The Odisha CPET 2025 Chemistry question paper is available here with detailed solutions for free download. Odisha CPET 2025 was conducted by SAMS Odisha (Higher Education Department) in offline mode, and the Chemistry paper carried 100 questions in 80 minutes.

Odisha CPET 2025 Chemistry Question Paper with Solutions Download PDF Check Solutions

Odisha CPET 2025 Chemistry Questions with Solutions

Question 1:

How many lines are produced when an electron jumps from the fifth to the second orbit for a hydrogen atom?

  • (A) 8
  • (B) 10
  • (C) 15
  • (D) 6
Detailed Solution
Question 2:

How many electrons in an atom have the following quantum numbers? \(N = 3, l = 0\)

  • (A) 4
  • (B) 2
  • (C) 6
  • (D) 8
Detailed Solution
Question 3:

What is the hybridization of copper in \([Cu(NH_3)_4]^{2+}\)?

  • (A) \(sp^3\)
  • (B) \(sp^2d\)
  • (C) \(dsp^2\)
  • (D) \(sp^3d\)
Detailed Solution
Question 4:

What is the bond order of \(O_2^{2-}\)?

  • (A) 1
  • (B) 2
  • (C) 2.5
  • (D) 1.5
Detailed Solution
Question 5:

What is the shape of \(XeF_6\)?

  • (A) Square pyramidal
  • (B) Octahedral
  • (C) Pentagonal bipyramidal
  • (D) Distorted octahedral
Detailed Solution
Question 6:

What is the order of the covalent character of CaCl2, CaF2, CaBr2, and CaI2?

  • (A) CaCl2 > CaF2 > CaBr2 > CaI2
  • (B) CaF2 > CaCl2 > CaBr2 > CaI2
  • (C) CaF2 < CaCl2 < CaBr2 < CaI2
  • (D) CaCl2 > CaBr2 > CaI2 > CaF2
Detailed Solution
Question 7:

A monobasic acid with a concentration of 0.04 M is dissociated to the extent of 0.5% in an aqueous solution. What is the dissociation constant of the acid?

  • (A) \(10^{-6}\)
  • (B) \(10^{-5}\)
  • (C) \(10^{-4}\)
  • (D) \(10^{-7}\)
Detailed Solution
Question 8:

The solubility product of Fe(OH)3 is \(1.1 \times 10^{-36}\) at 25 C. What is the solubility of ferric hydroxide?

  • (A) \(3.7 \times 10^{-8}\ \text{g L}^{-1}\)
  • (B) \(4.8 \times 10^{-9}\ \text{g L}^{-1}\)
  • (C) \(4.8 \times 10^{-8}\ \text{g L}^{-1}\)
  • (D) \(3.7 \times 10^{-9}\ \text{g L}^{-1}\)
Detailed Solution
Question 9:

Calculate the amount of oxalic acid required to prepare 250 mL of 0.35 M solution of oxalic acid.

  • (A) 8.735 g
  • (B) 7.875 g
  • (C) 8.175 g
  • (D) 8.375 g
Detailed Solution
Question 10:

Which indicator is used to titrate sodium bicarbonate with hydrochloric acid?

  • (A) Starch
  • (B) Phenolphthalein
  • (C) EBT
  • (D) Methyl orange
Detailed Solution

Odisha CPET 2025 Chemistry Exam Pattern and Marking Scheme Explained

As per the test booklet issued by SAMS Odisha (pg.samsodisha.gov.in), the Chemistry paper is a single-best-answer MCQ test.

  • Total questions: 100 MCQs (Subject Code 05)
  • Duration: 80 minutes
  • Total marks: 100
  • Marking scheme: +1 for a correct answer, -0.25 for a wrong one
  • Question types: single-best-answer MCQs, four options (A)-(D) each

High-Weightage Topics in Odisha CPET 2025 Chemistry

  • Atomic structure and chemical bonding - quantum numbers, hydrogen spectral lines, bond order and molecular shape questions recur early in the paper
  • Coordination compounds - hybridization and geometry of transition-metal complexes
  • Ionic and solubility equilibrium - dissociation constants and solubility product numericals
  • Volumetric analysis - molarity calculations and indicator selection for acid-base titrations
  • Organic reaction mechanisms - substitution, elimination and oxidation reactions of hydrocarbons

Odisha CPET 2025 Chemistry Question Paper Analysis Video

Source: Channel not yet verified - needs a real, non-competitor Odisha CPET 2025 Chemistry walkthrough video before publish.

How to Use the Odisha CPET Chemistry Question Paper for Practice

Solve the paper as a timed 80-minute mock first, then check every answer against the step-by-step solution PDF before moving on.

  • Attempt all 100 questions under exam conditions before looking at any solution
  • Re-solve every numerical (dissociation constant, solubility, molarity) by hand rather than just reading the solution
  • Group your mistakes by topic (bonding, equilibrium, organic mechanisms) and redo that topic's questions from other years
  • Watch the negative marking - with -0.25 per wrong answer, skip a question rather than guessing blind

Odisha CPET 2025 Chemistry Question Paper FAQs

Ques. How many questions are in the Odisha CPET 2025 Chemistry paper and how much time do I get?

Ans. The Chemistry paper (Subject Code 05) has 100 multiple-choice questions to be solved in 80 minutes, carrying 100 total marks.

Ques. What is the marking scheme for Odisha CPET 2025 Chemistry?

Ans. You get +1 mark for each correct answer and -0.25 for each wrong answer, so unattempted questions are safer than guesses you are not confident about.

Ques. Which indicator is used to titrate sodium bicarbonate with hydrochloric acid?

Ans. Methyl orange, since the equivalence point of this titration falls in the acidic range (pH 3.1-4.4) where methyl orange changes color; phenolphthalein would already be colorless well before that point.

Ques. Is a scientific calculator allowed in Odisha CPET 2025?

Ans. No. The test booklet instructions explicitly bar calculators, cell phones, and any other communication or computing device inside the exam hall.

Ques. Where can I download the Odisha CPET 2025 Chemistry question paper with solutions PDF for free?

Ans. Use the download table above on Collegedunia for the solved PDF, or check pg.samsodisha.gov.in for the original released paper.