NCERT Solutions for Class 9 Maths Chapter 11: Constructions

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The NCERT Solutions for Class 9 Maths Constructions are provided in this article. Construction deals with how to accurately draw shapes, angles, and lines. Many geometric figures can be precisely constructed using a variety of construction methods.

Class 9 Maths Chapter 11 Constructions belong to Unit 4 Geometry which has a weightage of 28 marks in the Class 9 Maths Examination. NCERT Solutions for Class 9 Maths for Chapter 11 cover the following important concepts:

Download: NCERT Solutions for Class 9 Mathematics Chapter 11 pdf

NCERT Solutions for Class 9 Mathematics Chapter 11

Important Topics in Class 9 Maths Chapter 11 Constructions

Important Topics in Class 9 Maths Chapter 11 Constructions are elaborated below:

2D and 3D Figures

Geometrically, 2D figures, otherwise known as two-dimensional objects, that can be drawn on a plane surface. 3D-shapes, howerver, are called three-dimensional objects or solids that include three dimensions.

Example: Determine the surface area of a cube, assuming that its edge length is 40 cm.

Solution: The edge of cube is given as = 40cm
As per formula, the surface area of a cube = 6a² (a = the edge length)
Hence, the surface area of the cube is = 6 (40) 2 = 9600 sq.cm

Line Segment

Line segments can be defined as points along a line which are found to be bounded by two distinct points.

Example: What are some properties of a Line Segment?

Solution: The properties of a line segment include:

A line has infinite ends which cannot be measured.
However, a line segment has a start point and an endpoint which means it can be measured.
Line segments normally include a defined length, which lead them to form the sides of any polygon.

Formula of Perimeter Shapes

Perimeter, in geometry, can be defined as the length of a closed figure's boundary. The perimeter formula for regular polygons is usually expressed using algebraic equations.

Perimeter of Different Geometric Figures:

Perimeter of a Hexagon: 6a [where a is the side of a Hexagon]
Perimeter of a Parallelogram: 2(b + h) [where b and h are the base and height respectiveley]
Perimeter of a Trapezoid: a + b + c + d [where a, b, c and d are the respective lengths of the Trapezoid]

NCERT Solutions for Class 9 Maths Chapter 11 Exercises:

The detailed solutions for all the NCERT Solutions for Constructions under different exercises are:

Also Read:

Unit Related Topics
Surface Area of a Right Circular Cylinder	Surface Area of a Right Circular Cone	Surface Area of a Sphere
Volume of a Cuboid	Volume of a Right Circular Cone	Volume of a Sphere
Tangent to a circle	Pascal’s Triangle	Equilateral Triangle
Scalene Triangle	Types Of Triangles	Properties of Triangle
Difference between Area and Volume	Quadrilateral Formula	Class 9 Maths Chapter 11 Constructions MCQs

Also Check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

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CBSE X Related Questions

1.
In the given figure, PQ is a tangent to a circle with centre \(O(-5, 3)\). If coordinates of P and Q are \((3, 1)\) and \((0, 6)\) respectively, then using distance formula, show that \(PQ \perp OQ\).
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2.
In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle. Based on above information, answer the following questions:

37(i) Find \(m\angle AOP\).
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3.
Find the missing frequencies p and q in the following frequency distribution, when sum of frequencies is 40 and mean is 19 :
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4.
Three coins are tossed together. The probability of getting exactly two tails is
- \(\frac{2}{8}\)
- \(\frac{1}{2}\)
- \(\frac{3}{8}\)
- 1
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5.
Find the H.C.F. and L.C.M. of 408 and 312.
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6.
If \( 2 \sin A = 1 \), then the value of \( \tan A + \cot A \) is :
- \( \sqrt{3} \)
- \( \frac{4}{\sqrt{3}} \)
- \( \frac{\sqrt{3}}{2} \)
- \( 1 \)
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