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NCERT Solutions Class 11 Maths Chapter 1 Sets Exercise 1.2 Solutions

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Class 11 Maths NCERT Solutions Chapter 1 Sets Exercise 1.2 covers important concepts including Empty Sets, Finite and Infinite Sets, and Equal Sets.

Download PDF NCERT Solutions for Class 11 Maths Chapter 1 Sets Exercise 1.2

Check out the solutions of Class 11 Maths NCERT Solutions Chapter 1 Sets Exercise 1.2

Read More: NCERT Solutions For Class 11 Mathematics Chapter 1 Sets

Also check other Exercise Solutions of Class 11 Maths Chapter 1 Sets

Also check:

Chapter 1 Sets Important Topics
Types of Sets	De Morgan’s Laws	Set Theory Symbols
Set Formulas	Number Theory	Group Theory
Universal Set	What is disjoint set	Equal equivalent sets

Also check:

Class 11 Mathematics Important Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
Find the local maxima and local minima of the function \[ f(x) = \frac{8}{3} x^3 - 12x^2 + 18x + 5. \]
View Solution
2.
\[ \int \frac{\tan^2 \sqrt{x}}{\sqrt{x}} \, dx \text{ is equal to:} \]
- \(\sec \sqrt{x} + C\)
- \(2\sqrt{x} \tan x - x + C\)
- \(2\left( \tan \sqrt{x} - \sqrt{x} \right) + C\)
- \(2 \tan \sqrt{x} - x + C\)
View Solution
3.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.
4.
Find the Derivative \( \frac{dy}{dx} \)
Given:\[ y = \cos(x^2) + \cos(2x) + \cos^2(x^2) + \cos(x^x) \]
View Solution
5.
In a rough sketch, mark the region bounded by \( y = 1 + |x + 1| \), \( x = -2 \), \( x = 2 \), and \( y = 0 \). Using integration, find the area of the marked region.
View Solution
6.
The domain of the function \( f(x) = \cos^{-1}(2x) \) is:
- \([-1, 1]\)
- \(\left[0, \frac{1}{2}\right]\)
- \([-2, 2]\)
- \(\left[-\frac{1}{2}, \frac{1}{2}\right]\)
View Solution

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