NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 Solutions are based on parallelograms and triangles that have the same base and same parallel lines. It also covers the median of a triangle that divides into two triangles of equal areas.

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Check out NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

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Important Chapter Related Topics
Area of Triangle	Perimeter of a Parallelogram
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CBSE X Related Questions

1.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.
View Solution
2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
3.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.
View Solution
4.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution
5.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is
- $50^\circ$
- $60^\circ$
- $45^\circ$
- $30^\circ$
View Solution
6.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is
- $\frac{5}{12}$
- $\frac{5}{6}$
- $1$
- $0$
View Solution

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NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

CBSE X Related Questions

1.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

4.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

5.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

6.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

CBSE X Related Questions

1.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

2.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

4.If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

5.An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

6.Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

4.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

5.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

6.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is