NCERT Solutions for Class 11 Maths Chapter 9 Miscellaneous Exercises

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Class 11 Maths NCERT Solutions Chapter 9 Sequence and Series Miscellaneous Exercises is based on the following concepts:

Sequences
Series
Arithmetic Progression (A.P.)
Geometric Progression (G.P.)
Relationship Between A.M. and G.M.
Sum to n terms of Special Series

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Also check other Exercise Solutions of Class 11 Maths Chapter 9 Sequence and Series

Also check:

Important Chapter Related Links
Harmonic Mean	Sum of Squares	Difference between Sequence and Series
Summation Formula	Geometric Series Formula	Sum of Arithmetic Sequence Formula
Sum Of Cubes Formula	Arithmetic Mean Formula	Arithmetic Sequence Explicit Formula
Arithmetic Sequence Recursive Formula	Difference of Cubes Formula	Difference of Squares Formula
Fourier Series Formula	Infinite Geometric Series Formula	Infinite Series Formula
Taylor Series Formula	Prime Number Formula	Arithmetic Geometric Sequence

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
Evaluate:
\[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]
View Solution
2.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).
View Solution
3.
A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length.
4.
A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is
- Reflexive only
- Reflexive and Transitive
- Symmetric and Transitive
- Symmetric only
View Solution
5.
Find:
Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).
- \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
View Solution
6.
Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).
View Solution

Similar Mathematics Concepts

Sequence and Series: Types, Formulas & Examples

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NCERT Solutions for class 11 Maths Chapter 9: Sequences and Series

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