Tripura JEE 2024 Mathematics Set P Question paper with answer key pdf is available for download. The exam was successfully organized by Tripura Board of Joint Entrance Examination (TBJEE). The question paper comprised a total of 30 questions. There is Multiple Choice Questions (MCQs) in exam.Each question will carry 4 (four) marks, i.e. total marks will be of 120 (30×4) for each subject.
Tripura JEE 2024 Mathematics Set P Question Paper with Answer Key PDFs
Tripura JEE 2024 Mathematics Question Paper with Answer Key | Check Solution |

Question 1:
Let \( \phi_1(x) = e^{\sin x}, \phi_2(x) = e^{\phi_1(x)}, \ldots, \phi_{n+1}(x) = e^{\phi_n(x)}, \forall n \geq 1.\) Then for any fixed \( n \), the expression \( \frac{d}{dx} \phi_n(x) \) is:
The value(s) of \( c \in (1, 2) \), where the conclusion of Lagrange’s M.V.T. is satisfied for the function \( f(x) = x^2 + 3x + 2 \) in \([1,2]\), is/are:
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Let the function \( f(x) \) be defined as follows:
\[ f(x) = \begin{cases} (1 + | \sin x |)^{\frac{a}{|\sin x|}}, & -\frac{\pi}{6} < x < 0
b, & x = 0
\frac{\tan 2x}{\tan 3x}, & 0 < x < \frac{\pi}{6} \end{cases} \]
Then the values of \( a \) and \( b \) are:
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If \[ \int \frac{3e^x + 5e^{-x}}{4e^x - 5e^{-x}} \, dx = Ax + B \ln |4e^{2x} - 5| + C \]
then, the values of \( A \), \( B \), and \( C \) are:
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Evaluate the integral: \[ \int_0^2 |x^2 + x - 2| \, dx \]
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The differential equation of all circles of radius \( a \) is:
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The range of the function \( f(x) = 7 - x\cdot P_{x-3} \) is:
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If \( f(x) \) and \( g(x) \) are two functions such that \( f(x) + g(x) = e^x \) and \( f(x) - g(x) = e^{-x} \), then:
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The mapping \( f: \mathbb{R} \to \mathbb{R} \) such that \( f(x) = |x - 1| \), \( x \in \mathbb{R} \) is:
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The area bounded by the curves \( y = \log_e x \) and \( y = (\log_e x)^2 \) is:
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For what value of \( n \), the curve \[ \left( \frac{x}{a} \right)^n + \left( \frac{y}{b} \right)^n = 2 touches the straight line \frac{x}{a} + \frac{y}{b} = 2 at the point (a, b)? \]
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The function \( f(x) = x^3 - 3x \) is:
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If \( A \) is the A.M. of the roots of the equation \( x^2 - 2ax + b = 0 \) and \( G \) is the G.M. of the roots of the equation \( x^2 - 2bx + a^2 = 0 \), \( a > 0 \), then:
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Out of 6 boys and 4 girls, a committee of 5 members is to be formed. In how many ways can this be done, if at least 2 girls are included?
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\( (666 \ldots up to n digits)^2 + (888 \ldots up to n digits) \) is:
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Sum of the last 40 coefficients in the expansion of \( (1 + x)^{79} \), when expanded in ascending power of \( x \) is:
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We are given that \( l, m, n \) are the \( p \)-th, \( q \)-th, and \( r \)-th terms of a G.P. In a geometric progression, the general form of the \( n \)-th term is: \[ t_n = a \cdot r^{n-1}, \]
where \( a \) is the first term and \( r \) is the common ratio.
Now, we are dealing with logarithmic expressions involving these terms. To solve the problem, we use the properties of logarithms and the fact that the terms are in G.P.
For a G.P. with terms \( l, m, n \), we have the following relations: \[ m = \sqrt{l \cdot n}, \]
since \( m \) is the geometric mean of \( l \) and \( n \).
Taking logarithms of both sides: \[ \log m = \frac{1}{2} (\log l + \log n). \]
Now, applying the properties of logarithms, we solve the equation: \[ \left| \log l \, p \, 1 \right| = 1. \]
Thus, the correct answer is \( \boxed{1} \). Quick Tip: When working with logarithms in geometric progressions, recall that the geometric mean relates to the arithmetic mean of the logarithms of the terms.
For what values of \( \lambda \) and \( \mu \), the following system of equations has a unique solution?
\[ 2x + 3y + 5z = 9 \] \[ 7x + 3y - 2z = 8 \] \[ 2x + 3y + \lambda z = \mu \]
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If \( 0 < \theta < \pi \) and \( \cos \theta + \sin \theta = \frac{1}{2} \), then the value of \( \tan \theta \) is:
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In a triangle \( ABC \), if angles \( A \), \( B \), and \( C \) are in A.P., then \( \frac{a + c}{b} \) is equal to:
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The value of \[ \tan^{-1} \left( \frac{\sin 2 - 1}{\cos 2} \right) \]
is:
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The equation of the image of the line \( 2y - x = 1 \) obtained by the reflection on the line \( 4y - 2x = 5 \) is:
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The equation of the circle of radius 3 units which touches the circles \( x^2 + y^2 - 6|x| = 0 \) is:
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The angle between the lines joining the foci of an ellipse to one particular extremity of the minor axis is \( 90^\circ \). The eccentricity of the ellipse is:
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The direction ratios of the normal to the plane passing through the points \[ (1, 2, -3), \quad (1, -2, 1) \quad and parallel to the line \quad \frac{x - 2}{2} = \frac{y + 1}{3} = \frac{z}{4} is: \]
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The area of a parallelogram whose diagonals are given by \( \vec{u} + \vec{v} \) and \( \vec{v} + \vec{w} \), where: \[ \vec{u} = 2\hat{i} - 3\hat{j} + \hat{k}, \quad \vec{v} = -\hat{i} + \hat{k}, \quad \vec{w} = 2\hat{j} - \hat{k} \]
is:
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The shortest distance between the lines \[ \frac{x + 1}{1} = \frac{y - 3}{-1} = \frac{z - 1}{-1} \quad and \quad \frac{x}{3} = \frac{y - 1}{2} = \frac{z + 1}{-1} \]
is:
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If the probability for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails is:
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If the probability density function of a random variable is given by \[ f(x) = \begin{cases} 12x^2(1 - x), & 0 \leq x \leq 1
0, & elsewhere \end{cases} \]
then the mean and variance are respectively:
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Let the two variables \( x \) and \( y \) satisfy the following conditions: \[ x + y \leq 50, \quad x + 2y \leq 80, \quad 2x + y \geq 20, \quad x, y \geq 0. \]
Then the maximum value of \( Z = 4x + 3y \) is:
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