0 \, \text{C} \)

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