Class 12 Chemistry Chapter 10 Biomolecules is the one chapter where organic chemistry stops being about reactions on paper and starts mapping directly onto living tissue, with the 2026-27 NCERT keeping every sub-system from carbohydrates to nucleic acids fully examinable. This Collegedunia formula sheet collates every structural rule, reagent test, base-pairing fact, and vitamin-deficiency pair on a printable revision page aligned with the new edition.

18 pages | 30+ structural facts | 9 vitamin pairs · Class 12 Chemistry Chapter 10, 2026-27 NCERT
  • CBSE Weightage: 3 to 5 marks
  • JEE Main Weightage: 1 to 2 percent (1 to 2 questions per paper)
  • NEET Weightage: 1 to 2 questions per year
Chapter 10 Biomolecules Formula Sheet PDF

The compact sheet that follows lists every structural fact, reagent test, base-pair rule, and vitamin-deficiency pair with its NCERT section reference.

This formula sheet is curated by Collegedunia subject experts, mapped to the 2026-27 new NCERT edition, and refined against the last five years of CBSE Board, JEE Main, and NEET papers.

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Biomolecules Formula Sheet - Class 12 Chemistry

Why Biomolecules Matters in 12th Chemistry and Entrance Exams

Biomolecules is the chapter that pulls every previous Organic block together and feeds it into the Biology / Biotechnology paper line. Carbohydrate chemistry brings back aldehyde and ketone testing from Chapter 8; amino-acid zwitter ions reuse the acid-base logic from Chapter 9; nucleic acid backbones recycle the ester linkage from Chapter 7. CBSE has set at least one 2-mark question on DNA / RNA differences in 4 of the last 5 board papers, and NEET has tested vitamin-deficiency pairs every year since 2021. Students who lock in the glycosidic linkage, peptide bond, phosphodiester linkage trio plus the fat-soluble ADEK rule pick up 3 to 4 nearly-guaranteed marks across CBSE, JEE Main, and NEET.

Biomolecules Video Walkthrough

Source: Magnet Brains on YouTube

How will Collegedunia's Biomolecules Formula Sheet Help You?

The sheet is built for a 20 to 25 minute final-night revision pass before a Chemistry paper.

  • 2026-27 NCERT Alignment: Every structural fact, reagent test, and base-pairing rule matches the current syllabus print of Sections 10.1 to 10.6.
  • One-Page Printability: The master reference table fits on a single A4 landscape sheet.
  • Sub-System Tagging: Each fact is tagged Carbohydrate, Amino acid, Protein, Enzyme, Vitamin, Nucleic acid, or Hormone, so you can pull the right answer for any 2-mark slot.
  • Expert Verification: Cross-checked against NCERT Sections 10.1 to 10.6 and the last five JEE Main and NEET papers.
Exam Hook: The single highest-frequency 1-mark trap on this chapter is ring size: glucose forms a 6-membered pyranose ring, fructose forms a 5-membered furanose ring. CBSE has tested this exact swap in 3 of the last 5 papers; NEET has asked it as an MCQ in 2025, 2024, and 2022.

Biomolecules Symbol and Notation Glossary for 12th Chemistry

The glossary below locks in every notation used in the master table. More than half of the 1-mark CBSE slips on Chapter 10 come from confusing ribose with deoxyribose, or putting thymine inside an RNA strand.

SymbolMeaningTypical Unit / Note
Cx(H2O)yEmpirical carbohydrate formulaMemory aid only; rhamnose breaks it
D, LRelative configuration (vs D-glyceraldehyde)Italic capitals; geometry only
(+), (−)Dextro- / laevo-rotatoryMeasured optical rotation; independent of D / L
α, βAnomeric configurationsα-OH below ring (Haworth); β-OH above ring
R−CH(NH2)−COOHα-amino acid general formula20 natural; only α in proteins
+H3N−CHR−COOZwitter ionNet charge 0; amphoteric in water
−CO−NH−Peptide / amide linkageBetween −COOH and −NH2 of next AA
1°, 2°, 3°, 4°Four levels of protein structureSequence; helix/sheet; 3-D fold; sub-unit assembly
EaActivation energySucrose hydrolysis: 6.22 (H+) → 2.15 (sucrase) kJ mol−1
A, T, G, C, UNitrogenous basesA/G purines; C/T/U pyrimidines; U only in RNA, T only in DNA
3′, 5′Sugar-ring carbons (nucleic acid)Phosphodiester linkage: 3′ of one sugar to 5′ of next
ADEKFat-soluble vitaminsA, D, E, K; stored in liver / adipose
Essential vs Non-Essential Amino Acids - Class 12 Chemistry Biomolecules

Biomolecules All Important Formulae and Reactions for Class 12 Chemistry

The canonical master table below lists every structural rule, reagent test, glycosidic / peptide / phosphodiester linkage, and quantitative trend in NCERT Chapter 10, with conditions, section reference, and the typical exam-use cue. All entries below are retained in the 2026-27 syllabus.

Concept / ReactionFormula / StructureConditions / NotesNCERT RefCommon Use
Carbohydrate (modern definition)Polyhydroxy aldehyde / ketone, optically activeEmpirical Cx(H2O)y is only a memory aid10.1Rhamnose C6H12O5 is a carbohydrate but breaks the empirical form
Monosaccharide (hexose) C6H12O6 Cannot be hydrolysed further10.1Glucose, fructose, galactose
Disaccharide (sucrose) C12H22O11 2 monosaccharide units; glycosidic linkage10.1.3Sucrose, maltose, lactose
Polysaccharide (C6H10O5)n Many monosaccharide units; non-sweet10.1.4Starch, cellulose, glycogen
Glucose (aldohexose) CHO-(CHOH)4-CH2OH D-(+); 4 chiral C; pyranose ring10.1.2Open-chain Fischer; six chemical evidences
Glucose preparation (commercial) (C6H10O5)n + nH2O H2SO4, 393 K, 2-3 atm nC6H12O6 Starch + dil. H2SO410.1.2.1Industrial route; pure glucose only
Glucose + HI, Δ Glucose HI, Δ n-hexane Prolonged heating10.1.2.1Proves straight 6-C chain
Glucose + Br2 water (mild) Glucose Br2/H2O Gluconic acid Mild oxidation of −CHO10.1.2.1Mono-COOH; proves aldehydic group
Glucose + HNO3 (strong) Glucose HNO3 Saccharic acid Strong oxidation of both ends10.1.2.1Di-COOH; proves terminal −CH2OH
Glucose + (CH3CO)2O Glucose (CH3CO)2O Glucose pentaacetate Acetic anhydride10.1.2.1Proves five −OH groups
Glucose + NH2OH / HCN Glucose NH2OH oxime; HCN cyanohydrin Reveal C=O10.1.2.1Proves the −CHO group
Cyclic hemiacetal (glucose)−OH at C5 attacks −CHO at C1 → 6-membered pyranose ringα (m.p. 419 K), β (m.p. 423 K)10.1.2.1New chiral C1 = anomeric C; α / β anomers; mutarotation
Fructose (ketohexose) CH2OH-CO-(CHOH)3-CH2OH D-(−); furanose ring10.1.2.2−OH at C5 attacks >C=O at C2 → 5-membered ring
Glycosidic linkage Sugar1-OH + HO-Sugar2 → Sugar1-O-Sugar2 + H2O Loss of H2O; H+ or enzyme reverses10.1.3Ether-like C−O−C bridge
Sucrose hydrolysis (invert sugar) C12H22O11 + H2O H+ or invertase D-(+)-glu + D-(-)-fru Equimolar; [α] flips +66.5° → −39.9°10.1.3 α-D-glu C1 → β-D-fru C2 ; non-reducing
Maltose2 α-D-glucose units; C1(I)–C4(II) linkageOne free hemiacetal ⇒ reducing10.1.3Maltase hydrolysis → 2 glucose
Lactose (milk sugar)β-D-galactose (C1) – β-D-glucose (C4)Free hemiacetal on glucose ⇒ reducing10.1.3Lactase hydrolysis → glucose + galactose
Starch (amylose + amylopectin) (C6H10O5)n ; α-D-glucoseAmylose 15-20%, C1–C4 unbranched; amylopectin 80-85%, C1–C4 + C1–C6 branches10.1.4I2/KI → deep blue
Celluloseβ-D-glucose; C1–C4 β-glycosidicStructural; indigestible to humans10.1.4Most abundant organic substance; wood, cotton, paper, rayon
Glycogen (animal starch)α-D-glucose; like amylopectin but more highly branchedStored in liver, muscles, brain10.1.4Hydrolysed to glucose on demand
α-Amino acid general formula R-CH(NH2)-COOH R = side chain10.2.120 natural; chiral except glycine (R = H)
Acidic / basic / neutral AACount side-chain −COOH vs −NH2More −COOH = acidic (Asp, Glu); more −NH2 = basic (Lys, Arg, His)10.2.1Side chain only; not the backbone
Essential amino acids (10)Val, Leu, Ile, Thr, Met, Phe, Trp, Lys, Arg, HisBody cannot synthesise; must come from diet10.2.2NCERT count = 10 (memorise list)
Zwitter ion R-CH(NH2)-COOH R-CH(+NH3)-COO- Net charge 0; amphoteric10.2.2Explains high m.p. + water solubility of AA
Peptide bond H2N-CHR1-COOH + H2N-CHR2-COOH -H2O -CHR1-CO-NH-CHR2- Amide between −COOH and −NH210.2.3Dipeptide; the boxed −CO−NH− is the peptide bond
Polypeptide vs protein>10 AA = polypeptide; >100 AA or M > 10,000 u = proteinBoundary is not sharp10.2.3Insulin (51 AA) is still called a protein
Four levels of protein structure1° sequence → 2° helix/sheet → 3° 3-D fold → 4° sub-unit assembly2°: H-bonds between peptide C=O and N−H10.2.3Haemoglobin = 4 sub-units (4°)
Fibrous vs globularParallel chains, insoluble (keratin, myosin) vs spherical, soluble (insulin, albumins)Function follows shape10.2.3Fibrous = structural; globular = enzymes / transport
DenaturationHeat / pH / urea / heavy metal / organic solvent2° and 3° lost; 1° preserved10.2.3Egg-white coagulation, milk curdling
Enzyme (general)Globular protein; substrate-specific; suffix −aseLowers Ea without being consumed10.3Maltase, sucrase, lactase, zymase, pepsin, trypsin
Enzyme Ea drop (NCERT) Ea (H+) = 6.22 kJ mol-1; Ea (sucrase) = 2.15 kJ mol-1 Sucrose hydrolysis10.3Enzyme drops Ea to about one-third
Fat-soluble vitaminsA, D, E, K (ADEK)Stored in liver and adipose tissue10.4Insoluble in water
Water-soluble vitaminsB group + CExcreted in urine; supplied regularly10.4Exception: B12 is stored
Nucleic acid compositionPentose sugar + H3PO4 + nitrogen baseSugars: β-D-ribose (RNA), β-D-2-deoxyribose (DNA)10.5DNA: A,G,C,T; RNA: A,G,C,U
Nucleoside vs nucleotideBase + sugar (N-glycosidic at C1′) vs Base + sugar + phosphate (ester at C5′)Nucleotide = phosphate ester of nucleoside10.5Nucleic acid = polynucleotide
Phosphodiester linkage …-Sugar-C3'O-P(=O)(O-)-C5'O-Sugar-… 3′ of one to 5′ of next10.5Sugar-phosphate backbone; bases project sideways
Watson-Crick base pairingA ··· T (2 H-bonds); G ··· C (3 H-bonds)1 : 1 ratio in any DNA (Chargaff)10.5Molecular basis of replication
Hormones (chemical classes)Steroid / polypeptide / amino-acid-derivedEndocrine origin; act at a distance10.6Estrogens, testosterone (steroid); insulin (polypeptide); thyroxine, epinephrine (AA-derived)
Insulin / glucagonPancreas; insulin lowers, glucagon raises blood glucoseInsulin: 51 AA, β-cells; glucagon: α-cells10.6Textbook example of hormonal homeostasis
ThyroxineIodinated tyrosine derivative (thyroid)Low ⇒ hypothyroidism (goitre)10.6Iodised salt prevents I-deficiency goitre

The single highest-frequency CBSE 1-mark slip on this chapter is the sugar-ring swap: glucose → pyranose (6-ring), fructose → furanose (5-ring). Tag every cyclic-form question with the sugar name first, then choose the ring size.

Quick Carbohydrate Linkage Map (Sucrose, Maltose, Lactose, Starch, Cellulose, Glycogen)

The disaccharide and polysaccharide linkages CBSE / NEET keep testing. Memorise the linkage type and the reducing-sugar status together.

SugarLinkageHydrolysisReducing?
Sucrosealpha-D-glu C1 ↔ beta-D-fru C2 (alpha,beta-1,2)Glucose + fructose (invert sugar; rotation +66.5 to -39.9)Non-reducing (both anomeric C locked)
Maltose2 alpha-D-glucose, alpha-1,42 glucoseReducing (one free hemiacetal)
Lactosebeta-D-galactose C1 ↔ beta-D-glucose C4 (beta-1,4)Galactose + glucoseReducing
Starch (amylose + amylopectin)amylose alpha-1,4 linear; amylopectin alpha-1,4 + alpha-1,6 branchesMaltose → glucose (amylase)Non-reducing
Cellulosebeta-D-glucose, beta-1,4 straight chainIndigestible to humansNon-reducing
Glycogen ("animal starch")alpha-D-glucose; alpha-1,4 + frequent alpha-1,6 branchesGlucose-1-phosphate (phosphorylase)Non-reducing

Anomers, Epimers and Mutarotation - The Stereochemistry of Glucose

  • Anomers differ only at the anomeric carbon (C1 in aldoses, C2 in ketoses). Alpha-D-glucose: -OH below the ring at C1; beta-D-glucose: -OH above. Anomerisation goes via the open-chain aldehyde.
  • Epimers differ at one non-anomeric chiral carbon. Glucose / galactose are C4 epimers; glucose / mannose are C2 epimers.
  • Mutarotation: alpha-D-glucose ([alpha] = +112) equilibrates in water through the open chain to give beta-D-glucose ([alpha] = +19); the equilibrium specific rotation is +52.5 degrees.
  • Fructose: ketohexose; cyclises C5-OH attacking C2 to give a 5-membered furanose ring; D-(-), [alpha] = -92.4 degrees. Note that "D" does not predict the sign of rotation.

Nucleoside vs Nucleotide; DNA vs RNA Composition

PropertyDNARNA
Sugarbeta-D-2-deoxyribose (no -OH at C2')beta-D-ribose (-OH at C2' present)
BasesA, G, C, TA, G, C, U (uracil replaces thymine)
StrandRight-handed double helix, antiparallelSingle strand; folds back in tRNA, rRNA
Base pairsA ··· T (2 H-bonds); G ··· C (3 H-bonds)Internal A-U / G-C in hairpin loops
FunctionStores hereditary information; replicatesmRNA carries message; tRNA delivers AA; rRNA forms ribosome

Nucleoside = base + sugar (no phosphate, N-glycosidic linkage at C1'); nucleotide = base + sugar + phosphate (ester at C5'). Nucleotides polymerise to nucleic acids via the 5' to 3' phosphodiester linkage. Purines (double-ring) = A, G; pyrimidines (single-ring) = C, T, U. Mnemonic "PURe As Gold" for purines.

One-Shot Revision Tips for Class 12th Chemistry Biomolecules

  • Count the rings, not the carbons, for sugars: 6 atoms in the ring = pyranose (glucose); 5 atoms in the ring = furanose (fructose). Faster than counting C atoms when the Haworth structure is drawn out.
  • Anomers differ only at one carbon — the anomeric C (C1 in aldoses, C2 in ketoses). Everything else in the ring is identical between α and β.
  • Sucrose is non-reducing because BOTH anomeric −OH groups (C1 of glucose + C2 of fructose) are locked in the glycosidic linkage. Maltose and lactose each keep one free hemiacetal, so they reduce Fehling and Tollens reagents.
  • Cellulose is β-1,4; starch and glycogen are α-1,4 — the only structural difference, but it is the reason humans digest starch and cannot digest cellulose.
  • Denaturation destroys 2° and 3°, not 1°: the peptide bonds (1° structure) survive boiling, acid, urea, or heavy-metal exposure. That is why a boiled egg-white is still a chain of amino acids, just no longer folded.
  • ADEK floats in oil: the four fat-soluble vitamins are A, D, E, K. Everything else is water-soluble. The one exception that is stored anyway is B12.
Quick Tip: The DNA / RNA discriminator at a glance is sugar at 2′ and one base swap. DNA has 2′-deoxyribose and uses thymine (T); RNA has ribose (2′-OH retained) and uses uracil (U). Adenine, guanine, and cytosine are common to both. Use this rule to answer every "which compound is found in RNA but not DNA" question.
Biomolecules Key Numbers - Class 12 Chemistry

Biomolecules Quick-Fact Cards for MCQ Recall

The four facts below are the ones JEE Main and NEET rotate as 1-mark MCQs. Memorise them in this exact form.

Glucose = pyranose (6); fructose = furanose (5)
Glucose −OH at C5 closes onto −CHO at C1 to give the 6-ring; fructose −OH at C5 closes onto C2 keto to give the 5-ring
A···T (2 H-bonds), G···C (3 H-bonds)
Chargaff: A:T and G:C are 1:1 in any DNA. T is replaced by U in RNA. Each pair is purine-pyrimidine (size matches)
Sucrose is non-reducing
Both anomeric −OH locked in the C1−C2 glycosidic linkage. Maltose and lactose keep one free hemiacetal, so they reduce Fehling / Tollens
Denaturation: 1° survives, 2° and 3° do not
Egg-white coagulation, milk curdling: peptide bonds intact, helix / sheet / fold gone. Native ≠ natural; native = folded with activity
Watch Out: Glycogen is animal starch, not animal cellulose. Students often write "cellulose stored in liver" — that is wrong. Glycogen has the same α-1,4 + α-1,6 branching as amylopectin (just more highly branched) and is stored in liver, muscles, and brain. Cellulose is the indigestible β-1,4 polymer that humans cannot store at all. Writing "cellulose is stored in animals" is a guaranteed 1-mark deduction in CBSE marking schemes.

Vitamins, Sources and Deficiency Reference Table for Biomolecules

The pairs below power most of the 1-mark MCQs on Section 10.4. NEET has asked at least one vitamin-deficiency question every year since 2021.

VitaminSolubility classMain sourceDeficiency disease
AFat-solubleFish liver oil, carrots, butter, milkXerophthalmia, night blindness
B1 (thiamine)Water-solubleYeast, milk, cerealsBeri-beri
B2 (riboflavin)Water-solubleMilk, egg white, liver, kidneyCheilosis
B6 (pyridoxine)Water-solubleYeast, milk, egg yolk, cerealsConvulsions
B12Water-soluble (but stored)Meat, fish, egg, curdPernicious anaemia
C (ascorbic acid)Water-solubleCitrus fruits, amla, leafy vegetablesScurvy, bleeding gums
DFat-solubleSunlight, fish, egg yolkRickets, osteomalacia
EFat-solubleWheat germ oil, sunflower oilRBC fragility, muscular weakness
KFat-solubleGreen leafy vegetablesIncreased blood-clotting time

Top 3 Most-Asked Biomolecules PYQ Topics in CBSE, JEE and NEET

The three patterns below have repeated most often since 2021. The full year-by-year map sits on the Collegedunia NCERT Solutions page.

TopicFrequency (CBSE + JEE + NEET, 2026 to 2021)Typical mark band
DNA vs RNA differences (sugar, base, strands)11 times2 to 3 marks
Vitamin-deficiency pairing (A-night blindness, K-clotting, etc.)10 times1 mark
Glucose chemical evidences (Br2/water, HNO3, acetic anhydride)8 times2 to 3 marks

Full year-wise PYQ map: Biomolecules Class 12 Chemistry NCERT Solutions

Biomolecules Common-Numerical Pattern Templates for 12th Chemistry

The four problem setups below have dominated CBSE, JEE Main, and NEET papers since 2021.

PatternWhat the question givesFormula / Rule to applyCommon trap
Reducing vs non-reducingDisaccharide name (sucrose, maltose, lactose) — classifyBoth anomeric −OH in linkage ⇒ non-reducing (sucrose); one free hemiacetal ⇒ reducing (maltose, lactose)Saying lactose is non-reducing because it has two sugars
Glycosidic linkage typeSucrose / maltose / lactose / cellulose / starch — name the linkageSucrose: α-glu C1 — β-fru C2; maltose: α-1,4; lactose: β-1,4 (gal-glu); starch / glycogen: α-1,4 + α-1,6 branches; cellulose: β-1,4Mixing α with β for starch vs cellulose
Vitamin-deficiency matchDisease name (scurvy, beri-beri, night blindness, rickets, pernicious anaemia, increased clotting time)C, B1, A, D, B12, K respectivelyConfusing B1 (beri-beri) with B12 (pernicious anaemia)
DNA / RNA compositionList of bases / sugars / strand types — identify DNA vs RNADNA: deoxyribose + A, G, C, T, double helix; RNA: ribose + A, G, C, U, single strandPutting thymine in RNA or uracil in DNA

Biomolecules Weightage Compared Across Class 12 Chemistry Chapters

Typical CBSE marks distribution across the 10 chapters of the 2026-27 NCERT, averaged over the last five board papers. Biomolecules sits in the low-tier, similar to Haloalkanes and Haloarenes — high-yield per page-of-reading because the entire chapter rewards rote-recall of structural pairs and reagent maps.

Ch 1 Solutions
7 marks
Ch 2 Electrochemistry
6 marks
Ch 3 Chemical Kinetics
6 marks
Ch 4 d- and f-Block Elements
5 marks
Ch 5 Coordination Compounds
7 marks
Ch 6 Haloalkanes and Haloarenes
4 marks
Ch 7 Alcohols, Phenols and Ethers
5 marks
Ch 8 Aldehydes, Ketones, Carboxylic Acids
6 marks
Ch 9 Amines
5 marks
Ch 10 Biomolecules
4 marks

Related Links:

More Biomolecules Chemistry Class 12 Resources

NCERT Formula Sheet for Class 12 Chemistry: All Chapters

Jump to the formula sheet for any other chapter of Class 12 Chemistry below.

Biomolecules Class 12 Chemistry Formula Sheet FAQs

Ques. Where can I download the Biomolecules Class 12 Chemistry Formula Sheet PDF?

Ans. You can download the Biomolecules Class 12 Chemistry Formula Sheet PDF directly from this Collegedunia page. Both the Normal and HD versions are available and free of cost.

Ques. Is this Formula Sheet aligned with the 2026-27 NCERT?

Ans. Yes. This page reflects the current 2026-27 syllabus for Class 12 Chemistry. Biomolecules is fully retained in the new edition with no structural cuts; every concept in Sections 10.1 to 10.6 of the NCERT remains examinable.

Ques. How many pages is the Class 12th Chemistry Biomolecules Formula Sheet PDF?

Ans. The Formula Sheet PDF runs approximately 18 pages and covers the carbohydrate master table, amino-acid and protein structural rules, enzyme activation-energy data, the vitamin-deficiency reference, the DNA-RNA comparison, and the hormone classification.

Ques. What is the difference between glucose and fructose at the structural level?

Ans. Both have the same molecular formula C6H12O6 , but they differ in three structural respects. Glucose is an aldohexose: it carries a −CHO group at C1 and four chiral centres (C2, C3, C4, C5). Fructose is a ketohexose: it carries a >C=O at C2, a primary −OH at C1, and three chiral centres. On cyclisation, the −OH at C5 of glucose attacks the C1 aldehyde to give a six-membered pyranose ring (one O + five C); in fructose the −OH at C5 attacks the C2 keto to give a five-membered furanose ring (one O + four C). Glucose is dextrorotatory ([α]D = +52.5) ; fructose is laevorotatory ([α]D = -92.4) . The 1 : 1 mixture obtained when sucrose hydrolyses is called invert sugar because the net rotation flips from + to −.

Ques. Why are sucrose, maltose and lactose classified differently on the reducing test?

Ans. A reducing sugar must have at least one free hemiacetal (a C bearing both an −OH and an −OR via the ring oxygen) which can open back to a free −CHO and reduce Fehling or Tollens reagent. Sucrose (α-D-glucose C1 – β-D-fructose C2) uses both anomeric −OH groups (C1 of glucose and C2 of fructose) inside the glycosidic linkage, so neither sugar can open up — sucrose is non-reducing. Maltose (two α-D-glucose units linked C1–C4) and lactose (β-D-galactose C1 – β-D-glucose C4) each leave one anomeric C free, so they retain a hemiacetal and reduce Fehling and Tollens. The same rule explains why all monosaccharides reduce both reagents.

Ques. What exactly happens during the denaturation of a protein, and is it reversible?

Ans. Denaturation is the loss of the secondary and tertiary three-dimensional structure of a protein, triggered by heat, pH change, urea, organic solvents, or heavy-metal salts. The hydrogen bonds that hold the α-helix and the β-pleated sheet, plus the disulphide −S−S− bridges that lock the 3-D fold, are cleaved. The primary structure (the peptide-bond sequence) is preserved because the −CO−NH− bond itself is not broken. The protein loses biological activity (a denatured enzyme cannot catalyse; a denatured hormone cannot signal). Common examples include the coagulation of egg-white on boiling and the curdling of milk by lactic acid from bacteria. In most cases denaturation is irreversible in a laboratory setting; refolding the chain back into its native conformation requires either chaperone proteins or controlled cellular conditions and is rarely complete.

Ques. How does the structure of DNA differ from the structure of RNA?

Ans. DNA and RNA differ at three structural levels. Sugar: DNA contains β-D-2-deoxyribose (no −OH at C2′); RNA contains β-D-ribose (−OH at C2′ retained). Bases: DNA uses adenine, guanine, cytosine, and thymine; RNA uses adenine, guanine, cytosine, and uracil in place of thymine. Strand architecture: DNA is a right-handed double helix with two antiparallel strands held by the Watson-Crick base pairs A···T (two H-bonds) and G···C (three H-bonds), giving Chargaff's 1:1 ratio. RNA is single-stranded and exists in three functional forms (mRNA, rRNA, tRNA) that work together during protein synthesis. DNA stores hereditary information and self-replicates; RNA executes the genetic message, and it does not self-replicate inside cells.

Ques. Which vitamin deficiencies cause scurvy, beri-beri, night blindness, rickets, and increased blood clotting time?

Ans. The five disease-vitamin pairs that NCERT Table 10.3 fixes are: Scurvy → deficiency of Vitamin C (ascorbic acid; sourced from citrus and amla); Beri-beri → deficiency of Vitamin B1 (thiamine); Night blindness / xerophthalmia → deficiency of Vitamin A; Rickets / osteomalacia → deficiency of Vitamin D; Increased blood-clotting time → deficiency of Vitamin K. NCERT exercise 10.19 asks "name the vitamin responsible for the coagulation of blood" and the marking scheme expects only "Vitamin K".

Ques. Why is insulin called a protein when it is only 51 amino acids long?

Ans. The boundary between polypeptide and protein is not a sharp count. NCERT records that compounds with more than 10 amino acid residues are usually called polypeptides, and those with more than 100 residues or a molecular mass above 10,000 u are called proteins. Insulin sits below both of those numerical thresholds (51 residues, M about 5,800 u), but it has a clearly defined three-dimensional fold built from two polypeptide chains held together by disulphide −S−S− bridges, and it performs a well-defined biological function (lowering blood glucose by promoting cellular uptake and storage as glycogen). Because of that well-defined 3-D structure and dedicated function, NCERT and IUPAC convention both classify insulin as a protein hormone, even though by residue count alone it would technically be a polypeptide.

Ques. What is the difference between anomers and epimers and how is mutarotation defined?

Ans. Anomers are stereoisomers of sugars that differ only at the anomeric carbon - C1 in aldoses or C2 in ketoses - which is the new chiral centre created when the open chain cyclises. Alpha- and beta-D-glucopyranose are anomers. Epimers are stereoisomers that differ at one non-anomeric chiral carbon: glucose and galactose are C4 epimers; glucose and mannose are C2 epimers. Mutarotation is the gradual change in specific rotation when a pure anomer of a reducing sugar dissolves in water and equilibrates with the other anomer through the open-chain form. For D-glucose, pure alpha has [α] = +112°, pure beta has [α] = +19°, and the equilibrium mixture has [α] = +52.5°.

Ques. How is haemoglobin an example of quaternary protein structure?

Ans. Haemoglobin is built from four polypeptide subunits - two α chains (141 residues each) and two β chains (146 residues each) - each cradling a heme group with a Fe(II) centre. The four subunits associate through non-covalent interactions and salt bridges; total molecular mass is about 64,500 u. Cooperative O2 binding (positive cooperativity) gives haemoglobin its sigmoidal binding curve, distinguishing it from monomeric myoglobin (a tertiary-only protein). The association of two or more polypeptide chains defines quaternary structure.

Ques. What are purines and pyrimidines and which bases appear in DNA vs RNA?

Ans. Purines are double-ring nitrogen bases - adenine (A) and guanine (G); mnemonic "PURe As Gold". Pyrimidines are single-ring bases - cytosine (C), thymine (T) and uracil (U). DNA contains A, G, C, T; RNA replaces thymine with uracil and so contains A, G, C, U. The Watson-Crick base pairs in DNA are A ··· T (2 H-bonds) and G ··· C (3 H-bonds), each pairing one purine with one pyrimidine.