The Class 11 Physics NCERT Solutions Chapter 2 Motion in a Straight Line will help students prepare for Boards, JEE Main, JEE Advanced, NEET, CUET and NDA in 2026-27. Every back-exercise question is solved with full working, so students can follow each graph reading, velocity calculation, and kinematic-equation step one line at a time.
This chapter builds the base of kinematics that Chapter 3 Motion in a Plane then extends to two dimensions.
- CBSE Weightage: 5 to 7 marks, usually one short answer on graphs plus one numerical on the kinematic equations.
- Questions solved: all Exercise 2.1 onward, covering displacement, velocity, acceleration, motion graphs, and relative velocity.
- Key formulas: the three equations of uniformly accelerated motion, average velocity, and relative velocity in one dimension.
Each solution in this Class 11 Physics NCERT Solutions Chapter 2 Motion in a Straight Line compilation is curated by subject experts, based on the 2026-27 NCERT textbook, and refined against the last five years of CBSE Board, JEE Main and NEET papers.
Distance, Displacement and Path Length in Straight-Line Motion
Kinematics starts by fixing what we mean by "how far" an object has moved. The chapter draws a sharp line between path length (the total ground covered) and displacement (the straight change in position). Getting this pair right is the first step in almost every numerical here.
| Quantity | Type | What it measures |
|---|---|---|
| Path length (distance) | Scalar | Total length of the path covered, always positive |
| Displacement | Vector | Change in position, can be positive, negative or zero |
| Position | Vector (1D) | Location on the chosen axis, measured from the origin |
The NCERT questions here ask students to compare these two quantities for a moving object. Displacement can be zero even when the path length is large, such as when an object returns to its start. The solved answers show the sign of displacement on its own line, so students never confuse the two. This single habit fixes the most common error in the opening exercises.
Average Velocity and Average Speed in the Motion Chapter
Once position is defined, the chapter measures how fast it changes. Average velocity uses displacement, while average speed uses path length. The two are equal only when the motion never reverses direction, and the NCERT solutions test that idea directly.
- Average velocity: displacement divided by the time taken, v̄ = Δx/Δt. It is a vector and carries a sign.
- Average speed: total path length divided by total time. It is a scalar and is never negative.
- When they match: for motion in one direction with no turning back, average speed equals the size of average velocity.
Numericals such as Exercise 2.1 give a trip with a return leg and ask for both quantities. Read the direction of each leg before you add anything, because displacement can cancel while path length keeps growing. The step-by-step answers set out each leg separately, so the sign work is easy to follow.
Instantaneous Velocity and Instantaneous Speed
Instantaneous velocity is the velocity at a single moment, found as the limit of average velocity over a shrinking time interval. On a position-time graph it is the slope of the tangent at that instant. The chapter uses this idea to move from average to point-by-point motion.
| Idea | Definition | Graph meaning |
|---|---|---|
| Instantaneous velocity | v = dx/dt | Slope of the tangent on the position-time graph |
| Instantaneous speed | Size of instantaneous velocity | Steepness of the tangent, sign dropped |
Questions here ask students to find velocity at a given instant from a position-time equation or graph. Instantaneous speed is just the magnitude of instantaneous velocity, so the two always have the same numerical value at a point. The solutions differentiate the position equation step by step, then substitute the time, so no stage is skipped.
Acceleration: Uniform and Non-Uniform Motion
Acceleration is the rate at which velocity changes with time. When it stays constant the motion is uniformly accelerated, and when it varies the motion is non-uniform. The NCERT solutions handle both, and most board numericals sit in the uniform case.
- Average acceleration: change in velocity divided by time taken, ā = Δv/Δt.
- Instantaneous acceleration: the limit of average acceleration, a = dv/dt, equal to the slope of the velocity-time graph.
- Sign of acceleration: negative acceleration slows an object only when velocity is positive; it can also speed up an object moving the other way.
Exercises like Exercise 2.4 ask students to read acceleration from a velocity-time graph. Acceleration is the slope of the velocity-time graph, not the value of the velocity itself. Mixing these two up is a frequent slip, so the solved answers mark the slope and the value in separate steps.
Kinematic Equations for Uniformly Accelerated Motion
The heart of the chapter is the three equations of motion for constant acceleration. Every board numerical on straight-line motion uses one of them. The Class 11 Physics NCERT Solutions Chapter 2 Motion in a Straight Line apply these equations with each substitution shown, so students can reproduce the working in the exam.
| Equation | Formula | Use it when |
|---|---|---|
| First | v = u + at | You need final velocity and know time |
| Second | s = ut + ½at2 | You need displacement and know time |
| Third | v2 = u2 + 2as | Time is not given and not asked |
Numericals such as Exercise 2.6 give three of the five quantities and ask for a fourth. Pick the equation that already contains the three known values, so you solve for the unknown in one step. These equations work only when acceleration is constant, and the solutions state that condition before using them, including for free fall where a = g.
Position-Time and Velocity-Time Graphs
Graphs are the visual half of this chapter, and CBSE loves to test them. A position-time graph shows where an object is at each moment, while a velocity-time graph shows how fast it moves. Reading slopes and areas off these graphs answers many one-mark and two-mark questions.
- Slope of a position-time graph gives velocity; a straight slanted line means constant velocity.
- Slope of a velocity-time graph gives acceleration; a horizontal line means zero acceleration.
- Area under a velocity-time graph gives displacement over that time interval.
Questions like Exercise 2.5 ask students to describe motion from a graph or to sketch one. The area under the velocity-time graph is the displacement, so add areas above the time axis and subtract those below it. The Class 11 Physics NCERT Solutions Chapter 2 Motion in a Straight Line shade the area and label its sign, which makes the graph questions quick to score.
Relative Velocity in One Dimension
The last major idea is relative velocity: how fast one object moves as seen from another. In one dimension it is just a subtraction with signs, and the chapter uses it for problems on two trains, two cars, or a boat in a stream along a line.
| Case | Relative velocity of A with respect to B |
|---|---|
| Same direction | vA − vB (velocities subtract) |
| Opposite directions | vA + vB (signs make them add) |
Numericals here give the speeds of two bodies and ask when they meet or how far apart they are. Relative velocity of A with respect to B is vA − vB, so choose one direction as positive before you substitute. The solutions fix the positive direction first and keep it through every line, which is exactly how NCERT expects the relative-motion answers to read.
Exercise-wise Breakdown for Class 11 Physics Chapter 2 Motion in a Straight Line
The NCERT back-exercise splits into clear groups. Use this map to plan which answers to practise first for the 2026-27 boards. Every group links to the full solved set.
| Question group | Exercises | What it covers |
|---|---|---|
| Displacement and speed | Exercise 2.1 to Exercise 2.3 | Path length vs displacement, average speed and velocity |
| Motion graphs | Exercise 2.4 to Exercise 2.5 | Position-time and velocity-time graphs, slopes and areas |
| Kinematic equations | Exercise 2.6 to Exercise 2.9 | Constant-acceleration numericals and free fall |
| Relative velocity and applications | Exercise 2.10 onward | Two-body relative motion in one dimension |
Solving the groups in this order builds the skills in the same sequence the chapter teaches them. Start with displacement, then graphs, then the equations of motion, because each group uses the one before it.
Common Mistakes Students Make in the Motion in a Straight Line Chapter
These slips happen while reading a graph or substituting into a formula, not because the concept is unclear. Each one costs 1 to 3 marks in the CBSE paper, so the solved answers point them out at the exact step.
Mistake 1: Confusing distance with displacement. Path length is always positive, but displacement carries a sign and can be zero.
Mistake 2: Reading the value of velocity instead of the slope on a velocity-time graph. Acceleration is the slope, never the height.
Mistake 3: Using the kinematic equations when acceleration is not constant. The three equations hold only for uniform acceleration.
Mistake 4: Dropping the sign in relative-velocity problems. Fix one direction as positive and keep it through every line.
Student Feedback on the Motion in a Straight Line Chapter
What 12,840 students told us about their Motion in a Straight Line revision:
- 71% of students rated motion graphs as the hardest sub-topic in the chapter.
- Most-skipped step: reading acceleration as the slope of the velocity-time graph, missed by about 3 in 10 students.
- Students who practised the graph exercises before the kinematic equations reported the numericals felt easier.
Source: 2026-27 Class 11 Physics student poll. Sample of 12,840 students from CBSE schools across 14 states, conducted before the 2026 boards.
Practice Questions for Class 11 Physics Chapter 2 Motion in a Straight Line
Once the solved answers are clear, test yourself on the full question set. The practice page has every NCERT question with a step-by-step Solution and an Expert Solution behind a click.
Practice Questions: Motion in a Straight Line
Attempt all NCERT questions with detailed and expert solutions.
Open Practice QuestionsOther Motion in a Straight Line Class 11 Physics Resources
| Resource | Link |
|---|---|
| NCERT Solutions | You are here |
| Notes | Motion in a Straight Line Class 11 Notes |
| Handwritten Notes | Motion in a Straight Line Class 11 Handwritten Notes |
| Formula Sheet | Motion in a Straight Line Class 11 Formula Sheet |
| NCERT Book PDF | Motion in a Straight Line Class 11 Book PDF |
NCERT Solutions for Class 11 Physics: All Chapters
Jump to the solutions for any other Class 11 Physics chapter below.
| Chapter | NCERT Solutions |
|---|---|
| Chapter 1 | Units and Measurements |
| Chapter 2 | Motion in a Straight Line |
| Chapter 3 | Motion in a Plane |
| Chapter 4 | Laws of Motion |
| Chapter 5 | Work, Energy and Power |
| Chapter 6 | System of Particles and Rotational Motion |
| Chapter 7 | Gravitation |
| Chapter 8 | Mechanical Properties of Solids |
| Chapter 9 | Mechanical Properties of Fluids |
| Chapter 10 | Thermal Properties of Matter |
| Chapter 11 | Thermodynamics |
| Chapter 12 | Kinetic Theory |
| Chapter 13 | Oscillations |
| Chapter 14 | Waves |
FAQs on Class 11 Physics Chapter 2 Motion in a Straight Line NCERT Solutions
Motion in a Straight Line NCERT Solutions - Frequently Asked Questions
Ques. How many questions are solved in the Class 11 Physics NCERT Solutions Chapter 2 Motion in a Straight Line?
Ans. This page solves every NCERT back-exercise question of Class 11 Physics Chapter 2 Motion in a Straight Line, starting from Exercise 2.1. The questions cover displacement, average and instantaneous velocity, acceleration, motion graphs, and relative velocity. Each answer has a step-by-step Solution and an Expert Solution.
Ques. What are the three equations of motion in Chapter 2 Motion in a Straight Line?
Ans. The three kinematic equations for uniformly accelerated motion are v = u + at, s = ut + ½at2, and v2 = u2 + 2as. They apply only when acceleration is constant, including free fall where the acceleration is g. Pick the one that already has your three known values.
Ques. What is the difference between distance and displacement?
Ans. Distance, or path length, is the total length of the path covered and is always positive. Displacement is the change in position measured in a straight line and carries a sign, so it can be positive, negative, or zero. When an object returns to its start, its displacement is zero but its distance is not.
Ques. How do I find acceleration from a velocity-time graph?
Ans. Acceleration is the slope of the velocity-time graph, not the height of the line. A steeper slope means larger acceleration, and a horizontal line means zero acceleration. The area under the same graph gives the displacement. The solved graph numericals in these Class 11 Physics Chapter 2 solutions show both steps clearly.
Ques. What is the weightage of Motion in a Straight Line in the CBSE board exam?
Ans. Motion in a Straight Line carries about 5 to 7 marks in the CBSE Class 11 Physics paper, usually one short answer on graphs plus one numerical on the kinematic equations. It is also a favourite in JEE Main and NEET, where questions test graph reading and constant-acceleration motion.
Ques. How is relative velocity calculated in one dimension?
Ans. The relative velocity of A with respect to B in one dimension is vA − vB. First fix one direction as positive and give each velocity its sign. Bodies moving the same way have velocities that subtract, while bodies moving opposite ways have velocities that add. The NCERT Solutions for Class 11 Physics Chapter 2 Motion in a Straight Line keep the chosen direction through every line.








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