NCERT Solutions for Class 11 Maths Chapter 12 Miscellaneous Exercises

Collegedunia Team logo

Collegedunia Team

Content Curator

Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises is based on the following concepts:

  • Coordinate Axes and Coordinate Planes in Three Dimensional Space
  • Coordinates of a Point in Space
  • Distance between Two Points
  • Section Formula

Download PDF NCERT Solutions for Class 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises

Check out the solutions of Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises

Read More: NCERT Solutions For Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

Also check other Exercise Solutions of Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

Also check:

Also check:

CBSE CLASS XII Related Questions

  • 1.

    Find the product of the maximum and minimum values of the function \( f(x) = \cos x - \frac{1}{2}\cos 2x,\ x \in \left[0, \frac{\pi}{2}\right] \).


      • 2.

        The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

          • \( -6 \) unit/sec
          • \( 0 \) unit/sec
          • \( 18 \) unit/sec
          • \( 6 \) unit/sec

        • 3.

          For the following Linear Programming Problem, shade the feasible region on the graph and find the coordinates of its corner points :

          Minimize \(Z = 18x + 10y\)

          subject to constraints

          \[ \begin{aligned} 4x + y &\ge 20 \\ 2x + 3y &\ge 30 \\ x, y &\ge 0. \end{aligned} \]


            • 4.

              \( \int e^{x}\left( \frac{2+\sin 2x}{1+\cos 2x} \right) dx \) is equal to :

                • \( \log \cos 2x + C \)
                • \( \sec^{2} 2x + C \)
                • \( e^{x}\tan x + C \)
                • \( e^{x}\cot x + C \)

              • 5.

                If \(P(A) = 0.3\), \(P(B) = 0.7\) and \(P(B/A) = 0.5\), then \(P(A \cup B)\) is :

                  • \(0.35\)
                  • \(0.85\)
                  • \(0.5\)
                  • \(0.21\)

                • 6.

                  Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).

                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show