NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.3 Solutions are based on Triangles on the Same Base and Between the Same Parallel lines.

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Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles 

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CBSE X Related Questions

  • 1.

    In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.


      • 2.
        In \(\triangle ABC, \angle B = 90^\circ\). If \(\frac{AB}{AC} = \frac{1}{2}\), then \(\cos C\) is equal to

          • \(\frac{3}{2}\)
          • \(\frac{1}{2}\)
          • \(\frac{\sqrt{3}}{2}\)
          • \(\frac{1}{\sqrt{3}}\)

        • 3.
          Solve the equation \(4x^2 - 9x + 3 = 0\), using quadratic formula.


            • 4.
              PA and PB are tangents drawn to a circle with centre O. If \(\angle AOB = 120^\circ\) and OA = 10 cm, then
              PA and PB are tangents drawn to a circle with centre O

              (i) Find \(\angle OPA\).
              (ii) Find the perimeter of \(\triangle OAP\).
              (iii) Find the length of chord AB.


                • 5.

                  From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
                  Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$


                    • 6.
                      Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

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