Jasmine Grover Content Strategy Manager
Content Strategy Manager
Force is the power that makes things move, stop, change shape, or do anything different. It's like a helper that tells things how to behave when you give them a little push or pull.
- Imagine one playing with a toy car. When one pushes the car, it starts moving. What's making it move? That's force!
- Force is like a little invisible push or pull that can make things change their motion.
- For example, if one wants to kick a ball, your leg applies force to the ball.
- If one wants to stop a rolling ball, you use your hand to apply force in the opposite direction.
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Key Terms: Acceleration, Mass, Momentum, Velocity, inertia, centrifugal force, Centripetal force
What is Force?
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Force is defined as an interaction that causes an object to accelerate, change its velocity, or deform.
- It is a vector quantity, which means it has both magnitude (how strong the force is) and direction (which way the force is applied).
- Force is typically measured in units of newtons (N) in the International System of Units (SI).
- It can be the result of various physical interactions, such as contact between objects, gravitational attraction, and electromagnetic fields.

Force
Read More: Force of Attraction Formula
Force Formula
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Force is a vector quantity, which means it has a magnitude as well as a direction. According to Newton's second law, force is defined as the "product of mass and acceleration."
Force = Mass × Acceleration

Force Formula
Example- A car with a mass of 1200 kg is accelerating at a rate of 5 m/s2. Calculate the force applied to the car.
Solution. Mass= 1200 Kg: Acceleration = 5 m/s2
Force = m x a
= 1200 x 5
= 6000 Newton
Force Formula with Velocity
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The acceleration or velocity change formula is derived from the force formula.
Acceleration = Velocity × Time
Therefore force formula can be written as
F = mv/t
Example- A baseball with a mass of 0.145 kg is pitched with an initial velocity of 35 m/s. If the ball experiences a constant deceleration of 8 m/s2 due to air resistance, what is the net force acting on the baseball during its deceleration?
Solution. Mass of the baseball (m) = 0.145 kgInitial velocity (u) = 35 m/sDeceleration (a) = – 8 m/s2
v2 = u2 + 2as
v2 = (35 m/s)2 + 2 × (-8 m/s2) × 1
v2 = 1225 m2/s2 – 16 m2/s2
v2 = 1209 m2/s2
v ≈ 34.77 m/s
Δv = v – u
Δv = 34.77 m/s – 35 m/s
Δv ≈ – 0.23 m/s
Force (F) = Mass (m) × Acceleration (a)
Δt = Δv / a
Δt = (-0.23 m/s) / (-8 m/s2)
Δt ≈ 0.02875 s
F = m × a
F = 0.145 kg x – 8 m/s2
F ≈ -1.16 N
Force Formula in Terms of Momentum
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The formula for inertia is p = mv which is also known as momentum.
So, Force can be defined as the speed at which momentum changes.
F = p/t = dp/dt
Example- A tennis ball with a mass of 0.06 kg is initially at rest. A player hits the ball, giving it a constant force that results in a change in velocity from 0 m/s to 20 m/s in a time of 0.02 seconds. Calculate the force applied to the tennis ball during the hit.
Solution- Mass of the tennis ball (m) = 0.06 kg Initial velocity (u) = 0 m/s, Final velocity (v) = 20 m/s, Time (Δt) = 0.02 seconds
Initial momentum (pinitial) = mass × initial velocity = 0.06 kg × 0 m/s = 0 kg m/s
Final momentum (pfinal) = mass × final velocity = 0.06 kg × 20 m/s = 1.2 kg m/s
Now, let's calculate the change in momentum (Δp):
Δp = pfinal - pinitial = 1.2 kg m/s - 0 kg m/s = 1.2 kg m/s
Force (F) = Change in Momentum (Δp) / Time (Δt)
F = 1.2 kg m/s / 0.02 s
F = 60 N
Read More: Gravity Waves
Unit of Force Formula
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Force is defined or quantified as the product of mass and acceleration, according to Newton's second law of motion.
SI Unit
The unit of force in the International System of Units (SI) is Newton, abbreviated as "N." The formula for force in SI units is:
F = m ⋅ a
where:
- F represents the force in newtons (N)
- m represents the mass of an object in kilograms (kg)
- a represents the acceleration of the object in metres per second squared (m/s2)
This formula states that force is equal to the product of an object's mass and its acceleration. In simpler terms, force is what causes an object to accelerate, decelerate, or change its state of motion.
FPS System
In the FPS (Foot-Pound-Second) system of units, the unit of force is the pound-force, often abbreviated as lbf or lbF. This is the force required to accelerate a one-pound mass by one foot per second squared.
In equation form:
1 pound-force (lbf) = 1 pound-mass (lb) × 1 foot per second squared (ft/s2)
Please note that the FPS system is not as commonly used as other systems like the SI (International System of Units) or the CGS (Centimeter-Gram-Second) system, and its usage has been largely supplanted by these other systems in scientific and engineering contexts.
Derivation of Force Formula
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Newton's second law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, it is expressed as:
F = m * a
Where:
- F is the force applied to the object (in newtons)
- m is the mass of the object (in kilograms)
- a is the acceleration of the object (in metres per second squared)
Now, let's derive this formula using basic principles.
Start with the definition of force:
Force (F) is the rate of change of momentum.
F = Δp / Δt
Momentum (p) is the product of mass and velocity:
p = m * v
Substitute momentum into the force definition:
F = Δ(m * v) / Δt
Apply the product rule of differentiation to the momentum:
F = m * Δv / Δt + v * Δm / Δt
The change in velocity (Δv / Δt) is the definition of acceleration (a):
F = m * a + v * Δm / Δt
In many cases, the change in mass (Δm / Δt) is negligible compared to the mass itself, especially for non-relativistic speeds. So, we can assume that the mass remains constant, and the change in mass term can be ignored:
F = m * a
This is Newton's second law of motion, which relates force, mass, and acceleration. This law forms the basis for understanding and calculating forces in various physical scenarios.
Also Read:
Things to Remember
- Force is a vector quantity causing acceleration or deformation.
- Newton's second law: Force (F) = mass (m) × acceleration (a).
- Units: SI (Newton, N), CGS (dyne, dyn), FPS (pound-force, lbf).
- Gravity's force: F = m × g (acceleration due to gravity).
- Contact vs. non-contact forces (e.g., friction vs. gravity).
- Force diagrams show forces on an object.
- Net force accelerates; equilibrium has zero net force.
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Sample Questions
Ques. A car with a mass of 1200 kg accelerates from rest to a speed of 25 m/s in 10 seconds. Calculate the force applied to the car during this acceleration. (3 marks)
Ans. Given:
- Mass of the car (m) = 1200 kg
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 25 m/s
- Time (t) = 10 s
Using the kinematic equation:v=u+at
Solving for acceleration (a):
a = v – u/t
25 – 0 / 10
= 2.5m/s2
Now, using Newton's second law (F = m * a) = 1200 kg x 2.5 m/s2 = 3000
The force applied during car acceleration is 3000 Newton
Ques. A box with a mass of 10 kg is pushed with a force of 20 newtons. What is the acceleration of the box? (2 marks)
Ans. Given:
- Mass of the box (m) = 10 kg
- Force applied (F) = 20 N
Using Newton's second law (F = m * a), solve for acceleration (a):
a = F/m
= 20/10 = 2m/s2
Ques. What is the weight of an object with a mass of 5 kg? ( Use g= 9.81m/s2) (2 marks)
Ans. Given
- Mass of the object (m) = 5 kg
- Acceleration due to gravity (g) = 9.81m/s2
W = m × g
= 5 × 9.81m/s2 = 49.05N
Ques. A skateboard with a mass of 2 kg is initially moving at a velocity of 4 m/s. A constant force is applied in the direction of motion, causing the skateboard's velocity to increase to 8 m/s over 3 seconds. Calculate the magnitude of the applied force. (3 marks)
Ans. Mass of the skateboard (m) = 2 kgInitial velocity (u) = 4 m/sFinal velocity (v) = 8 m/sTime (Δt) = 3 seconds
Change in Velocity = 8 m/s - 4 m/s = 4 m/s
Acceleration (a) = 4 m/s / 3 s ≈ 1.33 m/s2
Force (F) = Mass (m) × Acceleration (a)
Force (F) = 2 kg × 1.33 m/s2 ≈ 2.66 N
Ques. A rocket of mass 500 kg is launched with an initial velocity of 100 m/s. The rocket's engine provides a constant force that accelerates the rocket at a rate of 20 m/s2. Calculate the force exerted by the rocket's engine. (5 marks)
Ans. Mass of the rocket (m) = 500 kgInitial velocity (u) = 100 m/sAcceleration (a) = 20 m/s2
v2 = u2 + 2asv2 = 0 + 2 × 20 m/s2 x sv2 = 40s
v = u + at100 m/s + 20 m/s2 × Δt = v100 m/s + 20 m/s2 x Δt = √(40s)
Solving for Δt:
Δt = (√(40s) - 100 m/s) / 20 m/s2
Δt ≈ 1.5 seconds
Δv = a × ΔtΔv = 20 m/s2 × 1.5 sΔv = 30 m/s
Finally, let's calculate the force exerted by the rocket's engine using Newton's second law:
Force (F) = Mass (m) × Acceleration (a)
Force (F) = 500 kg × 20 m/s2
Force (F) = 10000 N
Ques. A car with a mass of 1200 kg accelerates from rest to a velocity of 25 m/s in 10 seconds. Calculate the average force exerted on the car during this acceleration. (3 marks)
Ans. Mass of the car (m) = 1200 kgInitial velocity (u) = 0 m/s Final velocity (v) = 25 m/sTime (Δt) = 10 seconds
Using the formula for acceleration: Acceleration (a) = (Change in Velocity) / Time
Acceleration (a) = (25 m/s - 0 m/s) / 10 s = 2.5 m/s2
Now, use Newton's second law to calculate the force:
Force (F) = Mass (m) x Acceleration (a)Force (F) = 1200 kg x 2.5 m/s2 = 3000 N
Ques. A book of mass 2 kg is pushed with a constant force, causing it to accelerate from 5 m/s to 15 m/s in 4 seconds. Determine the magnitude of the applied force. (5 marks)
Ans. Mass of the book (m) = 2 kgInitial velocity (u) = 5 m/s Final velocity (v) = 15 m/sTime (Δt) = 4 seconds
Change in Velocity (Δv) = Final Velocity (v) - Initial Velocity (u)
Δv = 15 m/s - 5 m/s = 10 m/s
Calculate the acceleration: Acceleration (a) = (Change in Velocity) / Time
Acceleration (a) = 10 m/s / 4 s = 2.5 m/s2
Use Newton's second law to calculate the force:
Force (F) = Mass (m) × Acceleration (a)
Force (F) = 2 kg × 2.5 m/s2 = 5 N
Ques. A bicycle of mass 15 kg is initially moving at a velocity of 8 m/s. A constant force is applied in the opposite direction of motion, causing the bicycle's velocity to decrease to 3 m/s over 4 seconds. Calculate the magnitude of the force applied to the bicycle. (5 marks)
Ans. Initial momentum (pinitial) = Mass (m) × Initial Velocity (u)
pinitial = 15 kg × 8 m/s = 120 kg m/s
Final momentum (pfinal) = Mass (m) × Final Velocity (v)
pfinal = 15 kg × 3 m/s = 45 kg m/s
Now, calculate the change in momentum (Δp):
Change in Momentum (Δp) = Final Momentum (pfinal ) - Initial Momentum (pinitial)
Δp = 45 kg m/s - 120 kg m/s = – 75 kg m/s
Now there is a change in momentum. Use the formula for force in terms of momentum and time:
Force (F) = Change in Momentum (Δp) / Time (Δt)
F = – 75 kg m/s / 4 s
F = – 18.75 N
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