Co-ordinate Geometry JEE Mains Questions - List Of Most Asked Questions With Solutions

NTA will shortly release the JEE Main Syllabus 2025 at jeemain.nta.ac.in. Last Year, the complete syllabus of JEE Main underwent some major changes. According to the latest syllabus guidelines, the weightage of Maths has dropped to 22.5%. Due to these changes in the syllabus, certain shifts in chapter-wise weightage have been observed. Coordinate Geometry are among such topics. It’s among the least weightage topics in JEE Main Maths Syllabus 2025. This chapter holds 1.39% weightage in the whole syllabus.

  • Coordinate Geometry Is a part of the General Maths section, and every year around 2-3 questions are asked from this chapter. Due to the drop in weightage, you can expect 1-2 questions in JEE Main 2025.
  • Coordinate Geometry in JEE Mains Maths Syllabus 2025 covers all the basic concepts on units and measurements, fundamentals of units, dimensions etc.

Aspirants consider Coordinate Geometry as one of the Easiest Chapters in Maths for JEE Main 2025. Even though this chapter has the least weightage in the syllabus, to develop a strong foundation in physics, this particular chapter plays a pivotal role. Hence the candidates need to develop a clear understanding of this chapter. The list of most asked questions from this chapter will help the students with their preparation.

Must Check News on JEE Main Maths:

Here are some examples of coordinate geometry questions that might be asked in the JEE Main:

  1. Distance from a point to the intersection of a line and a plane
  2. Find the distance of the point (1, 1, 9) from the intersection of the line (x – 3)/1 = (y – 4)/2 = (z – 5)/2 and the plane x + y + z = 17
  3. Finding the value of c in a rectangle
  4. The points (1, 3) and (5, 1) are opposite vertices of a rectangle, and the other two vertices lie on the line y = 2x + c. Find the value of c
  5. Finding the equation of a line
  6. Find the equation of the lines that pass through the point (3, -2) and are inclined at 60° to the line √3x + y = 1
  7. Finding the points on a line that are a certain distance away from a point
  8. If the slope of a line passing through point A (3, 2) is 3/4, then find the points on the line that are 5 units away from A

Coordinate geometry, also known as analytic geometry or Cartesian geometry, is the study of geometry using a coordinate system. It's used in many fields, including physics, engineering, aviation, rocketry, and space science.

Coordinate Geometry JEE Mains Questions -

List Of Most Asked Questions With Solutions

In the (JEE) Main, the topic of Physics and Measurement often features questions that have appeared multiple times in previous years. Many questions in this section are either repeated or follow similar patterns, with only minor changes, such as different numerical values or slight modifications in wording.Certain questions have been repeated as many as five times.

Here are some of the most frequently asked and repeated questions:

Question 1:

Find the equation of the line passing through the points (2, 3) and (4, 5).

Solution: The correct answer is y−3=1(x−2)y - 3 = 1(x - 2)y−3=1(x−2).

Explanation: Use the two-point form of the line equation: y−y1=m(x−x1)y - y_1 = m(x - x_1)y−y1​=m(x−x1​), where mmm is the slope calculated as m=(y2−y1)/(x2−x1)m = (y_2 - y_1)/(x_2 - x_1)m=(y2​−y1​)/(x2​−x1​).

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 2:

Find the distance between the points (1, 2) and (4, 6).

Solution: The correct answer is 5 units.

Explanation: Use the distance formula d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}d=(x2​−x1​)2+(y2​−y1​)2​.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 3:

What is the slope of the line 3x+4y−7=03x + 4y - 7 = 03x+4y−7=0?

Solution: The correct answer is −3/4-3/4−3/4.

Explanation: Rearrange the line equation to slope-intercept form y=mx+cy = mx + cy=mx+c, where mmm is the slope.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 4:

Find the coordinates of the centroid of the triangle with vertices (1, 2), (3, 4), and (5, 6).

Solution: The correct answer is (3, 4).

Explanation: Use the centroid formula G=(x1+x2+x33,y1+y2+y33)G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)G=(3x1​+x2​+x3​​,3y1​+y2​+y3​​).

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 5:

Find the equation of the circle with center (2, 3) and radius 4.

Solution: The correct answer is (x−2)2+(y−3)2=16(x - 2)^2 + (y - 3)^2 = 16(x−2)2+(y−3)2=16.

Explanation: Use the standard form of a circle (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2(x−h)2+(y−k)2=r2.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 6:

What is the equation of the parabola with vertex at the origin and focus at (0, 2)?

Solution: The correct answer is y2=8xy^2 = 8xy2=8x.

Explanation: Use the equation of a parabola y2=4axy^2 = 4axy2=4ax, where the distance from vertex to focus a=2a = 2a=2.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 7:

Find the equation of the ellipse with major axis 10 units and minor axis 6 units centered at the origin.

Solution: The correct answer is x225+y29=1\frac{x^2}{25} + \frac{y^2}{9} = 125x2​+9y2​=1.

Explanation: Use the standard form x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1a2x2​+b2y2​=1, where a=5a = 5a=5 and b=3b = 3b=3.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 8:

Find the length of the latus rectum of the parabola y2=4xy^2 = 4xy2=4x.

Solution: The correct answer is 4 units.

Explanation: The length of the latus rectum of a parabola y2=4axy^2 = 4axy2=4ax is 4a4a4a, where a=1a = 1a=1.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 9:

Find the center of the circle given by the equation x2+y2−4x+6y−12=0 x^2 + y^2 - 4x + 6y - 12 = 0x2+y2−4x+6y−12=0.

Solution: The correct answer is (2, -3).

Explanation: Complete the square to rewrite the equation in standard form (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2(x−h)2+(y−k)2=r2, where (h,k)(h, k)(h,k) is the center.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question 10:

What is the eccentricity of the hyperbola x216−y29=1\frac{x^2}{16} - \frac{y^2}{9} = 116x2​−9y2​=1?

Solution: The correct answer is 5\sqrt{5}5​.

Explanation: Use the formula for eccentricity e=1+b2a2e = \sqrt{1 + \frac{b^2}{a^2}}e=1+a2b2​​.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

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